多级用户组 PHP Mysql 无限循环
Multi Level user groups PHP Mysql while infinite loop
我想创建一个多级用户脚本,我有以下代码可以工作,但只显示一个用户线程。我的目标是显示每个人的所有用户,每个组中至少有 3 个子用户。
我有这个:
Maximo Eladio
- Jose Anibal
- Juan De Dios
- Pedro David
- Luis Alberto
- Henry
- Eury Alexander
但我想要这个:
(0)Maximo Eladio
- (1)Jose Anibal
- (2)Juan De Dios
- (3)Pedro David
- (4)Luis Alberto
- (5)Henry
- (6)Eury Alexander
(1)Jose Anibal
- (2)Juan De Dios
- (3)Pedro David
- (4)Luis Alberto
- (5)Henry
- (6)Eury Alexander
(2)Juan De Dios
- (3)Pedro David
- (4)Luis Alberto
- (5)Henry
- (6)Eury Alexander
(3)Pedro David
- (4)Luis Alberto
- (5)Henry
- (6)Eury Alexander
(4)Luis Alberto
- (5)Henry
- (6)Eury Alexander
这实际上是我的代码:
$sql = "SELECT * FROM t_usuarios ";
$results = mysqli_query($con,$sql) or die(mysqli_error()) ;
if($results)
{
while($result = mysqli_fetch_array($results))
{
$category['categories'][$result['id']] = $result;
$category['parent_cats'][$result['id_referido']][] = $result['id'];
}
}
function getCategories($parent, $category)
{
$html = "";
if (isset($category['parent_cats'][$parent]))
{
$html .= "<ul>\n";
foreach ($category['parent_cats'][$parent] as $cat_id)
{
if (!isset($category['parent_cats'][$cat_id]))
{
$html .= "<li>*".$category['categories'][$cat_id]['nombres']."</li> \n";
}
if (isset($category['parent_cats'][$cat_id]))
{
$html .= "<li>". $category['categories'][$cat_id]['nombres'] . " \n";
$html .= getCategories($cat_id, $category);
$html .= "</li> \n";
}
}
$html .= "</ul> \n";
}
return $html;
}
echo $data['category'] = getCategories(0, $category);
请帮我找路,我试过了,但不行:
$results2 = mysql_query( "SELECT * FROM t_usuarios ORDER BY id ASC", $link );
while ( $tagrow = mysql_fetch_array( $results2 )){
$sql = "SELECT * FROM t_usuarios WHERE id=".$tagrow["id"]."";
$results = mysqli_query($con,$sql) or die(mysqli_error()) ;
if($results)
{
while($result = mysqli_fetch_array($results))
{
$category['categories'][$result['id']] = $result;
$category['parent_cats'][$result['id_referido']][] = $result['id'];
}
}
function getCategories($parent, $category)
{
$html = "";
if (isset($category['parent_cats'][$parent]))
{
$html .= "<ul>\n";
foreach ($category['parent_cats'][$parent] as $cat_id)
{
if (!isset($category['parent_cats'][$cat_id]))
{
$html .= "<li>*".$category['categories'][$cat_id]['nombres']."</li> \n";
}
if (isset($category['parent_cats'][$cat_id]))
{
$html .= "<li>". $category['categories'][$cat_id]['nombres'] . " \n";
$html .= getCategories($cat_id, $category);
$html .= "</li> \n";
}
}
$html .= "</ul> \n";
}
return $html;
}
echo $data['category'] = getCategories(0, $category);
}
我不明白你在上一个代码中试图做什么,但如果你将第一个代码块中的 echo $data['category'] = getCategories(0, $category);
更改为:
,它应该可以工作
$data['category'] = "";
foreach (array_keys($category['parent_cats']) as $parent)
{
$data['category'] .= getCategories($parent, $category);
}
echo $data['category'];
它做的事情和你已经做过的一样,但每次对每只猫多次使用不同的$parent
。
我想创建一个多级用户脚本,我有以下代码可以工作,但只显示一个用户线程。我的目标是显示每个人的所有用户,每个组中至少有 3 个子用户。
我有这个:
Maximo Eladio
- Jose Anibal
- Juan De Dios
- Pedro David
- Luis Alberto
- Henry
- Eury Alexander
但我想要这个:
(0)Maximo Eladio
- (1)Jose Anibal
- (2)Juan De Dios
- (3)Pedro David
- (4)Luis Alberto
- (5)Henry
- (6)Eury Alexander
(1)Jose Anibal
- (2)Juan De Dios
- (3)Pedro David
- (4)Luis Alberto
- (5)Henry
- (6)Eury Alexander
(2)Juan De Dios
- (3)Pedro David
- (4)Luis Alberto
- (5)Henry
- (6)Eury Alexander
(3)Pedro David
- (4)Luis Alberto
- (5)Henry
- (6)Eury Alexander
(4)Luis Alberto
- (5)Henry
- (6)Eury Alexander
这实际上是我的代码:
$sql = "SELECT * FROM t_usuarios ";
$results = mysqli_query($con,$sql) or die(mysqli_error()) ;
if($results)
{
while($result = mysqli_fetch_array($results))
{
$category['categories'][$result['id']] = $result;
$category['parent_cats'][$result['id_referido']][] = $result['id'];
}
}
function getCategories($parent, $category)
{
$html = "";
if (isset($category['parent_cats'][$parent]))
{
$html .= "<ul>\n";
foreach ($category['parent_cats'][$parent] as $cat_id)
{
if (!isset($category['parent_cats'][$cat_id]))
{
$html .= "<li>*".$category['categories'][$cat_id]['nombres']."</li> \n";
}
if (isset($category['parent_cats'][$cat_id]))
{
$html .= "<li>". $category['categories'][$cat_id]['nombres'] . " \n";
$html .= getCategories($cat_id, $category);
$html .= "</li> \n";
}
}
$html .= "</ul> \n";
}
return $html;
}
echo $data['category'] = getCategories(0, $category);
请帮我找路,我试过了,但不行:
$results2 = mysql_query( "SELECT * FROM t_usuarios ORDER BY id ASC", $link );
while ( $tagrow = mysql_fetch_array( $results2 )){
$sql = "SELECT * FROM t_usuarios WHERE id=".$tagrow["id"]."";
$results = mysqli_query($con,$sql) or die(mysqli_error()) ;
if($results)
{
while($result = mysqli_fetch_array($results))
{
$category['categories'][$result['id']] = $result;
$category['parent_cats'][$result['id_referido']][] = $result['id'];
}
}
function getCategories($parent, $category)
{
$html = "";
if (isset($category['parent_cats'][$parent]))
{
$html .= "<ul>\n";
foreach ($category['parent_cats'][$parent] as $cat_id)
{
if (!isset($category['parent_cats'][$cat_id]))
{
$html .= "<li>*".$category['categories'][$cat_id]['nombres']."</li> \n";
}
if (isset($category['parent_cats'][$cat_id]))
{
$html .= "<li>". $category['categories'][$cat_id]['nombres'] . " \n";
$html .= getCategories($cat_id, $category);
$html .= "</li> \n";
}
}
$html .= "</ul> \n";
}
return $html;
}
echo $data['category'] = getCategories(0, $category);
}
我不明白你在上一个代码中试图做什么,但如果你将第一个代码块中的 echo $data['category'] = getCategories(0, $category);
更改为:
$data['category'] = "";
foreach (array_keys($category['parent_cats']) as $parent)
{
$data['category'] .= getCategories($parent, $category);
}
echo $data['category'];
它做的事情和你已经做过的一样,但每次对每只猫多次使用不同的$parent
。