Javafx:TreeView 的域对象
Javafx : Domain objects to TreeView
我的应用程序中有如下三个域对象:
public class Workflow {
private String name;
private List<Sheet> sheets;
}
public class Sheet {
private String name;
private List<Task> tasks;
}
public class Task {
private String name;
}
这三个都依赖于工作流 -> Sheet -> 任务。我的目标是构建 TreeView,使其如下所示:
-Workflow
|
- workflow name
-Sheets
|
- sheet name
- Tasks
|
- task name
到目前为止,我已经构建了一个示例,它构建的内容比我预期的要少,但它不是通用的,而且根本 'automated'。
public class TreeViewSample extends Application {
public static void main(String[] args) {
launch(args);
}
@Override
public void start(Stage primaryStage) {
primaryStage.setTitle("Tree View Sample");
Workflow w = setup();
TreeItem<String> rootItem = new TreeItem<String> ("Workflow");
rootItem.setExpanded(true);
TreeItem<String> item = new TreeItem<String> (w.getName());
rootItem.getChildren().add(item);
(...)
TreeView<String> tree = new TreeView<String> (rootItem);
StackPane root = new StackPane();
root.getChildren().add(tree);
primaryStage.setScene(new Scene(root, 300, 250));
primaryStage.show();
}
private Workflow setup(){
Workflow wflow = new Workflow();
wflow.setName("wflow name");
wflow.setSheets(Arrays.asList(new Sheet("sheet name", Arrays.asList(new Task("task name")))));
return wflow;
}
有人可以建议我如何递归地转到我的域对象并构建 TreeView 吗?
您必须为所有模型(工作流、Sheet、任务)创建一个通用的 Model
,因为它们都有一个字符串 属性,创建起来非常简单一。假设我们有以下模型:
public class Model {
private String name;
public Model(String name) {
this.name = name;
}
public String getName() {
return name;
}
@Override
public String toString() {
return getName();
}
}
class Workflow {
private String name;
private List<Sheet> sheets = new ArrayList<>();
public Workflow(String name) {
this.name = name;
}
public String getName() {
return name;
}
public List<Sheet> getSheets() {
return sheets;
}
}
class Sheet {
private String name;
private List<Task> tasks = new ArrayList<>();
public Sheet(String name) {
this.name = name;
}
public String getName() {
return name;
}
public List<Task> getTasks() {
return tasks;
}
}
class Task {
private String name;
public Task(String name) {
this.name = name;
}
public String getName() {
return name;
}
}
我把你所有的模型放在一起,以便更好地查看它们。
我看到你没有在你的应用程序中使用任何 .fxml
文件,我的是 .fxml
我建议你至少分开 Main
class 来自 Controller
class,如:
public class Main extends Application{
@Override
public void start(Stage primaryStage) throws Exception {
FXMLLoader loader = new FXMLLoader(getClass().getResource("View.fxml"));
AnchorPane pane = loader.load();
primaryStage.setScene(new Scene(pane,800,600));
primaryStage.show();
}
public static void main(String[] args) {
launch(args);
}
}
然后控制器class:
public class Controller implements Initializable {
@FXML
private TreeView<Model> treeView;
@Override
public void initialize(URL location, ResourceBundle resources) {
Workflow workflow = createWorkflow(); // This just sets up the models that you are using.
// You have to create a root in your case the "Workflow"
TreeItem<Model> root = new TreeItem<>(new Model(workflow.getName()));
// The foreach sheet you create a branch
workflow.getSheets().forEach(sheet -> {
TreeItem<Model> sheetBranch = new TreeItem<>(new Model(sheet.getName()));
// Then you have to add each branch to the root
root.getChildren().add(sheetBranch);
// Then foreach sheet you create a task item
sheet.getTasks().forEach(task -> {
TreeItem<Model> taskItem = new TreeItem<>(new Model(task.getName()));
// Then you have to add each task to its sheet parent
sheetBranch.getChildren().add(taskItem);
});
});
// Finally, you set the root for the TreeView. Of course this can be done right after instantiating the root.
treeView.setRoot(root);
}
// ------------------- Setup the model -----------------------
private Workflow createWorkflow() {
Workflow workflow = new Workflow("Workflow");
workflow.getSheets().addAll(createSheets());
return workflow;
}
private List<Sheet> createSheets() {
List<Sheet> sheets = new ArrayList<>();
IntStream.range(1, 10).forEach(value -> sheets.add(createSheet()));
return sheets;
}
private Sheet createSheet() {
Sheet sheet = new Sheet("Sheet" + new Random().nextInt(100)); // Random added to have different names
sheet.getTasks().addAll(createTasks());
return sheet;
}
private List<Task> createTasks() {
List<Task> tasks = new ArrayList<>();
IntStream.range(1, 5).forEach(value -> tasks.add(createTask()));
return tasks;
}
private Task createTask() {
return new Task("Task" + new Random().nextInt(100)); // Random added to have different names
}
}
以备不时之需,这里是 .fxml
文件:
<?xml version="1.0" encoding="UTF-8"?>
<?import javafx.scene.control.TreeView?>
<?import javafx.scene.layout.AnchorPane?>
<AnchorPane xmlns="http://javafx.com/javafx"
xmlns:fx="http://javafx.com/fxml"
fx:controller="Whosebug.tree.Controller">
<TreeView fx:id="treeView"/>
</AnchorPane>
如果您不知道 TreeView
的深度,您可以使用递归创建所有的分支或叶子。在这种情况下,使用两个 foreach 而不是创建构建树结构的递归方法要简单得多。
缺少提供子项列表的通用超类型,您需要对每个包含子对象列表的对象使用 1 个不同的 method/1 嵌套循环,即
private TreeItem<String> createWorkFlow(Workflow workflow) {
TreeItem<String> item = new TreeItem<>(workflow.getName());
for (Sheet sheet : workflow.getSheets()) {
item.getChildren().add(createSheet(sheet));
}
return item;
}
private TreeItem<String> createSheet(Sheet sheet) {
TreeItem<String> item = new TreeItem<>(sheet.getName());
for (Task task : sheet.getTasks()) {
item.getChildren().add(new TreeItem<>(task.getName());
}
return item;
}
或
private TreeItem<String> createWorkFlow(Workflow workflow) {
TreeItem<String> workflowItem = new TreeItem<>(workflow.getName());
for (Sheet sheet : workflow.getSheets()) {
TreeItem<String> sheetItem = new TreeItem<>(sheet.getName());
for (Task task : sheet.getTasks()) {
sheetItem.getChildren().add(new TreeItem<>(task.getName()));
}
workflowItem.getChildren().add(sheetItem);
}
return item;
}
除非你想使用反射。
为避免这种情况,您可以使用您的类型实现一个接口:
public interface Item<T extends Item<?>> {
String getName();
default List<T> getChildren() {
return null; // default for terminal object
}
}
这将使您能够将 TreeItem
的创建简化为
public static <T extends Item<?>> TreeItem<String> createItem(Item<T> item) {
TreeItem<String> treeItem = new TreeItem<>(item.getName());
List<T> children = item.getChildren();
if (children != null) {
for (Item<?> ci : children) {
treeItem.getChildren().add(createItem(ci));
}
}
return treeItem;
}
我的应用程序中有如下三个域对象:
public class Workflow {
private String name;
private List<Sheet> sheets;
}
public class Sheet {
private String name;
private List<Task> tasks;
}
public class Task {
private String name;
}
这三个都依赖于工作流 -> Sheet -> 任务。我的目标是构建 TreeView,使其如下所示:
-Workflow
|
- workflow name
-Sheets
|
- sheet name
- Tasks
|
- task name
到目前为止,我已经构建了一个示例,它构建的内容比我预期的要少,但它不是通用的,而且根本 'automated'。
public class TreeViewSample extends Application {
public static void main(String[] args) {
launch(args);
}
@Override
public void start(Stage primaryStage) {
primaryStage.setTitle("Tree View Sample");
Workflow w = setup();
TreeItem<String> rootItem = new TreeItem<String> ("Workflow");
rootItem.setExpanded(true);
TreeItem<String> item = new TreeItem<String> (w.getName());
rootItem.getChildren().add(item);
(...)
TreeView<String> tree = new TreeView<String> (rootItem);
StackPane root = new StackPane();
root.getChildren().add(tree);
primaryStage.setScene(new Scene(root, 300, 250));
primaryStage.show();
}
private Workflow setup(){
Workflow wflow = new Workflow();
wflow.setName("wflow name");
wflow.setSheets(Arrays.asList(new Sheet("sheet name", Arrays.asList(new Task("task name")))));
return wflow;
}
有人可以建议我如何递归地转到我的域对象并构建 TreeView 吗?
您必须为所有模型(工作流、Sheet、任务)创建一个通用的 Model
,因为它们都有一个字符串 属性,创建起来非常简单一。假设我们有以下模型:
public class Model {
private String name;
public Model(String name) {
this.name = name;
}
public String getName() {
return name;
}
@Override
public String toString() {
return getName();
}
}
class Workflow {
private String name;
private List<Sheet> sheets = new ArrayList<>();
public Workflow(String name) {
this.name = name;
}
public String getName() {
return name;
}
public List<Sheet> getSheets() {
return sheets;
}
}
class Sheet {
private String name;
private List<Task> tasks = new ArrayList<>();
public Sheet(String name) {
this.name = name;
}
public String getName() {
return name;
}
public List<Task> getTasks() {
return tasks;
}
}
class Task {
private String name;
public Task(String name) {
this.name = name;
}
public String getName() {
return name;
}
}
我把你所有的模型放在一起,以便更好地查看它们。
我看到你没有在你的应用程序中使用任何 .fxml
文件,我的是 .fxml
我建议你至少分开 Main
class 来自 Controller
class,如:
public class Main extends Application{
@Override
public void start(Stage primaryStage) throws Exception {
FXMLLoader loader = new FXMLLoader(getClass().getResource("View.fxml"));
AnchorPane pane = loader.load();
primaryStage.setScene(new Scene(pane,800,600));
primaryStage.show();
}
public static void main(String[] args) {
launch(args);
}
}
然后控制器class:
public class Controller implements Initializable {
@FXML
private TreeView<Model> treeView;
@Override
public void initialize(URL location, ResourceBundle resources) {
Workflow workflow = createWorkflow(); // This just sets up the models that you are using.
// You have to create a root in your case the "Workflow"
TreeItem<Model> root = new TreeItem<>(new Model(workflow.getName()));
// The foreach sheet you create a branch
workflow.getSheets().forEach(sheet -> {
TreeItem<Model> sheetBranch = new TreeItem<>(new Model(sheet.getName()));
// Then you have to add each branch to the root
root.getChildren().add(sheetBranch);
// Then foreach sheet you create a task item
sheet.getTasks().forEach(task -> {
TreeItem<Model> taskItem = new TreeItem<>(new Model(task.getName()));
// Then you have to add each task to its sheet parent
sheetBranch.getChildren().add(taskItem);
});
});
// Finally, you set the root for the TreeView. Of course this can be done right after instantiating the root.
treeView.setRoot(root);
}
// ------------------- Setup the model -----------------------
private Workflow createWorkflow() {
Workflow workflow = new Workflow("Workflow");
workflow.getSheets().addAll(createSheets());
return workflow;
}
private List<Sheet> createSheets() {
List<Sheet> sheets = new ArrayList<>();
IntStream.range(1, 10).forEach(value -> sheets.add(createSheet()));
return sheets;
}
private Sheet createSheet() {
Sheet sheet = new Sheet("Sheet" + new Random().nextInt(100)); // Random added to have different names
sheet.getTasks().addAll(createTasks());
return sheet;
}
private List<Task> createTasks() {
List<Task> tasks = new ArrayList<>();
IntStream.range(1, 5).forEach(value -> tasks.add(createTask()));
return tasks;
}
private Task createTask() {
return new Task("Task" + new Random().nextInt(100)); // Random added to have different names
}
}
以备不时之需,这里是 .fxml
文件:
<?xml version="1.0" encoding="UTF-8"?>
<?import javafx.scene.control.TreeView?>
<?import javafx.scene.layout.AnchorPane?>
<AnchorPane xmlns="http://javafx.com/javafx"
xmlns:fx="http://javafx.com/fxml"
fx:controller="Whosebug.tree.Controller">
<TreeView fx:id="treeView"/>
</AnchorPane>
如果您不知道 TreeView
的深度,您可以使用递归创建所有的分支或叶子。在这种情况下,使用两个 foreach 而不是创建构建树结构的递归方法要简单得多。
缺少提供子项列表的通用超类型,您需要对每个包含子对象列表的对象使用 1 个不同的 method/1 嵌套循环,即
private TreeItem<String> createWorkFlow(Workflow workflow) {
TreeItem<String> item = new TreeItem<>(workflow.getName());
for (Sheet sheet : workflow.getSheets()) {
item.getChildren().add(createSheet(sheet));
}
return item;
}
private TreeItem<String> createSheet(Sheet sheet) {
TreeItem<String> item = new TreeItem<>(sheet.getName());
for (Task task : sheet.getTasks()) {
item.getChildren().add(new TreeItem<>(task.getName());
}
return item;
}
或
private TreeItem<String> createWorkFlow(Workflow workflow) {
TreeItem<String> workflowItem = new TreeItem<>(workflow.getName());
for (Sheet sheet : workflow.getSheets()) {
TreeItem<String> sheetItem = new TreeItem<>(sheet.getName());
for (Task task : sheet.getTasks()) {
sheetItem.getChildren().add(new TreeItem<>(task.getName()));
}
workflowItem.getChildren().add(sheetItem);
}
return item;
}
除非你想使用反射。
为避免这种情况,您可以使用您的类型实现一个接口:
public interface Item<T extends Item<?>> {
String getName();
default List<T> getChildren() {
return null; // default for terminal object
}
}
这将使您能够将 TreeItem
的创建简化为
public static <T extends Item<?>> TreeItem<String> createItem(Item<T> item) {
TreeItem<String> treeItem = new TreeItem<>(item.getName());
List<T> children = item.getChildren();
if (children != null) {
for (Item<?> ci : children) {
treeItem.getChildren().add(createItem(ci));
}
}
return treeItem;
}