无法识别的选择器发送到实例 Xcode 9

Question

I have list of items to display in table view. And on clicking of each item i want to trigger a method. i-e

var menuItems = [LeftMenuItem]() // -> Define at top of vie controller

func populateLeftMenuData() {  // populating data in viewDidLoad
        var leftMenuItem =  LeftMenuItem(imageName: "flagIcon", cellLabel : "Home" , method : "home")
        menuItems.append(leftMenuItem)
        leftMenuItem =  LeftMenuItem(imageName: "flagIcon", cellLabel : "Logout" , method : "logout")
        menuItems.append(leftMenuItem)
    }

This is how data is populating in tableview. On each row i am displaying "cell label" and on clicking of cell i want to call the "method".

what i am doing is

func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
            let leftMenuItem = menuItems[indexPath.row]
            perform(Selector(leftMenuItem.method!))
        }

    func logout () {
           print("logout")   
        }

    func home () {
           print("Home")  
        }

But clicking on cell it saying unrecognised selector sent to an instance. where as same thing is working fine for xCode 8 swift 3.

Answer 1

只需将 @objc 放在使用 Selectors 调用的所有方法之上：

@objc func logout() {
    print("logout")
}

@objc func home() {
    print("Home")
}

中Swift4、@objc inference is very limited。我怀疑在 Swift.

中动态创建 Selector 是不是一个好策略