python pulp 与变量 dict 的值不匹配

Question

这几天我一直在努力简化约束。还在学习python。请帮忙，提前谢谢你。

    Employees=['Paul', 'Ben', 'Nasim', 'Ceci', 'Victoria',]
    Days = ['Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday',      
    'Saturday', 'Sunday']

    avail = pulp.LpVariable.dicts("on_off", ((employee, day) for     
    employee in Employees for day in Days), cat="Binary")

    requests={"Paul": {"Monday":1, "Tuesday":1, "Wednesday":1,   
    "Thursday":1, "Friday":1, "Saturday":1, "Sunday":1},
    "Ben": {"Monday":1, "Tuesday":1, "Wednesday":1, "Thursday":1, 
    "Friday":1, "Saturday":1, "Sunday":0},
    "Nasim": {"Monday":1, "Tuesday":1, "Wednesday":1, "Thursday":1, 
    "Friday":1, "Saturday":1, "Sunday":1},
    "Ceci": {"Monday":1, "Tuesday":1, "Wednesday":1, "Thursday":1, 
    "Friday":1,"Saturday":1, "Sunday":0},
    "Victoria": {"Monday":1, "Tuesday":1, "Wednesday":0, "Thursday":0, 
    "Friday":0, "Saturday":0, "Sunday":0}}



    for employee, day in avail:
            prob += avail[employee, day] == [requests[i][j] for i in    
            requests for j in requests[i]]

举个例子，前几个约束：

"_C13: on_off_('Paul',_'Monday') = 28
_C14: on_off_('Paul',_'Tuesday') = 28
_C15: on_off_('Paul',_'Wednesday') = 28
_C16: on_off_('Paul',_'Thursday') = 28
_C17: on_off_('Paul',_'Friday') = 28
_C18: on_off_('Paul',_'Saturday') = 28"

（“28”恰好是我嵌套字典中所有 1 和 0 的总和。）

相反，我希望每个变量都匹配我的嵌套字典中的 1 和 0。

"_C13: on_off_('Paul',_'Monday') = 1
_C14: on_off_('Paul',_'Tuesday') = 1
_C15: on_off_('Paul',_'Wednesday') = 1
_C16: on_off_('Paul',_'Thursday') = 1
_C17: on_off_('Paul',_'Friday') = 1
_C18: on_off_('Paul',_'Saturday') = 1"

Answer 1

在 == 符号后，您需要字典中的值 1 或 0，因此您应该使用：

for employee, day in avail:
    prob += avail[employee, day] == requests[employee][day]

对于请求[员工]，您select该员工的字典

requests['Paul'] = {"Monday":1, "Tuesday":1, "Wednesday":1,   
"Thursday":1, "Friday":1, "Saturday":1, "Sunday":1}

然后通过添加 [day] 你 select 字典中的那一天：

 requests['Paul']['Monday'] = 1

python pulp 与变量 dict 的值不匹配

python pulp not matching value of variable dict

python

pulp