如何通过调整权重优化皮尔逊相关系数？

Question

我想调整权重 w 以优化 Pearson 相关系数的 r 平方。

import numpy as np
from scipy import stats

x1_raw=np.array([277, 115, 196])
x2_raw=np.array([263, 118, 191])
x3_raw=np.array([270, 114, 191])

w=np.array([w1, w2, w3])

x1=np.prod([w,x1_raw], axis=0).sum()
x2=np.prod([w,x2_raw], axis=0).sum()
x3=np.prod([w,x3_raw], axis=0).sum()

x=np.array([x1, x2, x3])

y=np.array([71.86, 71.14, 70.76])

slope, intercept, r_value, p_value, std_err = stats.linregress(x,y)
r_squared = r_value**2

那么调整[w1, w2, w3]最大化r_squared的代码是什么？

谢谢@mathew gunther

我从print(res)得到的结果是：

final_simplex: (array([[ 0.41998763,  2.66314965,  3.34462572],
  [ 0.4199877 ,  2.66314968,  3.34462654],
  [ 0.41998749,  2.66314983,  3.34462649],
  [ 0.41998765,  2.66314917,  3.34462607]]), array([-1., -1., -1., -1.]))
      fun: -0.99999999999999822
  message: 'Optimization terminated successfully.'
     nfev: 130
      nit: 65
   status: 0
  success: True
        x: array([ 0.41998763,  2.66314965,  3.34462572])

我可以理解为x: array([ 0.41998763, 2.66314965, 3.34462572])就是w； nfev 是函数求值的次数； nit 是迭代次数

但是下面的参数是什么？

array([[ 0.41998763,  2.66314965,  3.34462572],
  [ 0.4199877 ,  2.66314968,  3.34462654],
  [ 0.41998749,  2.66314983,  3.34462649],
  [ 0.41998765,  2.66314917,  3.34462607]])

array([-1., -1., -1., -1.]))
status: 0

Answer 1

我敢打赌有一些封闭形式的解决方案，但如果黑客代码足够，请参见下文

（此解决方案基于 scipy.optimize 包 https://docs.scipy.org/doc/scipy/reference/tutorial/optimize.html)

(返回-1次最小化变成最大化r_squared)

import numpy as np
from scipy import stats
from scipy import optimize
import IPython

def get_linregress(*args):

    #IPython.embed()
    w1,w2,w3 = args[0]

    x1_raw=np.array([277, 115, 196])
    x2_raw=np.array([263, 118, 191])
    x3_raw=np.array([270, 114, 191])

    w=np.array([w1, w2, w3])
    #w=np.array([1, 1, 1])

    x1=np.prod([w,x1_raw], axis=0).sum()
    x2=np.prod([w,x2_raw], axis=0).sum()
    x3=np.prod([w,x3_raw], axis=0).sum()

    x=np.array([x1, x2, x3])

    y=np.array([71.86, 71.14, 70.76])

    slope, intercept, r_value, p_value, std_err = stats.linregress(x,y) r_squared = r_value**2

    return -1*r_squared

res = optimize.minimize(get_linregress, [1,2,3], method='Nelder-Mead', tol=1e-6)

res.x

如何通过调整权重优化皮尔逊相关系数？

How to optimise the Pearson's correlation coefficient by adjusting the weights?

python

numpy

linear-regression

python-3.x

pearson-correlation