处理 JSON 包含多种类型的数组 - Swift 4 可解码
Handling JSON Array Containing Multiple Types - Swift 4 Decodable
我正在尝试使用 Swift 4 Decodable 来解析包含两种不同类型对象的数组。数据看起来像这样,included
数组是包含 Member
和 ImageMedium
对象的数组:
{
"data": [{
"id": "8f7cbbac-c133-4b5e-a2ec-1f32353018fa",
"type": "post",
"title": "Test Post 1",
"owner-id": "8986563c-438c-4d77-8115-9e5de2b6e477",
"owner-type": "member"
}, {
"id": "f6b3c640-a58b-449f-93c7-f6cb7b569a9c",
"type": "post",
"title": "Test Post 2",
"owner-id": "38d845a4-db66-48b9-9c15-d857166e255e",
"owner-type": "member"
}],
"included": [{
"id": "8986563c-438c-4d77-8115-9e5de2b6e477",
"type": "member",
"first-name": "John",
"last-name": "Smith"
}, {
"id": "d7218ca1-de53-4832-bb8f-dbceb6747e98",
"type": "image-medium",
"asset-url": "https://faketest.com/fake-test-1.png",
"owner-id": "f6b3c640-a58b-449f-93c7-f6cb7b569a9c",
"owner-type": "post"
}, {
"id": "c59b8c72-13fc-44fd-8ef9-4b0f8fa486a0",
"type": "image-medium",
"asset-url": "https://faketest.com/fake-test-2.png",
"owner-id": "8f7cbbac-c133-4b5e-a2ec-1f32353018fa",
"owner-type": "post"
}, {
"id": "38d845a4-db66-48b9-9c15-d857166e255e",
"type": "member",
"first-name": "Jack",
"last-name": "Doe"
}]
}
我尝试了很多不同的方法来使用 Decodable 彻底解决这个问题,但到目前为止,唯一对我有用的是为 Included
创建一个包含两个对象的所有属性的结构可选项,像这样:
struct Root: Decodable {
let data: [Post]?
let included: [Included]?
}
struct Post: Decodable {
let id: String?
let type: String?
let title: String?
let ownerId: String?
let ownerType: String?
enum CodingKeys: String, CodingKey {
case id
case type
case title
case ownerId = "owner-id"
case ownerType = "owner-type"
}
}
struct Included: Decodable {
let id: String?
let type: String?
let assetUrl: String?
let ownerId: String?
let ownerType: String?
let firstName: String?
let lastName: String?
enum CodingKeys: String, CodingKey {
case id
case type
case assetUrl = "asset-url"
case ownerId = "owner-id"
case ownerType = "owner-type"
case firstName = "first-name"
case lastName = "last-name"
}
}
这可以通过实现一种方法来工作,该方法根据 type
属性 是什么,从 Included
结构创建 Member
和 ImageMedium
对象,然而,它显然不太理想。我希望有一种方法可以使用自定义 init(from decoder: Decoder)
来完成此操作,但我还没有让它工作。有什么想法吗?
我的建议是对所有项目使用单一类型 Post
。为了区分不同的类型,将 type
键解码为枚举并根据情况解码属性。
这需要将所有 non-global 属性声明为 var
。
struct Root : Decodable {
let data : [Post]
let included : [Post]
}
enum PostType : String, Decodable {
case member, post, imageMedium = "image-medium"
}
struct Post : Decodable {
let id: String
let type: PostType
var title: String?
var assetUrl: String?
var ownerId: String?
var ownerType: String?
var firstName: String?
var lastName: String?
enum CodingKeys: String, CodingKey {
case id, type, title
case assetUrl = "asset-url"
case ownerId = "owner-id"
case ownerType = "owner-type"
case firstName = "first-name"
case lastName = "last-name"
}
init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CodingKeys.self)
id = try container.decode(String.self, forKey: .id)
type = try container.decode(PostType.self, forKey: .type)
switch type {
case .member:
firstName = try container.decode(String.self, forKey: .firstName)
lastName = try container.decode(String.self, forKey: .lastName)
case .post:
title = try container.decode(String.self, forKey: .title)
ownerId = try container.decode(String.self, forKey: .ownerId)
ownerType = try container.decode(String.self, forKey: .ownerType)
case .imageMedium:
assetUrl = try container.decode(String.self, forKey: .assetUrl)
ownerId = try container.decode(String.self, forKey: .ownerId)
ownerType = try container.decode(String.self, forKey: .ownerType)
}
}
}
这是基于最初的编辑,它有一些冗余代码,但总体思路应该是可以理解的:
enum Post: Codable {
case post(id: UUID, title: String, ownerId: UUID, ownerType: PostOwner)
case member(id: UUID, firstName: String, lastName: String)
case imageMedium(id: UUID, assetURL: URL, ownerId: UUID, ownerType: ImageOwner)
enum PostType: String, Codable {
case post
case member
case imageMedium = "image-medium"
}
enum PostOwner: String, Codable {
case member
}
enum ImageOwner: String, Codable {
case post
}
enum CodingKeys: String, CodingKey {
case id
case type
case title
case assetUrl = "asset-url"
case ownerId = "owner-id"
case ownerType = "owner-type"
case firstName = "first-name"
case lastName = "last-name"
}
init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CodingKeys.self)
let id = try container.decode(UUID.self, forKey: .id)
let type = try container.decode(PostType.self, forKey: .type)
switch type {
case .post:
let title = try container.decode(String.self, forKey: .title)
let ownerId = try container.decode(UUID.self, forKey: .ownerId)
let ownerType = try container.decode(PostOwner.self, forKey: .ownerType)
self = .post(id: id, title: title, ownerId: ownerId, ownerType: ownerType)
case .member:
let firstName = try container.decode(String.self, forKey: .firstName)
let lastName = try container.decode(String.self, forKey: .lastName)
self = .member(id: id, firstName: firstName, lastName: lastName)
case .imageMedium:
let assetURL = try container.decode(URL.self, forKey: .assetUrl)
let ownerId = try container.decode(UUID.self, forKey: .ownerId)
let ownerType = try container.decode(ImageOwner.self, forKey: .ownerType)
self = .imageMedium(id: id, assetURL: assetURL, ownerId: ownerId, ownerType: ownerType)
}
}
func encode(to encoder: Encoder) throws {
var container = encoder.container(keyedBy: CodingKeys.self)
switch self {
case .post(let id, let title, let ownerId, let ownerType):
try container.encode(PostType.post, forKey: .type)
try container.encode(id, forKey: .id)
try container.encode(title, forKey: .title)
try container.encode(ownerId, forKey: .ownerId)
try container.encode(ownerType, forKey: .ownerType)
case .member(let id, let firstName, let lastName):
try container.encode(PostType.member, forKey: .type)
try container.encode(id, forKey: .id)
try container.encode(firstName, forKey: .firstName)
try container.encode(lastName, forKey: .lastName)
case .imageMedium(let id, let assetURL, let ownerId, let ownerType):
try container.encode(PostType.imageMedium, forKey: .type)
try container.encode(id, forKey: .id)
try container.encode(assetURL, forKey: .assetUrl)
try container.encode(ownerId, forKey: .ownerId)
try container.encode(ownerType, forKey: .ownerType)
}
}
}
let jsonDecoder = JSONDecoder()
let result = try jsonDecoder.decode([String: [Post]].self, from: yourJSONData)
print(result)
对于当前 post 类型中未使用的字段,它具有零可选,并且 UUID
s 被键入为 UUID
,URL
s 被键入为 URL
而不是到处都是 String
s。
ownerType
被键入为 PostOwner
和 ImageOwner
用于 .post
和 .imageMedium
用于额外的类型安全。
EDIT:好的,我检查了问题的编辑:在你的 json 中只有“.post"s go into "data”,并且休息进入 "included"。在我的回答中,Post
s 和 Included
s 合并为一个类型。
所以应该是这样的:
struct Post: Codable {
let id: UUID
let title: String
let ownerId: UUID
let ownerType: PostOwner
enum PostOwner: String, Codable {
case member
}
enum CodingKeys: String, CodingKey {
case id
case title
case ownerId = "owner-id"
case ownerType = "owner-type"
}
}
enum Included: Codable {
case member(id: UUID, firstName: String, lastName: String)
case imageMedium(id: UUID, assetURL: URL, ownerId: UUID, ownerType: ImageOwner)
enum PostType: String, Codable {
case member
case imageMedium = "image-medium"
}
enum ImageOwner: String, Codable {
case post
}
enum CodingKeys: String, CodingKey {
case id
case type
case title
case assetUrl = "asset-url"
case ownerId = "owner-id"
case ownerType = "owner-type"
case firstName = "first-name"
case lastName = "last-name"
}
init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CodingKeys.self)
let id = try container.decode(UUID.self, forKey: .id)
let type = try container.decode(PostType.self, forKey: .type)
switch type {
case .member:
let firstName = try container.decode(String.self, forKey: .firstName)
let lastName = try container.decode(String.self, forKey: .lastName)
self = .member(id: id, firstName: firstName, lastName: lastName)
case .imageMedium:
let assetURL = try container.decode(URL.self, forKey: .assetUrl)
let ownerId = try container.decode(UUID.self, forKey: .ownerId)
let ownerType = try container.decode(ImageOwner.self, forKey: .ownerType)
self = .imageMedium(id: id, assetURL: assetURL, ownerId: ownerId, ownerType: ownerType)
}
}
func encode(to encoder: Encoder) throws {
var container = encoder.container(keyedBy: CodingKeys.self)
switch self {
case .member(let id, let firstName, let lastName):
try container.encode(PostType.member, forKey: .type)
try container.encode(id, forKey: .id)
try container.encode(firstName, forKey: .firstName)
try container.encode(lastName, forKey: .lastName)
case .imageMedium(let id, let assetURL, let ownerId, let ownerType):
try container.encode(PostType.imageMedium, forKey: .type)
try container.encode(id, forKey: .id)
try container.encode(assetURL, forKey: .assetUrl)
try container.encode(ownerId, forKey: .ownerId)
try container.encode(ownerType, forKey: .ownerType)
}
}
}
Post
键入 parsing/validating could/should 通过手动编码添加 init(from: )
.
我想出了如何将混合的 included
数组解码为两个数组,每个数组都是一种类型。使用两个 Decodable 结构比用一个结构覆盖多种类型的数据更容易处理,也更通用。
对于任何感兴趣的人,这就是我的最终解决方案:
struct Root: Decodable {
let data: [Post]?
let members: [Member]
let images: [ImageMedium]
init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CodingKeys.self)
data = try container.decode([Post].self, forKey: .data)
var includedArray = try container.nestedUnkeyedContainer(forKey: .included)
var membersArray: [Member] = []
var imagesArray: [ImageMedium] = []
while !includedArray.isAtEnd {
do {
if let member = try? includedArray.decode(Member.self) {
membersArray.append(member)
}
else if let image = try? includedArray.decode(ImageMedium.self) {
imagesArray.append(image)
}
}
}
members = membersArray
images = imagesArray
}
enum CodingKeys: String, CodingKey {
case data
case included
}
}
struct Post: Decodable {
let id: String?
let type: String?
let title: String?
let ownerId: String?
let ownerType: String?
enum CodingKeys: String, CodingKey {
case id
case type
case title
case ownerId = "owner-id"
case ownerType = "owner-type"
}
}
struct Member: Decodable {
let id: String?
let type: String?
let firstName: String?
let lastName: String?
enum CodingKeys: String, CodingKey {
case id
case type
case firstName = "first-name"
case lastName = "last-name"
}
}
struct ImageMedium: Decodable {
let id: String?
let type: String?
let assetUrl: String?
let ownerId: String?
let ownerType: String?
enum CodingKeys: String, CodingKey {
case id
case type
case assetUrl = "asset-url"
case ownerId = "owner-id"
case ownerType = "owner-type"
}
}
我正在尝试使用 Swift 4 Decodable 来解析包含两种不同类型对象的数组。数据看起来像这样,included
数组是包含 Member
和 ImageMedium
对象的数组:
{
"data": [{
"id": "8f7cbbac-c133-4b5e-a2ec-1f32353018fa",
"type": "post",
"title": "Test Post 1",
"owner-id": "8986563c-438c-4d77-8115-9e5de2b6e477",
"owner-type": "member"
}, {
"id": "f6b3c640-a58b-449f-93c7-f6cb7b569a9c",
"type": "post",
"title": "Test Post 2",
"owner-id": "38d845a4-db66-48b9-9c15-d857166e255e",
"owner-type": "member"
}],
"included": [{
"id": "8986563c-438c-4d77-8115-9e5de2b6e477",
"type": "member",
"first-name": "John",
"last-name": "Smith"
}, {
"id": "d7218ca1-de53-4832-bb8f-dbceb6747e98",
"type": "image-medium",
"asset-url": "https://faketest.com/fake-test-1.png",
"owner-id": "f6b3c640-a58b-449f-93c7-f6cb7b569a9c",
"owner-type": "post"
}, {
"id": "c59b8c72-13fc-44fd-8ef9-4b0f8fa486a0",
"type": "image-medium",
"asset-url": "https://faketest.com/fake-test-2.png",
"owner-id": "8f7cbbac-c133-4b5e-a2ec-1f32353018fa",
"owner-type": "post"
}, {
"id": "38d845a4-db66-48b9-9c15-d857166e255e",
"type": "member",
"first-name": "Jack",
"last-name": "Doe"
}]
}
我尝试了很多不同的方法来使用 Decodable 彻底解决这个问题,但到目前为止,唯一对我有用的是为 Included
创建一个包含两个对象的所有属性的结构可选项,像这样:
struct Root: Decodable {
let data: [Post]?
let included: [Included]?
}
struct Post: Decodable {
let id: String?
let type: String?
let title: String?
let ownerId: String?
let ownerType: String?
enum CodingKeys: String, CodingKey {
case id
case type
case title
case ownerId = "owner-id"
case ownerType = "owner-type"
}
}
struct Included: Decodable {
let id: String?
let type: String?
let assetUrl: String?
let ownerId: String?
let ownerType: String?
let firstName: String?
let lastName: String?
enum CodingKeys: String, CodingKey {
case id
case type
case assetUrl = "asset-url"
case ownerId = "owner-id"
case ownerType = "owner-type"
case firstName = "first-name"
case lastName = "last-name"
}
}
这可以通过实现一种方法来工作,该方法根据 type
属性 是什么,从 Included
结构创建 Member
和 ImageMedium
对象,然而,它显然不太理想。我希望有一种方法可以使用自定义 init(from decoder: Decoder)
来完成此操作,但我还没有让它工作。有什么想法吗?
我的建议是对所有项目使用单一类型 Post
。为了区分不同的类型,将 type
键解码为枚举并根据情况解码属性。
这需要将所有 non-global 属性声明为 var
。
struct Root : Decodable {
let data : [Post]
let included : [Post]
}
enum PostType : String, Decodable {
case member, post, imageMedium = "image-medium"
}
struct Post : Decodable {
let id: String
let type: PostType
var title: String?
var assetUrl: String?
var ownerId: String?
var ownerType: String?
var firstName: String?
var lastName: String?
enum CodingKeys: String, CodingKey {
case id, type, title
case assetUrl = "asset-url"
case ownerId = "owner-id"
case ownerType = "owner-type"
case firstName = "first-name"
case lastName = "last-name"
}
init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CodingKeys.self)
id = try container.decode(String.self, forKey: .id)
type = try container.decode(PostType.self, forKey: .type)
switch type {
case .member:
firstName = try container.decode(String.self, forKey: .firstName)
lastName = try container.decode(String.self, forKey: .lastName)
case .post:
title = try container.decode(String.self, forKey: .title)
ownerId = try container.decode(String.self, forKey: .ownerId)
ownerType = try container.decode(String.self, forKey: .ownerType)
case .imageMedium:
assetUrl = try container.decode(String.self, forKey: .assetUrl)
ownerId = try container.decode(String.self, forKey: .ownerId)
ownerType = try container.decode(String.self, forKey: .ownerType)
}
}
}
这是基于最初的编辑,它有一些冗余代码,但总体思路应该是可以理解的:
enum Post: Codable {
case post(id: UUID, title: String, ownerId: UUID, ownerType: PostOwner)
case member(id: UUID, firstName: String, lastName: String)
case imageMedium(id: UUID, assetURL: URL, ownerId: UUID, ownerType: ImageOwner)
enum PostType: String, Codable {
case post
case member
case imageMedium = "image-medium"
}
enum PostOwner: String, Codable {
case member
}
enum ImageOwner: String, Codable {
case post
}
enum CodingKeys: String, CodingKey {
case id
case type
case title
case assetUrl = "asset-url"
case ownerId = "owner-id"
case ownerType = "owner-type"
case firstName = "first-name"
case lastName = "last-name"
}
init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CodingKeys.self)
let id = try container.decode(UUID.self, forKey: .id)
let type = try container.decode(PostType.self, forKey: .type)
switch type {
case .post:
let title = try container.decode(String.self, forKey: .title)
let ownerId = try container.decode(UUID.self, forKey: .ownerId)
let ownerType = try container.decode(PostOwner.self, forKey: .ownerType)
self = .post(id: id, title: title, ownerId: ownerId, ownerType: ownerType)
case .member:
let firstName = try container.decode(String.self, forKey: .firstName)
let lastName = try container.decode(String.self, forKey: .lastName)
self = .member(id: id, firstName: firstName, lastName: lastName)
case .imageMedium:
let assetURL = try container.decode(URL.self, forKey: .assetUrl)
let ownerId = try container.decode(UUID.self, forKey: .ownerId)
let ownerType = try container.decode(ImageOwner.self, forKey: .ownerType)
self = .imageMedium(id: id, assetURL: assetURL, ownerId: ownerId, ownerType: ownerType)
}
}
func encode(to encoder: Encoder) throws {
var container = encoder.container(keyedBy: CodingKeys.self)
switch self {
case .post(let id, let title, let ownerId, let ownerType):
try container.encode(PostType.post, forKey: .type)
try container.encode(id, forKey: .id)
try container.encode(title, forKey: .title)
try container.encode(ownerId, forKey: .ownerId)
try container.encode(ownerType, forKey: .ownerType)
case .member(let id, let firstName, let lastName):
try container.encode(PostType.member, forKey: .type)
try container.encode(id, forKey: .id)
try container.encode(firstName, forKey: .firstName)
try container.encode(lastName, forKey: .lastName)
case .imageMedium(let id, let assetURL, let ownerId, let ownerType):
try container.encode(PostType.imageMedium, forKey: .type)
try container.encode(id, forKey: .id)
try container.encode(assetURL, forKey: .assetUrl)
try container.encode(ownerId, forKey: .ownerId)
try container.encode(ownerType, forKey: .ownerType)
}
}
}
let jsonDecoder = JSONDecoder()
let result = try jsonDecoder.decode([String: [Post]].self, from: yourJSONData)
print(result)
对于当前 post 类型中未使用的字段,它具有零可选,并且 UUID
s 被键入为 UUID
,URL
s 被键入为 URL
而不是到处都是 String
s。
ownerType
被键入为 PostOwner
和 ImageOwner
用于 .post
和 .imageMedium
用于额外的类型安全。
EDIT:好的,我检查了问题的编辑:在你的 json 中只有“.post"s go into "data”,并且休息进入 "included"。在我的回答中,Post
s 和 Included
s 合并为一个类型。
所以应该是这样的:
struct Post: Codable {
let id: UUID
let title: String
let ownerId: UUID
let ownerType: PostOwner
enum PostOwner: String, Codable {
case member
}
enum CodingKeys: String, CodingKey {
case id
case title
case ownerId = "owner-id"
case ownerType = "owner-type"
}
}
enum Included: Codable {
case member(id: UUID, firstName: String, lastName: String)
case imageMedium(id: UUID, assetURL: URL, ownerId: UUID, ownerType: ImageOwner)
enum PostType: String, Codable {
case member
case imageMedium = "image-medium"
}
enum ImageOwner: String, Codable {
case post
}
enum CodingKeys: String, CodingKey {
case id
case type
case title
case assetUrl = "asset-url"
case ownerId = "owner-id"
case ownerType = "owner-type"
case firstName = "first-name"
case lastName = "last-name"
}
init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CodingKeys.self)
let id = try container.decode(UUID.self, forKey: .id)
let type = try container.decode(PostType.self, forKey: .type)
switch type {
case .member:
let firstName = try container.decode(String.self, forKey: .firstName)
let lastName = try container.decode(String.self, forKey: .lastName)
self = .member(id: id, firstName: firstName, lastName: lastName)
case .imageMedium:
let assetURL = try container.decode(URL.self, forKey: .assetUrl)
let ownerId = try container.decode(UUID.self, forKey: .ownerId)
let ownerType = try container.decode(ImageOwner.self, forKey: .ownerType)
self = .imageMedium(id: id, assetURL: assetURL, ownerId: ownerId, ownerType: ownerType)
}
}
func encode(to encoder: Encoder) throws {
var container = encoder.container(keyedBy: CodingKeys.self)
switch self {
case .member(let id, let firstName, let lastName):
try container.encode(PostType.member, forKey: .type)
try container.encode(id, forKey: .id)
try container.encode(firstName, forKey: .firstName)
try container.encode(lastName, forKey: .lastName)
case .imageMedium(let id, let assetURL, let ownerId, let ownerType):
try container.encode(PostType.imageMedium, forKey: .type)
try container.encode(id, forKey: .id)
try container.encode(assetURL, forKey: .assetUrl)
try container.encode(ownerId, forKey: .ownerId)
try container.encode(ownerType, forKey: .ownerType)
}
}
}
Post
键入 parsing/validating could/should 通过手动编码添加 init(from: )
.
我想出了如何将混合的 included
数组解码为两个数组,每个数组都是一种类型。使用两个 Decodable 结构比用一个结构覆盖多种类型的数据更容易处理,也更通用。
对于任何感兴趣的人,这就是我的最终解决方案:
struct Root: Decodable {
let data: [Post]?
let members: [Member]
let images: [ImageMedium]
init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CodingKeys.self)
data = try container.decode([Post].self, forKey: .data)
var includedArray = try container.nestedUnkeyedContainer(forKey: .included)
var membersArray: [Member] = []
var imagesArray: [ImageMedium] = []
while !includedArray.isAtEnd {
do {
if let member = try? includedArray.decode(Member.self) {
membersArray.append(member)
}
else if let image = try? includedArray.decode(ImageMedium.self) {
imagesArray.append(image)
}
}
}
members = membersArray
images = imagesArray
}
enum CodingKeys: String, CodingKey {
case data
case included
}
}
struct Post: Decodable {
let id: String?
let type: String?
let title: String?
let ownerId: String?
let ownerType: String?
enum CodingKeys: String, CodingKey {
case id
case type
case title
case ownerId = "owner-id"
case ownerType = "owner-type"
}
}
struct Member: Decodable {
let id: String?
let type: String?
let firstName: String?
let lastName: String?
enum CodingKeys: String, CodingKey {
case id
case type
case firstName = "first-name"
case lastName = "last-name"
}
}
struct ImageMedium: Decodable {
let id: String?
let type: String?
let assetUrl: String?
let ownerId: String?
let ownerType: String?
enum CodingKeys: String, CodingKey {
case id
case type
case assetUrl = "asset-url"
case ownerId = "owner-id"
case ownerType = "owner-type"
}
}