如何在 python 中按下某个键时停止程序?
How to stop a program when a key is pressed in python?
我有一个无限循环的程序,每 5 秒打印一次 "program running",我想在按下结束键时停止它。
所以我创建了一个按键侦听器,如果按下结束键,则 returns 为 false。如果我没有无限循环,那应该可以工作。我希望它即使在我处于无限循环中时也能正常工作。
这是我的代码:
from pynput import keyboard
import time
def on_press(key):
print key
if key == keyboard.Key.end:
print 'end pressed'
return False
with keyboard.Listener(on_press=on_press) as listener:
while True:
print 'program running'
time.sleep(5)
listener.join()
from pynput import keyboard
import time
break_program = False
def on_press(key):
global break_program
print (key)
if key == keyboard.Key.end:
print ('end pressed')
break_program = True
return False
with keyboard.Listener(on_press=on_press) as listener:
while break_program == False:
print ('program running')
time.sleep(5)
listener.join()
我有一个无限循环的程序,每 5 秒打印一次 "program running",我想在按下结束键时停止它。
所以我创建了一个按键侦听器,如果按下结束键,则 returns 为 false。如果我没有无限循环,那应该可以工作。我希望它即使在我处于无限循环中时也能正常工作。
这是我的代码:
from pynput import keyboard
import time
def on_press(key):
print key
if key == keyboard.Key.end:
print 'end pressed'
return False
with keyboard.Listener(on_press=on_press) as listener:
while True:
print 'program running'
time.sleep(5)
listener.join()
from pynput import keyboard
import time
break_program = False
def on_press(key):
global break_program
print (key)
if key == keyboard.Key.end:
print ('end pressed')
break_program = True
return False
with keyboard.Listener(on_press=on_press) as listener:
while break_program == False:
print ('program running')
time.sleep(5)
listener.join()