如何通过重复矩阵​​行来扩大矩阵？

Question

初始矩阵为A = [ [1 2 3; 4 5 6; 7 8 9]。每行将被复制 3 次，使得输出矩阵为

B = [1 2 3;1 2 3;1 2 3;4 5 6; 4 5 6; 4 5 6; 7 8 9; 7 8 9; 7 8 9]
B = replicate(permute(A,[3 2 1]),3,1)

Answer 1

你是这个意思吗？

kron(A,ones(3,1))

答案=

 1     2     3
 1     2     3
 1     2     3
 4     5     6
 4     5     6
 4     5     6
 7     8     9
 7     8     9
 7     8     9

Answer 2

从R2015a开始，有一个专门的函数：repelem.

A = [1 2 3; 4 5 6; 7 8 9]
B = repelem(A,3,1)

---

B =

     1     2     3
     1     2     3
     1     2     3
     4     5     6
     4     5     6
     4     5     6
     7     8     9
     7     8     9
     7     8     9

Answer 3

或者只是索引：

A = [1 2 3; 4 5 6; 7 8 9]; % original matrix
m = 3; % row repetition factor
n = 1; % column repetition factor
B = A(ceil(1/m:1/m:size(A,1)), ceil(1/n:1/n:size(A,2)));