QtQuick 2 - 侧面板示例
QtQuick 2 - Side Panel example
有人可以帮助我理解这段代码的行为吗?我写了侧面板菜单的简单示例(现在只是模板)并且使用 onMenuVisibleChanged 插槽存在问题(但我需要的只是实际工作,只是想了解为什么另一种方式不行)。从逻辑上讲,它应该将面板矩形的 x 更改为指定值,但它没有。请帮助我理解这件事的正确方法。
main.qml
import QtQuick 2.3
import QtQuick.Controls 1.3
import QtQuick.Window 2.2
import QtQuick.Dialogs 1.2
ApplicationWindow {
title: qsTr("Hello World")
width: 640
height: 480
visible: true
menuBar: MenuBar{
Menu{
title: "File"
MenuItem{
text: "Exit"
onTriggered: Qt.quit()
}
}
}
SidePane{
id: sidePane
menuWidth: 350
z: 2
}
}
SidePane.qml
import QtQuick 2.3
import QtQuick.Window 2.2
Item {
id: screenItem
anchors.fill: parent
function show() {
rect.x = 0
menuVisible = true
}
function hide() {
rect.x = -rect.width
menuVisible = false
}
property int animationDuration: 200
property bool menuVisible: false
property int dragThreshold: 120
property int menuWidth: 300
Rectangle {
id: rect
width: menuWidth
x: -rect.width
height: Screen.height
color: "lightsteelblue"
Drag.active: menuDragArea.drag.active
Behavior on x {
NumberAnimation {
duration: animationDuration
easing.type: Easing.InOutQuad
}
}
MouseArea {
property int dragX: 0
property int startX: 0
property int diffX: 0
id: menuDragArea
hoverEnabled: true
height: rect.height
width: rect.width + 40
anchors.left: rect.left
drag.target: rect
drag.axis: Drag.XAxis
drag.minimumX: -rect.width
drag.maximumX: 0
onPressed: startX = rect.x + rect.width
onReleased: {
dragX = rect.x + rect.width
diffX = Math.abs(startX - dragX)
if ((diffX > dragThreshold) && (startX == 0)){
rect.x = 0
menuVisible = true
} else if ((diffX < dragThreshold) && (startX == 0)){
rect.x = -rect.width
menuVisible = false
}
if ((diffX > dragThreshold) && (startX == rect.width)){
rect.x = -rect.width
menuVisible = false
} else if ((diffX < dragThreshold) && (startX == rect.width)){
rect.x = 0
menuVisible = true
}
}
}
}
Rectangle{
id: shadowRect
anchors.left: rect.right
anchors.right: screenItem.right
opacity: (rect.x + rect.width) / (rect.width * 2.2)
color: "black"
height: screenItem.height
MouseArea{
id: shadowArea
anchors.fill: shadowRect
visible: menuVisible ? true : false
hoverEnabled: true
onClicked: {
if (menuVisible == true){
rect.x = -rect.width
menuVisible = false
}
}
}
Rectangle{
id: shadowRect2
color: "black"
anchors.left: parent.left
width: 5
opacity: (rect.x + rect.width) / (rect.width * 2)
height: screenItem.height
}
Rectangle{
id: shadowRect3
color: "black"
anchors.left: parent.left
width: 3
opacity: (rect.x + rect.width) / (rect.width * 1.9)
height: screenItem.height
}
}
onMenuVisibleChanged: menuVisible ? rect.x = 0 : rect.x = -rect.width
}
感谢任何帮助。只是一个 QML 初学者。最主要的目的是在 android 应用程序中使用此面板。如果需要,请随意使用此代码。
属性 drag
使 x 值可拖动
如果您通过 mouseX
onPressed/onReleased 实现它,rect.x
将是 0
或 -rect.width
onMenuVisibleChanged
MouseArea {
property int dragX: 0
property int startX: 0
property int diffX: 0
id: menuDragArea
hoverEnabled: true
height: rect.height
width: rect.width + 40
anchors.left: rect.left
onPressed: {
startX = mouseX;
console.log(rect.x)
}
onReleased: {
diffX = Math.abs(startX - mouseX)
console.log("diff:"+diffX)
if ((diffX > dragThreshold) && (mouseX > startX) && (rect.x !=0 )){
rect.x = 0
menuVisible = true
} else if ((diffX > dragThreshold) && (mouseX < startX) && (rect.x == 0)){
rect.x = -rect.width
menuVisible = false
}
}
}
视觉拖拽,不好意思丑了:
MouseArea {
property int startX: 0
property int diffX: 0
property int startRectX: 0
property bool isPressed: false
id: menuDragArea
hoverEnabled: true
height: rect.height
width: rect.width + 40
anchors.left: rect.left
onPressed: {
startX = mouseX;
startRectX = rect.x
isPressed = true
console.log(rect.x)}
onMouseXChanged: {
if(isPressed)
rect.x = (mouseX>rect.width)? 0 : (mouseX-rect.width)
}
onReleased: {
isPressed = false
diffX = Math.abs(startX - mouseX)
console.log("diff:"+diffX)
if ((mouseX >= startX) && (startRectX == -rect.width )){
if(diffX > dragThreshold)
{
rect.x = 0
menuVisible = true
}
else
rect.x = startRectX
} else if ((mouseX <= startX) && (startRectX == 0)){
if(diffX > dragThreshold)
{
rect.x = -rect.width
menuVisible = false
}
else
rect.x = startRectX
}
else
rect.x = startRectX
}
}
有人可以帮助我理解这段代码的行为吗?我写了侧面板菜单的简单示例(现在只是模板)并且使用 onMenuVisibleChanged 插槽存在问题(但我需要的只是实际工作,只是想了解为什么另一种方式不行)。从逻辑上讲,它应该将面板矩形的 x 更改为指定值,但它没有。请帮助我理解这件事的正确方法。
main.qml
import QtQuick 2.3
import QtQuick.Controls 1.3
import QtQuick.Window 2.2
import QtQuick.Dialogs 1.2
ApplicationWindow {
title: qsTr("Hello World")
width: 640
height: 480
visible: true
menuBar: MenuBar{
Menu{
title: "File"
MenuItem{
text: "Exit"
onTriggered: Qt.quit()
}
}
}
SidePane{
id: sidePane
menuWidth: 350
z: 2
}
}
SidePane.qml
import QtQuick 2.3
import QtQuick.Window 2.2
Item {
id: screenItem
anchors.fill: parent
function show() {
rect.x = 0
menuVisible = true
}
function hide() {
rect.x = -rect.width
menuVisible = false
}
property int animationDuration: 200
property bool menuVisible: false
property int dragThreshold: 120
property int menuWidth: 300
Rectangle {
id: rect
width: menuWidth
x: -rect.width
height: Screen.height
color: "lightsteelblue"
Drag.active: menuDragArea.drag.active
Behavior on x {
NumberAnimation {
duration: animationDuration
easing.type: Easing.InOutQuad
}
}
MouseArea {
property int dragX: 0
property int startX: 0
property int diffX: 0
id: menuDragArea
hoverEnabled: true
height: rect.height
width: rect.width + 40
anchors.left: rect.left
drag.target: rect
drag.axis: Drag.XAxis
drag.minimumX: -rect.width
drag.maximumX: 0
onPressed: startX = rect.x + rect.width
onReleased: {
dragX = rect.x + rect.width
diffX = Math.abs(startX - dragX)
if ((diffX > dragThreshold) && (startX == 0)){
rect.x = 0
menuVisible = true
} else if ((diffX < dragThreshold) && (startX == 0)){
rect.x = -rect.width
menuVisible = false
}
if ((diffX > dragThreshold) && (startX == rect.width)){
rect.x = -rect.width
menuVisible = false
} else if ((diffX < dragThreshold) && (startX == rect.width)){
rect.x = 0
menuVisible = true
}
}
}
}
Rectangle{
id: shadowRect
anchors.left: rect.right
anchors.right: screenItem.right
opacity: (rect.x + rect.width) / (rect.width * 2.2)
color: "black"
height: screenItem.height
MouseArea{
id: shadowArea
anchors.fill: shadowRect
visible: menuVisible ? true : false
hoverEnabled: true
onClicked: {
if (menuVisible == true){
rect.x = -rect.width
menuVisible = false
}
}
}
Rectangle{
id: shadowRect2
color: "black"
anchors.left: parent.left
width: 5
opacity: (rect.x + rect.width) / (rect.width * 2)
height: screenItem.height
}
Rectangle{
id: shadowRect3
color: "black"
anchors.left: parent.left
width: 3
opacity: (rect.x + rect.width) / (rect.width * 1.9)
height: screenItem.height
}
}
onMenuVisibleChanged: menuVisible ? rect.x = 0 : rect.x = -rect.width
}
感谢任何帮助。只是一个 QML 初学者。最主要的目的是在 android 应用程序中使用此面板。如果需要,请随意使用此代码。
属性 drag
使 x 值可拖动
如果您通过 mouseX
onPressed/onReleased 实现它,rect.x
将是 0
或 -rect.width
onMenuVisibleChanged
MouseArea {
property int dragX: 0
property int startX: 0
property int diffX: 0
id: menuDragArea
hoverEnabled: true
height: rect.height
width: rect.width + 40
anchors.left: rect.left
onPressed: {
startX = mouseX;
console.log(rect.x)
}
onReleased: {
diffX = Math.abs(startX - mouseX)
console.log("diff:"+diffX)
if ((diffX > dragThreshold) && (mouseX > startX) && (rect.x !=0 )){
rect.x = 0
menuVisible = true
} else if ((diffX > dragThreshold) && (mouseX < startX) && (rect.x == 0)){
rect.x = -rect.width
menuVisible = false
}
}
}
视觉拖拽,不好意思丑了:
MouseArea {
property int startX: 0
property int diffX: 0
property int startRectX: 0
property bool isPressed: false
id: menuDragArea
hoverEnabled: true
height: rect.height
width: rect.width + 40
anchors.left: rect.left
onPressed: {
startX = mouseX;
startRectX = rect.x
isPressed = true
console.log(rect.x)}
onMouseXChanged: {
if(isPressed)
rect.x = (mouseX>rect.width)? 0 : (mouseX-rect.width)
}
onReleased: {
isPressed = false
diffX = Math.abs(startX - mouseX)
console.log("diff:"+diffX)
if ((mouseX >= startX) && (startRectX == -rect.width )){
if(diffX > dragThreshold)
{
rect.x = 0
menuVisible = true
}
else
rect.x = startRectX
} else if ((mouseX <= startX) && (startRectX == 0)){
if(diffX > dragThreshold)
{
rect.x = -rect.width
menuVisible = false
}
else
rect.x = startRectX
}
else
rect.x = startRectX
}
}