获取对象为singleArrayObject，如何在NSMutableArray中转换？

Question

作为响应，我将 gas_cylinders 键作为单个数组对象

"gas_cylinders":["[{\"quantity\":\"2\",\"name\":\"Medium Blue\",\"price\":\"100.0\",\"total_price\":\"200.0\"},{\"quantity\":\"3\",\"name\":\"Green\",\"price\":\"100.0\",\"total_price\":\"300.0\"},{\"quantity\":\"1\",\"name\":\"Dark Green\",\"price\":\"100.0\",\"total_price\":\"100.0\"}]"]

注：- tripDictionary 包含以下数据..

(lldb) po tripDictionary 
{
    "gas_cylinder_total" = 600;
    "gas_cylinders" =     (
        "[{\"quantity\":\"2\",\"name\":\"Medium Blue\",\"price\":\"100.0\",\"total_price\":\"200.0\"},{\"quantity\":\"3\",\"name\":\"Green\",\"price\":\"100.0\",\"total_price\":\"300.0\"},{\"quantity\":\"1\",\"name\":\"Dark Green\",\"price\":\"100.0\",\"total_price\":\"100.0\"}]"
    );
}

我正在采取 gas_cylinders 如下方式..

NSArray *arr = [tripDictionary valueForKey:@"gas_cylinders"];
if (arr && arr.count > 0) {
   NSLog(@"first obj = %@",arr[0]);
}

上面NSLog的输出像..

first obj = [{"quantity":"2","name":"Medium Blue","price":"100.0","total_price":"200.0"},{"quantity":"3","name":"Green","price":"100.0","total_price":"300.0"},{"quantity":"1","name":"Dark Green","price":"100.0","total_price":"100.0"}]

如何在 NSMutableArray 中获取此对象？

Answer 1

数据不是你想的那样。 gas_cylinders 键的值是一个 JSON 字符串数组。

NSArray *cylinders = tripDictionary[@"gas_cylinders"];
NSString *firstCylinder = cylinders[0];

此时，firstCylinder是一个JSON字符串。您需要解析 JSON 字符串以获取包含在 JSON 字符串中的所需字典数组。

获取对象为singleArrayObject，如何在NSMutableArray中转换？

Getting object as singleArrayObject, how to convert in NSMutableArray?

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