Try-Catch 选项在 Java 中没有 运行

Try-Catch option does not run in Java

我正在尝试在 Java 中编写一个十进制和二进制转换器。我正在尝试使用 try & catch 选项进行错误处理。例如,如果任何一个输入 "a" 作为二进制数,它将打印 "Wrong Input"。我为此功能使用了解析和尝试捕获。但它不起作用。我试图找出问题所在,但找不到。谁能帮我写这段代码?当我为二进制到十进制的转换写入“1”时,它会转到代码的末尾。 完整代码在这里:

package binary.with.decimal;

import java.util.Scanner;

public class RiaJava {

    public static void main(String[] args) {

        Scanner scan = new Scanner(System.in);

        int binaryp = 0;
        int n;
        int base = 2;
        int result = 0;
        int multiplier = 1;

        System.out.println("1.Binary to Decimal \n 2.Decimal to Binary");
        System.out.println("Enter Your Option Number:");
        n = scan.nextInt();

        switch (n) {
        case 1:
            System.out.println("Input Binary Number:");

            String binary = scan.nextLine();
            scan.close();
            try {
                binaryp = Integer.parseInt(binary);
            }

            catch (NumberFormatException e) {
                System.out.println("Wrong Input!!!");
            }

            while (binaryp > 0) {
                int residue = binaryp % base;
                binaryp = binaryp / base;
                result = result + residue * multiplier;
                multiplier = multiplier * 10;
            }
            System.out.println("Decimal....." + result);

            break;
        case 2:
            System.out.println("Input Decimal Number:");
            int decimal = scan.nextInt();
            scan.close();

            while (decimal > 0) {
                int residue = decimal % base;
                decimal = decimal / base;
                result = result + residue * multiplier;
                multiplier = multiplier * 10;
            }
            System.out.println("Binary....." + result);
            break;
        default:
            System.out.println("you have selected wrong option number");
            break;
        }
    }
}

scan.nextLine() 应该是 scan.next()

nextLine() 不等待用户输入,而是读取剩余缓冲区直到下一行结束。