从 HTML 中检索内容，这是一个 NSString

Question

这是我的 NSString :

 NSString timeString = @"<h5 style="direction:ltr"><span data-version-created-date="20180326T120530.000+0000" class="releasedDate">26-Mar-2018 12:05:30</span></h5>";

我只想检索 span 标签中的“26-Mar-2018 12:05:30”。我如何在 Objective C 中做到这一点？

请注意：给定的 HTML 是 NSString 格式。

Answer 1

试试这个

- (NSString *)stringByStrippingHTML : (NSString*) s {
    NSRange r;
    while ((r = [s rangeOfString:@"<[^>]+>" options:NSRegularExpressionSearch]).location != NSNotFound)
    s = [s stringByReplacingCharactersInRange:r withString:@""];
    return s;
}

Answer 2

这将通过删除方括号 (<>) 的表达式来实现。已将斜杠 () 添加到 timeString 以使其成为正确的 NSString*。剥离重复四次，bt应该有条件循环。

NSString * timeString = @"<h5 style=\"direction:ltr\"><span data-version-created-date=\"20180326T120530.000+0000\" class=\"releasedDate\">26-Mar-2018 12:05:30</span></h5>";

NSRange openRange = [timeString rangeOfString:@"<"];
NSRange closeRange = [timeString rangeOfString:@">"];
NSRange enclosedRange = NSMakeRange(openRange.location, closeRange.location-openRange.location+1);
timeString = [timeString stringByReplacingCharactersInRange:enclosedRange withString:@""];

openRange = [timeString rangeOfString:@"<"];
closeRange = [timeString rangeOfString:@">"];
enclosedRange = NSMakeRange(openRange.location, closeRange.location-openRange.location+1);
timeString = [timeString stringByReplacingCharactersInRange:enclosedRange withString:@""];

openRange = [timeString rangeOfString:@"<"];
closeRange = [timeString rangeOfString:@">"];
enclosedRange = NSMakeRange(openRange.location, closeRange.location-openRange.location+1);
timeString = [timeString stringByReplacingCharactersInRange:enclosedRange withString:@""];

openRange = [timeString rangeOfString:@"<"];
closeRange = [timeString rangeOfString:@">"];
enclosedRange = NSMakeRange(openRange.location, closeRange.location-openRange.location+1);
timeString = [timeString stringByReplacingCharactersInRange:enclosedRange withString:@""];

NSLog(@"timeString = %@", timeString);

Answer 3

这对我有用

 NSString *timeString = @"<h5 style=\"direction:ltr\"><span data-version-created-date=\"20180326T120530.000+0000\" class=\"releasedDate\">26-Mar-2018 12:05:30</span></h5>";
  NSRegularExpression *regex = [NSRegularExpression
                              regularExpressionWithPattern:@">\d.+\d<"
                              options:NSRegularExpressionCaseInsensitive
                              error:NULL];
[regex enumerateMatchesInString:timeString options:0 range:NSMakeRange(0, [timeString length]) usingBlock:^(NSTextCheckingResult *match, NSMatchingFlags flags, BOOL *stop){
    // your code to handle matches here

    NSString *subString = [timeString substringWithRange:match.range];

    NSLog(@"%@",[subString substringWithRange:NSMakeRange(1, subString.length - 2)]);

}];

Answer 4

如果您想确保获得 span 标签之间的日期，最好比剥离所有 HTML 标签并假设唯一剩下的就是日期更明确，或者假设整个 HTML 文本中只有一个 span 标签。它现在可能有效，但如果 HTML 发生变化，将来可能会中断。

NSString * timeString = @"<h5 style=\"direction:ltr\"><span data-version-created-date=\"20180326T120530.000+0000\" class=\"releasedDate\">26-Mar-2018 12:05:30</span><span class=\"someOtherClass\">garbageData</span></h5>";
NSRegularExpression *regex = [NSRegularExpression
                              regularExpressionWithPattern:@"<span.*class=\"releasedDate\"[^>]*>(.*)</span.*>"
                              options:NSRegularExpressionCaseInsensitive
                              error:nil];
NSTextCheckingResult *textCheckingResult = [regex firstMatchInString:timeString options:0 range:NSMakeRange(0, timeString.length)];

NSString *releaseDateString = [timeString substringWithRange:[textCheckingResult rangeAtIndex:1]];
if( ! [releaseDateString isEqualToString:@""] )
{
    NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
    [dateFormatter setDateFormat:@"dd-MMM-yyyy' 'HH:mm:ss"];
     NSDate *releaseDate = [dateFormatter dateFromString:releaseDateString];

    NSLog( @"%@ - %@", releaseDateString, releaseDate );
}

请注意，即使 HTML 文本中有其他跨度，这仍然有效。它专门拉出带有 class "releasedDate".

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