在列表中附加用户输入

Question

我运行遇到了第二个和第三个 if 语句的问题。它似乎确实注册了输入，但没有将其添加到列表中。如果按 2 添加产品并按 1 列出产品，您可以观察到我正在谈论的问题。你会注意到没有什么可悲的出现。就像列表仍然是空的，但我已经给了它一个项目。有什么办法可以解决吗？

hell_is_not_frozen = True
while hell_is_not_frozen:

  #menu 
  def menu():
    tab = ' '
    print (40*'=')
    print (8*tab + 'Shopping list app v1\n')
    print (12*tab + 'MAIN MENU \n\n')



  #options
  def options():
    print('[1] View products in list \n'
          '[2] Add a product to list \n'    
          '[3] Remove a product from list :c \n'
          '[4] Exit program\n\n'
          'To choose an option type coresponding number:')

  #calling feds (defs backwords) nice joke isn't it ?  :)
  menu()
  options()

  #Making sure input is int type
  #TODO Implement anit-other-character system 
  numberInt = raw_input()
  number = int(numberInt)

  #Core of this app
  shoppingList = []



  #checking wich option was picked  
  if number == 1:
    if len(shoppingList) == 0:
      print('\nYour shopping list doesn\'t seem to contain any products')
    print ('\n')
    print('\n'.join(shoppingList)) 
    print ('\n\n\n')

  if number == 2:
    #taking a name of beloved product user would like to add
    productAddStr = raw_input("\nWhat product would you want to add in?\n")
    productAdd = str(productAddStr)
    shoppingList.append(productAdd)
    print(shoppingList)

  if number == 3:
    #taking a name of beloved product user would like to Remove
    productRmStr = raw_input("\nWhat product would you want to add in?\n")
    productRm = str(productRmStr)
    shoppingList.remove(productRm)

  if number == 4:
    #Exiting
    print('\nSee you next time :D')
    hell_is_not_frozen = False

Answer 1

我看到了 2 个问题：

1，您在 while 循环中重新初始化 shoppingList = []，这基本上意味着其中的值每隔运行就会被忽略。将此初始化移出 while 循环。

hell_is_not_frozen = True
#Core of this app
shoppingList = []
while hell_is_not_frozen:
    # remaining code goes here

第二个是这个 if 块

if number == 3:
    #taking a name of beloved product user would like to Remove
    productRmStr = raw_input("\nWhat product would you want to add in?\n")
    productRm = str(productRmStr)
    shoppingList.remove(productRm)

在这里，您尝试删除 productRm 而不检查它是否存在于列表中，这将抛出 ValueError。我建议您检查该产品是否存在，然后尝试将其删除，或者在 try-except:

中包含 .remove

if number == 3:
    #taking a name of beloved product user would like to Remove
    productRmStr = raw_input("\nWhat product would you want to add in?\n")
    productRm = str(productRmStr)
    try:
        shoppingList.remove(productRm)
    except ValueError:
        pass

在列表中附加用户输入

Appending user input in a list

python

python-2.x