如何 运行 在 Visual Studio 中使用任务编写代码

How to run Cmake in Visual Studio Code using tasks

我正尝试 运行 cmake 与 ctrl+shift+B 像这样:

{
"version": "2.0.0",
"tasks": [
    {
        "label": "cmake",
        "type": "shell",
        "options": {
            "cwd": "${workspaceRoot}/build"
        },
        "command": "cmake ${workspaceRoot} -G \"MinGW Makefiles\"",
        (...)
    },
    {
        "label": "make",
        "type": "shell",
        "command": "mingw32-make.exe",
        "options": {
            "cwd": "${workspaceRoot}/build"
        },
       (...),
        "dependsOn":["cmake"]
    },
    {
        "label": "build",
        "type": "shell",
        "options": {
            "cwd": "${workspaceRoot}/build"
        },
        "group": {
            "kind": "build",
            "isDefault": true
        },
        "dependsOn": ["make"]
    }
]
}

但无论我做什么 运行s on ${workspaceRoot} 而不是 ${workspaceRoot}/build one:

Executing task in folder cpppractice: cmake C:\workspace\cpp\cpppractice -G "MinGW Makefiles"

这种方法有什么问题吗?据我了解 options 项中的 cwd 变量应该有效。

您错误地向 cmake 传递了参数。整个字符串 cmake ${workspaceRoot} -G "MinGW Makefiles" 被视为命令名称。参数必须列在 args 数组中。

{
    "version": "2.0.0",
    "tasks": [
        {
            "label": "cmake",
            "type": "shell",
            "options": {
                "cwd": "${workspaceRoot}/build"
            },
            "command": "cmake",
            "args": [
                "${workspaceRoot}",
                "-G",
                "\"MinGW Makefiles\""
            ]
        },
        ...
    ]
}
{
    "label": "cmake",
    "type": "shell",
    "options": {
        "cwd": "${workspaceRoot}/build"
    },
    "command": "cmake \"MinGW Makefiles\"  ${workspaceRoot}",
},

这个可以,好像是"Executing task in folder cpppractice:"不准确,是在正确的地方执行的,至于之前为什么不行我觉得是args解析不正确?我无法确认,但这是输出:

Executing task in folder cpppractice: cmake "MinGW Makefiles"  
C:\workspace\cpp\cpppractice <

-- Configuring done
-- Generating done
-- Build files have been written to: C:/workspace/cpp/cpppractice/build

之前抱怨无法使用生成器 "MinGW",这意味着它将参数 "MinGW Makefiles" 分开。 经过一些修补,我发现这也是一个答案:

{
        "label": "cmake",
        "type": "shell",
        "options": {
            "cwd": "${workspaceRoot}/build"
        },
        "command": "cmake",
        "args": [
            "-G",
            "'MinGW Makefiles'",
            "./.."
        ],
        ...
    },

实际上我发现第二种方法更简洁一些,但两者的工作原理相同,因此为了将参数作为字符串传递,您必须像这样使用单引号:

...
"command":"echo",
"args": [
        "'Za Warudo!'",
    ],
...