linearlayout 以编程方式导致错误 "The specified child already has a parent. You must call removeView() on the child's parent first."

Question

我有一个 xml 格式的现有片段

<LinearLayout
                    android:id="@+id/phoneLinearLyout"
                    android:layout_width="match_parent"
                    android:layout_height="wrap_content"
                    android:paddingLeft="10dp"
                    android:paddingBottom="@dimen/title_mar_gap"
                    android:paddingRight="10dp"
                    android:paddingTop="@dimen/title_mar_gap"
                    android:orientation="vertical">


                    <TextView
                        android:id="@+id/CL"
                        android:layout_width="wrap_content"
                        android:layout_height="match_parent"
                        android:gravity="center_vertical|left|center_horizontal"
                        android:text="Contact No"
                        android:textSize="@dimen/text_small" />


                    <TextView
                        android:id="@+id/CNV"
                        android:layout_width="match_parent"
                        android:layout_height="wrap_content"
                        android:gravity="center_vertical|left"
                        android:paddingBottom="5dp"
                        android:textColor="@color/black"
                        android:text=""
                        android:textSize="@dimen/text_medium" />


                    <Button
                        android:id="@+id/callButton"
                        android:textSize="15sp"
                        android:layout_width="wrap_content"
                        android:layout_height="wrap_content"
                        android:layout_marginLeft="20dp"
                        android:textColor="@color/white"
                        android:background="@color/Blue"
                        android:text="Call" />

                </LinearLayout>

现在我有 activity class 在 oncreateview 中我有以下代码 -

 View rootView = inflater.inflate(R.layout.fragment_above_fragmentView, container, false);

LinearLayuot llayout = (LinearLayout) rootView.findViewById(R.id.phoneLinearLyout);

我正在尝试使用以下代码在线性布局 Fragment_above_fragmentView 中动态显示 TextView（如第一个 XML 帖子中所述）。

for (int i=0;i<2(variable here);i++)
    {


        contactDisplay = (TextView) rootView.findViewById(R.id.contanctNumberValue);
        contactDisplay.setTypeface(typeface);


        contactDisplay.setText(dataModel.getTelNo());
        //contactDisplay.setLayoutParams(new LinearLayout.LayoutParams(LinearLayout.LayoutParams.MATCH_PARENT,LinearLayout.LayoutParams.MATCH_PARENT));
          llayout.addView(contactDisplay);
        //phoneLinearLyout.updateViewLayout(contactDisplay,);
    }

但是，面临由以下原因引起的错误：java.lang.IllegalStateException：指定的 child 已经有一个 parent。您必须先在 child 的 parent 上调用 removeView()，否则应用程序会崩溃。

Answer 1

您只需在将视图添加到布局之前删除所有视图即可：

llayout.removeAllViews(); //add this

for (int i=0;i<2(variable here);i++)
    {


        contactDisplay = (TextView) rootView.findViewById(R.id.contanctNumberValue);
        contactDisplay.setTypeface(typeface);


        contactDisplay.setText(dataModel.getTelNo());
        //contactDisplay.setLayoutParams(new LinearLayout.LayoutParams(LinearLayout.LayoutParams.MATCH_PARENT,LinearLayout.LayoutParams.MATCH_PARENT));
          llayout.addView(contactDisplay);
        //phoneLinearLyout.updateViewLayout(contactDisplay,);

    }

Answer 2

for (int i=0;i<2(此处为变量);i++) {

    contactDisplay = (TextView) rootView.findViewById(R.id.contanctNumberValue);
    contactDisplay.setTypeface(typeface);

if(contactDisplay.getParent()!=null) ((ViewGroup)tv.getParent()).removeView(contactDisplay);

    contactDisplay.setText(dataModel.getTelNo());
    //contactDisplay.setLayoutParams(new LinearLayout.LayoutParams(LinearLayout.LayoutParams.MATCH_PARENT,LinearLayout.LayoutParams.MATCH_PARENT));
      llayout.addView(contactDisplay);
    //phoneLinearLyout.updateViewLayout(contactDisplay,);

}

Answer 3

您应该创建一个新的 TextView 并添加到布局中。

for (int i=0;i<2(variable here);i++)
{
   TextView contactDisplay = new TextView(getApplicationContext());
   contactDisplay.setTypeface(typeface);
   contactDisplay.setText(dataModel.getTelNo());
   llayout.addView(contactDisplay);
}

Answer 4

每次都创建文本视图，而不是指向已使用的同一个文本视图。

linearlayout 以编程方式导致错误 "The specified child already has a parent. You must call removeView() on the child's parent first."

linearlayout programmatically causes error "The specified child already has a parent. You must call removeView() on the child's parent first."

android

dynamic

textview