为什么类型关键字以“_t”后缀结尾？
Why are type keywords ended with "_t" suffix?
我知道 size_t 有 _t 后缀，因为它的别名是 /typedef。但是我不明白为什么 char16_t、char32_t 和 wchar_t 包含 _t 后缀。
对于wchar_t:
In C++, wchar_t is a distinct fundamental type (and thus it is not defined in <cwchar> nor any other header).
In C, this is a typedef of an integral type.
对于char16_t和char32_t，在<cuchar>/uchar.c中定义：
In C, this header defines two macros: char16_t and char32_t, which map to unsigned integral types of the appropriate size (the same as uint_least16_t and uint_least32_t, respectively).
In C++, char16_t and char32_t are fundamental types (and thus this header does not define such macros in C++).
因此，在这两种情况下，即使它们是 C++ 中的基本类型，它们仍保留 _t 以与 C 兼容，它们是 typedef 或宏。
我知道 size_t 有 _t 后缀，因为它的别名是 /typedef。但是我不明白为什么 char16_t、char32_t 和 wchar_t 包含 _t 后缀。
对于wchar_t:
In C++,
wchar_tis a distinct fundamental type (and thus it is not defined in<cwchar>nor any other header).In C, this is a typedef of an integral type.
对于char16_t和char32_t，在<cuchar>/uchar.c中定义：
In C, this header defines two macros:
char16_tandchar32_t, which map to unsigned integral types of the appropriate size (the same asuint_least16_tanduint_least32_t, respectively).In C++,
char16_tandchar32_tare fundamental types (and thus this header does not define such macros in C++).
因此，在这两种情况下，即使它们是 C++ 中的基本类型，它们仍保留 _t 以与 C 兼容，它们是 typedef 或宏。