可以仅使用实例 ID 添加到 Django ManyToManyField

Question

当您只有 ID 列表而没有数据库命中来检索实例时，是否可以添加到 ManyToManyField（add_instances_but_with_db_hit 这样做，但有命中）。

谢谢。

class WorkerCombinedPayment(AbstractReimbursement):
    charge_id = models.TextField(blank=True, null=True)
    paid = models.BooleanField(default=False)
    worker = models.ForeignKey(Worker)

class MassPayment(TimeStampedModel):
    list_payments = JSONField(blank=True, null=True)
    paypal_batch_id = models.TextField(blank=True, null=True)
    success = models.NullBooleanField()
    response_from_paypal = JSONField(blank=True, null=True)
    workercombinedpayments = models.ManyToManyField(WorkerCombinedPayment)

    def add_instances_but_with_db_hit(self, id_list):
        found = WorkerCombinedPayment.objects.filter(id__in=id_list)
        self.workercombinedpayments.add(found)

Answer 1

是的，您可以只传递 ID：

self.workercombinedpayments.add(*id_list)

Answer 2

Facebook Django Python Web 框架小组在 'set' 上回答了我在 thread. Here are the Django docs 中的问题。注意，这将替换现有内容。如果您想更新您的字段而不是覆盖它，请参阅@DanielRoseman 接受的答案。

class WorkerCombinedPayment(AbstractReimbursement):
    charge_id = models.TextField(blank=True, null=True)
    paid = models.BooleanField(default=False)
    worker = models.ForeignKey(Worker)

class MassPayment(TimeStampedModel):
    list_payments = JSONField(blank=True, null=True)
    paypal_batch_id = models.TextField(blank=True, null=True)
    success = models.NullBooleanField()
    response_from_paypal = JSONField(blank=True, null=True)
    workercombinedpayments = models.ManyToManyField(WorkerCombinedPayment)

    def add_instances(self, id_list):
        self.workercombinedpayments.set(id_list)

可以仅使用实例 ID 添加到 Django ManyToManyField

possible to add to Django ManyToManyField with only instance IDs

django

manytomanyfield