如何进行线程安全的字典操作
How to do Thread Safe Dictionary Manipulation
如何以线程安全的方式操作字典,我想将字典存储到 2 个具有不同字典值的不同队列(操作前 1 个,操作后 1 个)但结果是它们都在操作后存储字典。
这是我的代码
from threading import Timer, Lock
from queue import Queue
q = Queue(maxsize=10000)
k = Queue(maxsize=10000)
k_lock = Lock()
q_lock = Lock()
def write_func(x):
rows = []
while not x.empty():
rows.append(x.get())
if len(rows) == 0:
return
print('A Row is {} and total A row is {}'.format(rows, len(rows)))
def write_k(x):
rows = []
while not x.empty():
rows.append(x.get())
if len(rows) == 0:
return
print('B Row is {} and total B row is {}'.format(rows, len(rows)))
def write_caller(sec=10):
write_func(q)
Timer(sec, write_caller, [sec]).start()
def k_caller(sec=1):
write_k(k)
Timer(sec, k_caller, [sec]).start()
write_caller()
k_caller()
while True:
val = {"event": "lazada"}
k.put(val)
q_val = val
with Lock():
q_val["dt"] = "2018-04-11"
q.put(q_val)
if q.qsize() >= 10:
write_func(q)
上面代码的结果是这样的
A Row is [{'event': 'lazada', 'dt': '2018-04-11'}, ...]
B Row is [{'event': 'lazada', 'dt': '2018-04-11'}, ...]
但我希望 B 行只包含 'event' 而没有 'dt'。这就是我想要的
A Row is [{'event': 'lazada', 'dt': '2018-04-11'}, ...]
B Row is [{'event': 'lazada'}, ...]
当您执行 q_val = val
时,您复制的是字典的引用,您并未创建变量的副本。所以q_val和val其实是同一个字典
Assignment statements in Python do not copy objects, they create bindings between a target and an object
如果要复制 python 中的变量,请使用 copy.copy()。
q_val = copy.copy(val)
如何以线程安全的方式操作字典,我想将字典存储到 2 个具有不同字典值的不同队列(操作前 1 个,操作后 1 个)但结果是它们都在操作后存储字典。
这是我的代码
from threading import Timer, Lock
from queue import Queue
q = Queue(maxsize=10000)
k = Queue(maxsize=10000)
k_lock = Lock()
q_lock = Lock()
def write_func(x):
rows = []
while not x.empty():
rows.append(x.get())
if len(rows) == 0:
return
print('A Row is {} and total A row is {}'.format(rows, len(rows)))
def write_k(x):
rows = []
while not x.empty():
rows.append(x.get())
if len(rows) == 0:
return
print('B Row is {} and total B row is {}'.format(rows, len(rows)))
def write_caller(sec=10):
write_func(q)
Timer(sec, write_caller, [sec]).start()
def k_caller(sec=1):
write_k(k)
Timer(sec, k_caller, [sec]).start()
write_caller()
k_caller()
while True:
val = {"event": "lazada"}
k.put(val)
q_val = val
with Lock():
q_val["dt"] = "2018-04-11"
q.put(q_val)
if q.qsize() >= 10:
write_func(q)
上面代码的结果是这样的
A Row is [{'event': 'lazada', 'dt': '2018-04-11'}, ...]
B Row is [{'event': 'lazada', 'dt': '2018-04-11'}, ...]
但我希望 B 行只包含 'event' 而没有 'dt'。这就是我想要的
A Row is [{'event': 'lazada', 'dt': '2018-04-11'}, ...]
B Row is [{'event': 'lazada'}, ...]
当您执行 q_val = val
时,您复制的是字典的引用,您并未创建变量的副本。所以q_val和val其实是同一个字典
Assignment statements in Python do not copy objects, they create bindings between a target and an object
如果要复制 python 中的变量,请使用 copy.copy()。
q_val = copy.copy(val)