显示嵌套数据表而不重复原始数据

Question

我想显示数据库中的数据但不能重复相同的配置文件，只需在现有配置文件中添加一个位置即可。有了上面的例子就清楚了：

+-------------------+---------------+---------------+
|   PROFILE         |   LOCATION    |   STATUS      |
+-------------------+---------------+---------------+
+-------------------+---------------+---------------+
|   Admin           |   Chief       |   OK          |
+-------------------+---------------+---------------+
|   Director        |   Supervision |   OK          |
+-------------------+---------------+---------------+
|   Secretary       |   Supervision |   OK          |
+-------------------+---------------+---------------+
|                   |   Admin       |   OK          |
|                   |   Chief       |   OK          |
|   Chief-accessor  |   Director    |   OK          |
|                   |   Secretary   |   OK          |
|                   |   Supervision |   OK          |
+-------------------+---------------+---------------+

这段代码是我的数据table，只能重复，不能分组：

<rich:panel header="User location info" style="margin: 20px 0 !important;">
    <h:dataTable id="userLocationList"
        value="#{userLocation.list()}" var="row"
        styleClass="rich-table"
        headerClass="rich-table-subheader rich-table-subheadercell rich-table-thead"
        rowClasses="rich-table-row"
        columnClasses="rich-table-cell,rich-table-cell,rich-table-cell">
        <h:column>
            <f:facet name="header">
                <h:outputText value="Profile" />
            </f:facet>
            <center>
                <h:outputText value="#{row.profile}" />
            </center>
        </h:column>
        <h:column>
            <f:facet name="header">
                <h:outputText value="Location" />
            </f:facet>
            <h:outputText value="#{row.location}" />
        </h:column>
        <h:column>
            <f:facet name="header">
                <h:outputText value="Status" />
            </f:facet>
            <center>
                <h:outputText value="#{row.profile.status ? 'OK' : 'Inactive'}" />
            </center>
        </h:column>
    </h:dataTable>
</rich:panel>

像这样：

+-------------------+---------------+---------------+
|   PROFILE         |   LOCATION    |   STATUS      |
+-------------------+---------------+---------------+
+-------------------+---------------+---------------+
|   Admin           |   Chief       |   OK          |
+-------------------+---------------+---------------+
|   Director        |   Supervision |   OK          |
+-------------------+---------------+---------------+
|   Secretary       |   Supervision |   OK          |
+-------------------+---------------+---------------+
|   Chief-accessor  |   Admin       |   OK          |
+-------------------+---------------+---------------+
|   Chief-accessor  |   Chief       |   OK          |
+-------------------+---------------+---------------+
|   Chief-accessor  |   Director    |   OK          |
+-------------------+---------------+---------------+
|   Chief-accessor  |   Secretary   |   OK          |
+-------------------+---------------+---------------+
|   Chief-accessor  |   Supervision |   OK          |
+-------------------+---------------+---------------+

UserLocation 中的方法 list() 只是 table_user_location 中的一个 select：

select userLoc from UserLocation userLoc where userLoc.user.id = :userId

我已经尝试在 Whosebug 中遵循一些答案，这些答案说将一个数据 table 放入另一个数据 table，但我可以重复所有没有组配置文件的位置，例如:

+-------------------+---------------+---------------+
|   PROFILE         |   LOCATION    |   STATUS      |
+-------------------+---------------+---------------+
+-------------------+---------------+---------------+
|                   |   Chief       |               |
|                   |   Supervision |               |
|                   |   Supervision |               |
|                   |   Admin       |               |
|   Admin           |   Chief       |   OK          |
|                   |   Director    |               |
|                   |   Secretary   |               |
|                   |   Supervision |               |
+-------------------+---------------+---------------+
|                   |   Chief       |               |
|                   |   Supervision |               |
|                   |   Supervision |               |
|                   |   Admin       |               |
|   Director        |   Chief       |   OK          |
|                   |   Director    |               |
|                   |   Secretary   |               |
|                   |   Supervision |               |
+-------------------+---------------+---------------+
|                   |   Chief       |               |
|                   |   Supervision |               |
|                   |   Supervision |               |
|                   |   Admin       |               |
|   Secretary       |   Chief       |   OK          |
|                   |   Director    |               |
|                   |   Secretary   |               |
|                   |   Supervision |               |
+-------------------+---------------+---------------+
|                   |   Chief       |               |
|                   |   Supervision |               |
|                   |   Supervision |               |
|                   |   Admin       |               |
|   Chief-accessor  |   Chief       |   OK          |
|                   |   Director    |               |
|                   |   Secretary   |               |
|                   |   Supervision |               |
+-------------------+---------------+---------------+
|                   |   Chief       |               |
|                   |   Supervision |               |
|                   |   Supervision |               |
|                   |   Admin       |               |
|   Chief-accessor  |   Chief       |   OK          |
|                   |   Director    |               |
|                   |   Secretary   |               |
|                   |   Supervision |               |
+-------------------+---------------+---------------+
And so it goes...

我的疑问是我正在做的通用查询，所以 table 中的内容重复。有人知道这个操作吗？

相关问题：

Nested datatable in JSF 2.0
JSF: Empty nested dataTable
JSF, datatable in datatable

Answer 1

因为我无法按照他们的方式来做到这一点 return 同一配置文件的所有位置并且只使用一个查询，我决定做不同的事情，我想到了使用两个查询，一个用于所有没有重复配置文件 (select distinct ...) 并且根据配置文件每个位置一个。才意识到（如果我错了请纠正我）属性 h:datatable 按列而不是行呈现。因此，在某种程度上，第一个配置文件列 return 全部没有重复配置文件，但是如果位置将出现的单元格属于给定配置文件，则每个单元格中的位置都相同显示所有用户位置而没有区别.就在那时我意识到我非常专注于关注用户配置文件的位置。

运行 select distinct 配置文件并创建了一种方法来 return 在创建 table 时配置文件的位置。正如报题，一个datatable里面另一个datatable.

终于拿到我的代码了：

<rich:panel header="Informations" style="margin: 20px 0 !important;">
    <h:dataTable id="userLocationList"
        value="#{userLocation.list()}" var="row"
        styleClass="rich-table"
        headerClass="rich-table-subheader rich-table-subheadercell rich-table-thead"
        rowClasses="rich-table-row"
        columnClasses="rich-table-cell,rich-table-cell,rich-table-cell">
        <h:column>
            <f:facet name="header">
                <h:outputText value="Profile" />
            </f:facet>
            <center>
                <h:outputText value="#{row.name}" />
            </center>
        </h:column>
        <h:column>
            <f:facet name="header">
                <h:outputText value="Localizations" />
            </f:facet>
                <h:dataTable id="uLoc" var="c" 
                value="#{home.getLocByProfile(row.idProfile)}">
                    <h:column>
                        <h:outputText value="#{c}" />
                    </h:column>
                </h:dataTable>
        </h:column>
        <h:column>
            <f:facet name="header">
                <h:outputText value="Status" />
            </f:facet>
            <center>
                <h:outputText value="#{row.active ? 'OK' : 'Inactive'}" />
            </center>
        </h:column>
    </h:dataTable>
</rich:panel>

显示嵌套数据表而不重复原始数据

Show nested datatable without repeating original data

jsf

richfaces