Googletest expect_call 未记录通话

Question

测试用例应断言调用了资源的方法tagcache()，以确保更新资源的标记缓存。我知道调用了该方法，但测试失败，因为：

Expected: to be called at least once
Actual: never called - unsatisfied and active

但是为什么呢？

void TagModel::tagResource(Tag *tag, Resource *r)
{
    if ( tag ){ tag->addToResource(r); }
}

void Tag::addToResource(Resource *r)
{
    if ( !r ){ return; }
    addToResource(r->id());
    r->tagcache()->add(this->id(),this->name());
}

class ResourceMock : public Resource
{
public:
    MOCK_CONST_METHOD0(tagcache,TagCache *(void));
};

TEST(tagmodel,tag_resource){
    TagModel m;
    Tag *t = m.createTag("tag");
    ResourceMock mockres;
    EXPECT_CALL(mockres,tagcache()).Times(AtLeast(1));
    m.tagResource(t,&mockres);
}

更新：资源定义

class Resource
{
    mutable TagCache *tagcache_ = nullptr;
public:
    virtual ~Resource(){
        if ( tagcache_){ delete tagcache_; }
    }    
    TagCache *tagcache() const{
        if ( !tagcache_){
            tagcache_ = new TagCache;
        }
        return tagcache_;
    }
};

Answer 1

Resource::tagcache() 不是 virtual，所以

ResourceMock mockres;
Resource *r = &mockres;
// [..]
r->tagcache()->add(this->id(),this->name());

会从基础 class 中调用 tagcache，而不是从 mock 中调用 tagcache。

Answer 2

通过这些更改，它正在运行。但是测试本身并不好；太多的依赖。我也应该模拟 TagCache，并可能将 TagModel 移动到固定装置。

TEST(tagmodel,tag_resource){
    TagModel m;
    Tag *t = m.createTag("tag");
    ResourceMock mockres;
    TagCache cache;
    EXPECT_CALL(mockres,tagCache())
            .Times(AtLeast(1))
            .WillOnce(Return(&cache)); // must not return a nullptr default value, because the 'tagResource' will call the cache.
    m.tagResource(t,&mockres);
}

mutable QSharedPointer<TagCache> tagcache_;
// Would like to add 'final' keyword, but the mock must be able to override this method.
virtual TagCache *tagCache() const{
    if ( tagcache_.isNull() ){ tagcache_ = QSharedPointer<TagCache>(new TagCache); }
    return tagcache_.data();
}

Googletest expect_call 未记录通话

Googletest expect_call not logging call

c++

googletest