Python: finally 需要一个 try-except 子句吗？

Question

假设如下代码。

try:
    some_code_1
except: # will it be called twice, if an error occures in finally?
    some_code_2
finally:
    some_code_3

假设在some_code_3中发生异常。我是否需要围绕 some_code_3（见下文）的额外 try-except 子句，或者是否会再次调用带有 some_code_2 的异常，这原则上会导致无限循环？

这个省事吗？

try:
    some_code_1
except: # will it be called twice, if an error occures in finally?
    some_code_2
finally:
    try:
        some_code_3
    except:
        pass

Answer 1

python 不会在执行流程中返回，而是逐条返回。

当它到达 finally 时，如果在那里抛出错误，它还需要另一个句柄

Answer 2

试一试：

try:
    print(abc) #Will raise NameError
except: 
    print("In exception")
finally:
    print(xyz) #Will raise NameError

Output: 
In exception
Traceback (most recent call last):
  File "Z:/test/test.py", line 7, in <module>
    print(xyz)
NameError: name 'xyz' is not defined

所以不，它不会以无限循环结束

Answer 3

示例代码中的 finally 不会捕获来自 some_code_3 的异常。

是否需要捕获来自some_code_3的异常取决于你的设计。

Python: finally 需要一个 try-except 子句吗？

Python: Does finally needs a try-except clause?

python

finally

except