引用由宏变量引用的转置列名称

Question

参考下面的代码，在我转置一个数据集（输出 qc2）之后，我尝试创建一个百分比列（most_recent_wk_percent_change）但是该列的结果是 12.5%，有两个新列 - &周3。和&week2。创建。预期结果是根据 week2 和 week3 列的值进行计算。我知道问题可能出在百分比计算中对两列的引用 (==> ( &week3. - &week2.)/&week2.;) ，但我无法集中精力进行更正。请告知:)

%let week1 = 7;
%let week2 = 8;
%let week3 = 9;


proc sql;
create table qc as
select t_week, prod_cat, sum(sales) as sales
from master_table
where t_week in (&week1.,&week2.,&week3.)
group by 1,2
order by 2;
quit;


proc transpose data= qc out=qc2;
format 
by prod_cat ;
id t_week;
run;

data qc2;
set qc2; 
format most_recent_wk_percent_change PERCENT7.1;
most_recent_wk_percent_change =    ( &week3. - &week2.)/&week2.;
run;

qc:
t_week|prod_cat|sales
7|cat|100
8|cat|200
9|cat|300
7|dog|150
8|dog|400
9|dog|300
7|rat|200
8|rat|600
9|rat|300

qc2: (TRANSPOSED TABLE --> note the column name of 7,8,9. (which is expected)
prod_cat|7|8|9
cat|100|200|300
dog|150|400|300
rat|200|600|300

qc2: (i wanted to get the change in % )
prod_cat|7|8|9|most_recent_wk_percent_change|&week2.|&week3.
cat|100|200|300|12.5%|.|.|    ==> 12.5% is wrong. should be 50% (300-200)/(200)
dog|150|400|300|12.5%|.|.|    ==> 12.5% is wrong. should be -25%
rat|200|600|300|12.5%|.|.|    ==> 12.5% is wrong. should be -50%

Answer 1

尝试在最后一个数据步骤中添加一个 keep 语句，这只会在输出中保留您想要的列。

data qc2 (keep= most_recent_wk_percent_change prod_cat);
set qc2; 
format most_recent_wk_percent_change PERCENT7.1;
most_recent_wk_percent_change =    ( &week3. - &tweek2.)/&week2.;
run;

Answer 2

我不知道你在做什么或为什么，但是如果你设置了 VALIDVARNAME=any 并且变量的实际名称是 7 并且你尝试在 SAS 代码中使用它，就像这样:

ratio = 7/8 ;

然后 SAS 会假定您指的是数值 7。

您需要改用名称文字。

ratio = '7'n / '8'n ;

所以你想要

most_recent_wk_percent_change = ("&week3"n-"&week2"n)/"&week2"n;

如果变量的实际名称是 _7 那么您需要这样编码。

most_recent_wk_percent_change = (_&week3.-_&week2.)/_&week2.;

引用由宏变量引用的转置列名称

refering to a transposed column name which is referenced by a macro variable

sas

sas-macro