无法将文本文件中的每个单词存储在C ++中的双向链表中

Question

我想从包含以下数据的文本文件中读取：

"This is a small file containing words ."

我想将它的每个单词存储在每个节点中。

node1：这个，node2：是，node3：a，node4：小...等等

现在，在下面的运行代码中，它只是将最后一个字符“ .” 存储了两次。

任何人都可以指出我在这里犯了什么错误。

我是菜鸟，所以只是从基础开始。

struct node
{
    struct node *next;
    string num;
    struct node *prev;
};

struct node *create_ll(struct node *start)
{
    string word;

    ifstream file;

    file.open("/Volumes/MAC Extended/Softwares/Xcode/DSA project/DSA project/file.txt",
              ios::in);
    if (!file)
    {
        cout << "File Does not Exist";
        return 0;
    }
    struct node *new_node, *ptr;
    while (file >> word)
    {
        if (start == NULL)
        {
            new_node = new node;
            new_node->prev = NULL;
            new_node->num = word;
            new_node->next = NULL;
            start = new_node;
        }
        else
        {

            ptr = start;
            new_node = new node;
            new_node->num = word;
            while (ptr->next != NULL)
                ptr = ptr->next;
            ptr->next = new_node;
            new_node->prev = ptr;
            new_node->next = NULL;
        }
    }
    return start;
}

Answer 1

//
//  main.cpp
//  DSA project
//
//  Created by Vivank Sharma on 26/03/18.
//  Copyright © 2018 Vivank Sharma. All rights reserved.
//

#include<iostream>
#include<fstream>
#include<cstring>
using namespace std;
struct node
{
    struct node *next;
    string num;
    struct node *prev;
};
struct node *start = NULL;
struct node *create_ll(struct node *);
struct node *display(struct node *);
int main()
{
    int option;

    do
    {
        cout<<"\n\n *****MAIN MENU *****";
        cout<<"\n 1: Create a list";
        cout<<"\n 2: Display the list";
        cout<<"\n\n Enter your option : ";
        cin>>option;
        switch(option)
        {
            case 1:
            { start = create_ll(start);
                cout<<"\n DOUBLY LINKED LIST CREATED";

            }
                break;
            case 2:
            {
                start = display(start);
            }
                break;
        }
    }while(option!=3);
}
struct node *create_ll(struct node *start)
{
    string word;

    ifstream file;

    file.open("/Volumes/MAC Extended/Softwares/Xcode/DSA project/DSA project/file.txt",ios::in);
    if (!file) {
        cout << "File Does not Exist";
        return 0;
    }
    struct node *new_node, *ptr;
    while(file>>word)
    {
        if(start == NULL)
        {
            new_node = new node;
            new_node -> prev = NULL;
            new_node -> num = word;
            new_node -> next = NULL;
            start = new_node;
        }
        else {

            ptr=start;
            new_node = new node;
            new_node->num=word;
            while(ptr->next!=NULL)
                ptr = ptr->next;
            ptr->next = new_node;
            new_node->prev=ptr;
            new_node->next=NULL;
        }
    }
    return start;
}
struct node *display(struct node *start)
{
    struct node *ptr;
    ptr=start;
    while(ptr!=NULL)
    {
        cout<<ptr -> num<<endl;
        ptr = ptr -> next;
    }
    return start;
}

这样就可以了。发现错误。

Answer 2

#include<iostream>
#include<fstream>
#include<cstring>
using namespace std;
struct node
{
struct node *next;
string num;
struct node *prev;
};
struct node *start = NULL;
struct node *create_ll(struct node *);
struct node *display(struct node *);
int main()
{
int option;

do
{
    cout<<"\n\n *****MAIN MENU *****";
    cout<<"\n 1: Create a list";
    cout<<"\n 2: Display the list";
    cout<<"\n\n Enter your option : ";
    cin>>option;
    switch(option)
    {
        case 1:
        { start = create_ll(start);
            cout<<"\n DOUBLY LINKED LIST CREATED";

        }
            break;
        case 2:
        {
            start = display(start);
        }
            break;
    }
}while(option!=3);
}
struct node *create_ll(struct node *start)
{
string word;

ifstream file;

file.open("/Volumes/MAC Extended/Softwares/Xcode/DSA project/DSA 
project/file.txt",ios::in);
if (!file) {
    cout << "File Does not Exist";
    return 0;
}
struct node *new_node, *ptr;
while(file>>word)
{
    if(start == NULL)
    {
        new_node = new node;
        new_node -> prev = NULL;
        new_node -> num = word;
        new_node -> next = NULL;
        start = new_node;
    }
    else {

        ptr=start;
        new_node = new node;
        new_node->num=word;
        while(ptr->next!=NULL)
            ptr = ptr->next;
        ptr->next = new_node;
        new_node->prev=ptr;
        new_node->next=NULL;
    }
}
return start;
}
struct node *display(struct node *start)
{
struct node *ptr;
ptr=start;
while(ptr!=NULL)
{
    cout<<ptr -> num<<endl;
    ptr = ptr -> next;
}
return start;
}

try this code

无法将文本文件中的每个单词存储在C ++中的双向链表中

Unable to store each word from text file in doubly linked list in c++

c++

file

data-structures

doubly-linked-list