Uncaught ReferenceError: jsonFlickrFeed is not defined

Question

我有以下要求：

const flickrApiPoint = "https://api.flickr.com/services/feeds/photos_public.gne";

try {

  $.ajax({
    url: flickrApiPoint,
    dataType: 'jsonp',
    data: { "format": "json" },
    success: function (data) {
      console.log(data); //formatted JSON data
    }
  });
}
catch (e) {
  console.log(e);
}

但最后我得到

Uncaught ReferenceError: jsonFlickrFeed is not defined
    at photos_public.gne?&callback=jQuery331016421245174669186_1523107884637&format=json&_=1523107884638:1

我做错了什么，我该如何解决？提前致谢！

Answer 1

您的 URLflickrApiPoint 不完整。必须是 const flickrApiPoint = "https://api.flickr.com/services/feeds/photos_public.gne?jsoncallback=?";

完整示例：

const flickrApiPoint = "https://api.flickr.com/services/feeds/photos_public.gne?jsoncallback=?";

    try {

          $.ajax({
            url: flickrApiPoint,
            dataType: 'jsonp',
            data: {format: "json"},
            success: function (data) {
              console.log(data); //formatted JSON data
            }
      });
    }
    catch (e) {
      console.log(e);
    }

Answer 2

因为您正在使用 jsonp ajax 调用，flickr 服务 returns 对函数的调用：jsonFlickrFeed 这意味着您必须在代码中自己定义这样的函数：

function jsonFlickrFeed(json) {
    console.log(json);

    $.each(json.items, function (i, item) {
        $("<img />").attr("src", item.media.m).appendTo("#images");
    });
}

这样的功能会在 ajax 完成后自动执行。因此，您需要定义一个 jsonFlickrFeed 函数回调，而不是成功 ajax 回调。

function jsonFlickrFeed(json) {
    //console.log(json);
    console.log('jsonFlickrFeed called');

    $.each(json.items, function (i, item) {
        $("<img />").attr("src", item.media.m).appendTo("#images");
    });
}
const flickrApiPoint = "https://api.flickr.com/services/feeds/photos_public.gne";

try {

    $.ajax({
        url: flickrApiPoint,
        dataType: 'jsonp',
        data: { "format": "json" },
        complete: function (data) {
            console.log('ajax call completed'); //formatted JSON data
        }
    });
}
catch (e) {
    console.log(e);
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>


<div id="images"></div>

Answer 3

使用参数nojsoncallback=1只获取JSON个对象。

const flickrApiPoint = "https://api.flickr.com/services/feeds/photos_public.gne?nojsoncallback=1";

Uncaught ReferenceError: jsonFlickrFeed is not defined

Uncaught ReferenceError: jsonFlickrFeed is not defined

javascript

ajax

flickr

request