如何延迟脚本标签直到其他脚本标签有运行

Question

我一直在尝试在网页中进行元编程，并且需要将脚本标记从运行ning 延迟到 just 另一个脚本标记 [=24] =].但是，需要先加载脚本标签，否则两者都会失败。

我正在尝试做的事情的简化版和更易读的版本：

<script defer>
    w=function(){
        <stuff that gives a parser error until modified by the next script tag>
    }
</script>
<script>
    <stuff that changes the previous script tag and any other script tags that ever will be added via the DOM
    so it doesn't give a parser error>
</script>
<button onclick='w()'></button>

除了按钮的 onclick 属性失败之外，这将非常有效，因为按钮是在第一个脚本标记运行之前加载的。提前致谢！

(编辑：I linked a pastebin to show the full version of my code, it might clear things up a bit since it seems my summed-up version wasn't very good.

Answer 1

正如@meagar 在评论中所建议的那样，如果您不介意更改 "not actually javascript" 脚本块的 type 属性，您可以这样做：

<script type='derpscript'>
  var derp;
  var w=function(){alert('hello')}; 
  derp||=5;
  console.log(derp);
</script>

<script>
function compileDerps() {
  // find all derpscript script tags
  var x = document.querySelectorAll('script[type=derpscript]');
  for(var i=0;i<x.length;i++){
    meta=x[i].text
    while(true){
      pastmeta=meta;
      console.log(exc=regex.exec(meta))
      if(exc){
        meta=meta.replace(regex,exc[1]+'='+exc[1]+'||');
      }
      if(pastmeta==meta){break;}
    }
    // make a new javascript script tag to hold the compiled derp
    var s = document.createElement('script');
    s.text = meta;
    document.body.appendChild(s);
    // delete the derpscript tag
    x[i].parentNode.removeChild(x[i]);
  }
}

    //stuff that changes the previous script tag and any other script tags that ever will be added via the DOM
    var regex=/([a-zA-Z$_][a-zA-Z$_1-9]*)(\|\|\=)/;
    var meta;
    var pastmeta='';
    var exc='';

    compileDerps();
</script>

<button onclick='w()'>THIS IS W</button>

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如何延迟脚本标签直到其他脚本标签有运行