在 Kotlin ArrayAdapter 中需要 (Context context,int resource) 作为参数，但我想作为 ArrayList 中的字符串 h 如何做到这一点？

Question

class Word(var mDefultTranslation: String, var mArabicTranslation: String ) {
      fun Word (defultTranslation : String , arabicTranslation : String  ){
          mDefultTranslation = defultTranslation
          mArabicTranslation = arabicTranslation
      } 
}

val words = arrayListOf<Word>()
words.add( Word("one","two" ))  
val wordAdapter = WordAdapter (this, word??)

Answer 1

如果您只想要 ListView 和 ArrayAdapter，这样的事情可能会让您入门：

    val adapter = object : ArrayAdapter<Word>(this, android.R.layout.simple_list_item_2, android.R.id.text1, words) {
        override fun getView(position: Int, convertView: View?, parent: ViewGroup?): View {
            val view = super.getView(position, convertView, parent)
            val text1 = view.findViewById(android.R.id.text1) as TextView
            val text2 = view.findViewById(android.R.id.text2) as TextView
            text1.setText(words[position].mDefultTranslation)
            text2.setText(words[position].mArabicTranslation)
            return view
        }
    }
    listview.adapter = adapter

Answer 2

将第三个参数放入您的 WordAdapter。

class WordAdapter(context: Context, @LayoutRes resource: Int, private val wordList: ArrayList<Word>) : ArrayAdapter<Word>(context, resource)

在 Kotlin ArrayAdapter 中需要 (Context context,int resource) 作为参数，但我想作为 ArrayList 中的字符串 h 如何做到这一点？

in Kotlin ArrayAdapter need (Context context,int resource) as parameter but i want as a string in the ArrayList how h can do that?

android

arraylist

android-arrayadapter

kotlin