NSCharacterSet URLHostAllowedCharacterSet 不替换“+”号?
NSCharacterSet URLHostAllowedCharacterSet doesn't replace '+' sign?
我正在努力通过网络传输长加密字符串并让它们在服务器上正确输出。例如,我在客户端有这个加密字符串:
wcWSERZCh8Xm1hpbNo1kSD1LvFmpuUr4wmq9hQUWeK0vYcLeFPGwFR/sBTES1A4rPV6eyp9nzEEU9uKkiFSTdP+SPOSqUf6evjf3WRHrXMRe81lIrHuRyk0iRwoNe5uIk+VlpR41kETmznXa4+gELmf53r7oayRkkffnIPDmpO+WbgE0VL3PQeOsXB01tWJyDiBIsz5WJiiEIm3ZoJW/sw==
如您所见,如果没有某些 URL 编码(最值得注意的是 +
和 /
,它有一些字符将无法通过网络传输。我不完全确定在其他情况下是否会出现其他字符,因此我想确保我的解决方案 'universally' 正确。我正在使用这条线:
NSString *escapedString = [cipherString stringByAddingPercentEncodingWithAllowedCharacters:[NSCharacterSet URLHostAllowedCharacterSet]];
我在高度评价 answer 中找到的。
然而,我在服务器端解密仍然遇到问题,所以我在发送前立即在客户端打印了结果,我看到了这个:
wcWSERZCh8Xm1hpbNo1kSD1LvFmpuUr4wmq9hQUWeK0vYcLeFPGwFR%2FsBTES1A4rPV6eyp9nzEEU9uKkiFSTdP+SPOSqUf6evjf3WRHrXMRe81lIrHuRyk0iRwoNe5uIk+VlpR41kETmznXa4+gELmf53r7oayRkkffnIPDmpO+WbgE0VL3PQeOsXB01tWJyDiBIsz5WJiiEIm3ZoJW%2Fsw==
为什么“+”号还在那里?我使用了错误的允许字符集吗?我应该使用哪个字符集来保证我正确转义所有有问题的字符?
如果有帮助,这是我用来加密纯文本字符串的代码。完成后,我在通过网络发送之前对结果进行 base64 编码:
- (NSData *)phpEncryptCleartext : (NSData *)cleartext
{
NSData *cleartextPadded = [self phpPadData:cleartext];
CCCryptorStatus ccStatus = kCCSuccess;
size_t cryptBytes = 0; // Number of bytes moved to buffer.
NSMutableData *cipherTextData = [NSMutableData dataWithLength:cleartextPadded.length];
ccStatus = CCCrypt(kCCEncrypt,
kCCAlgorithmAES128,
0,
_sessionKey.bytes,
kCCKeySizeAES128,
_iv.bytes,
cleartextPadded.bytes,
cleartextPadded.length,
cipherTextData.mutableBytes,
cipherTextData.length,
&cryptBytes);
if (ccStatus == kCCSuccess) {
cipherTextData.length = cryptBytes;
}
else {
NSLog(@"kEncryptionError code: %d", ccStatus); // Add error handling
cipherTextData = nil;
}
return cipherTextData;
}
感谢任何建议!
Swift version here.
转义字符使用stringByAddingPercentEncodingWithAllowedCharacters:
NSString *URLEscapedString =
[string stringByAddingPercentEncodingWithAllowedCharacters:[NSCharacterSet URLQueryAllowedCharacterSet]];
以下是有用的字符集,其实集里没有的字符:
URLFragmentAllowedCharacterSet "#%<>[\]^`{|}
URLHostAllowedCharacterSet "#%/<>?@\^`{|}
URLPasswordAllowedCharacterSet "#%/:<>?@[\]^`{|}
URLPathAllowedCharacterSet "#%;<>?[\]^`{|}
URLQueryAllowedCharacterSet "#%<>[\]^`{|}
URLUserAllowedCharacterSet "#%/:<>?@[\]^`
或者只使用需要转义的字符创建自己的字符集。
NSCharacterSet *customCharacterset = [[NSCharacterSet characterSetWithCharactersInString:@"your characters"] invertedSet];
结合以上所有内容创建字符集:
NSCharacterSet *URLFullCharacterSet = [[NSCharacterSet characterSetWithCharactersInString:@" \"#%/:<>?@[\]^`{|}"] invertedSet];
创建 Base64
如果是Base64字符集:
NSCharacterSet *URLBase64CharacterSet = [[NSCharacterSet characterSetWithCharactersInString:@"/+=\n"] invertedSet];
注意:stringByAddingPercentEncodingWithAllowedCharacters
还将对需要编码的 UTF-8 字符进行编码。
验证集合中字符的示例:
void characterInSet(NSCharacterSet *set) {
NSMutableString *characters = [NSMutableString new];
NSCharacterSet *invertedSet = set.invertedSet;
for (int i=32; i<127; i++) {
if ([invertedSet characterIsMember:(unichar)i]) {
NSString *c = [[NSString alloc] initWithBytes:&i length:1 encoding:NSUTF8StringEncoding];
[characters appendString:c];
}
}
printf("characters not in set: '%s'\n", [characters UTF8String]);
}
我正在努力通过网络传输长加密字符串并让它们在服务器上正确输出。例如,我在客户端有这个加密字符串:
wcWSERZCh8Xm1hpbNo1kSD1LvFmpuUr4wmq9hQUWeK0vYcLeFPGwFR/sBTES1A4rPV6eyp9nzEEU9uKkiFSTdP+SPOSqUf6evjf3WRHrXMRe81lIrHuRyk0iRwoNe5uIk+VlpR41kETmznXa4+gELmf53r7oayRkkffnIPDmpO+WbgE0VL3PQeOsXB01tWJyDiBIsz5WJiiEIm3ZoJW/sw==
如您所见,如果没有某些 URL 编码(最值得注意的是 +
和 /
,它有一些字符将无法通过网络传输。我不完全确定在其他情况下是否会出现其他字符,因此我想确保我的解决方案 'universally' 正确。我正在使用这条线:
NSString *escapedString = [cipherString stringByAddingPercentEncodingWithAllowedCharacters:[NSCharacterSet URLHostAllowedCharacterSet]];
我在高度评价 answer 中找到的。
然而,我在服务器端解密仍然遇到问题,所以我在发送前立即在客户端打印了结果,我看到了这个:
wcWSERZCh8Xm1hpbNo1kSD1LvFmpuUr4wmq9hQUWeK0vYcLeFPGwFR%2FsBTES1A4rPV6eyp9nzEEU9uKkiFSTdP+SPOSqUf6evjf3WRHrXMRe81lIrHuRyk0iRwoNe5uIk+VlpR41kETmznXa4+gELmf53r7oayRkkffnIPDmpO+WbgE0VL3PQeOsXB01tWJyDiBIsz5WJiiEIm3ZoJW%2Fsw==
为什么“+”号还在那里?我使用了错误的允许字符集吗?我应该使用哪个字符集来保证我正确转义所有有问题的字符?
如果有帮助,这是我用来加密纯文本字符串的代码。完成后,我在通过网络发送之前对结果进行 base64 编码:
- (NSData *)phpEncryptCleartext : (NSData *)cleartext
{
NSData *cleartextPadded = [self phpPadData:cleartext];
CCCryptorStatus ccStatus = kCCSuccess;
size_t cryptBytes = 0; // Number of bytes moved to buffer.
NSMutableData *cipherTextData = [NSMutableData dataWithLength:cleartextPadded.length];
ccStatus = CCCrypt(kCCEncrypt,
kCCAlgorithmAES128,
0,
_sessionKey.bytes,
kCCKeySizeAES128,
_iv.bytes,
cleartextPadded.bytes,
cleartextPadded.length,
cipherTextData.mutableBytes,
cipherTextData.length,
&cryptBytes);
if (ccStatus == kCCSuccess) {
cipherTextData.length = cryptBytes;
}
else {
NSLog(@"kEncryptionError code: %d", ccStatus); // Add error handling
cipherTextData = nil;
}
return cipherTextData;
}
感谢任何建议!
Swift version here.
转义字符使用stringByAddingPercentEncodingWithAllowedCharacters:
NSString *URLEscapedString =
[string stringByAddingPercentEncodingWithAllowedCharacters:[NSCharacterSet URLQueryAllowedCharacterSet]];
以下是有用的字符集,其实集里没有的字符:
URLFragmentAllowedCharacterSet "#%<>[\]^`{|}
URLHostAllowedCharacterSet "#%/<>?@\^`{|}
URLPasswordAllowedCharacterSet "#%/:<>?@[\]^`{|}
URLPathAllowedCharacterSet "#%;<>?[\]^`{|}
URLQueryAllowedCharacterSet "#%<>[\]^`{|}
URLUserAllowedCharacterSet "#%/:<>?@[\]^`
或者只使用需要转义的字符创建自己的字符集。
NSCharacterSet *customCharacterset = [[NSCharacterSet characterSetWithCharactersInString:@"your characters"] invertedSet];
结合以上所有内容创建字符集:
NSCharacterSet *URLFullCharacterSet = [[NSCharacterSet characterSetWithCharactersInString:@" \"#%/:<>?@[\]^`{|}"] invertedSet];
创建 Base64
如果是Base64字符集:
NSCharacterSet *URLBase64CharacterSet = [[NSCharacterSet characterSetWithCharactersInString:@"/+=\n"] invertedSet];
注意:stringByAddingPercentEncodingWithAllowedCharacters
还将对需要编码的 UTF-8 字符进行编码。
验证集合中字符的示例:
void characterInSet(NSCharacterSet *set) {
NSMutableString *characters = [NSMutableString new];
NSCharacterSet *invertedSet = set.invertedSet;
for (int i=32; i<127; i++) {
if ([invertedSet characterIsMember:(unichar)i]) {
NSString *c = [[NSString alloc] initWithBytes:&i length:1 encoding:NSUTF8StringEncoding];
[characters appendString:c];
}
}
printf("characters not in set: '%s'\n", [characters UTF8String]);
}