当它变为零时如何隐藏计数器天数？

Question

我有一个显示 0 的计数器，我想在它变为 0 时隐藏它。因此，如果计数器显示（0 天 6 小时 25 分钟），我希望它是（6 小时 25 分钟），只需将其隐藏在 0... 这是我的代码：

<!DOCTYPE HTML>
<html>
<head>
<meta name="viewport" content="width=device-width, initial-scale=1">
<style>
p {
  text-align: center;
  font-size: 60px;
  margin-top:0px;
}
</style>
</head>
<body>

<p id="demo"></p>

<script>
// Set the date we're counting down to
var countDownDate = new Date("April 12, 2018 15:37:25").getTime();

// Update the count down every 1 second
var x = setInterval(function() {

    // Get todays date and time
    var now = new Date().getTime();
    
    // Find the distance between now an the count down date
    var distance = countDownDate - now;
    
    // Time calculations for days, hours, minutes and seconds
    var days = Math.floor(distance / (1000 * 60 * 60 * 24));
    var hours = Math.floor((distance % (1000 * 60 * 60 * 24)) / (1000 * 60 * 60));
    var minutes = Math.floor((distance % (1000 * 60 * 60)) / (1000 * 60));
    var seconds = Math.floor((distance % (1000 * 60)) / 1000);
    
    // Output the result in an element with id="demo"
    document.getElementById("demo").innerHTML = days + "d " + hours + "h "
    + minutes + "m " + seconds + "s ";
    
    // If the count down is over, write some text 
    if (distance < 0) {
        clearInterval(x);
        document.getElementById("demo").innerHTML = "EXPIRED";
    }
}, 1000);
</script>

</body>
</html>

感谢您的帮助

Answer 1

你可以检查什么时候days === 0然后填空

days = days === 0 ? '' : days + "d "

// Output the result in an element with id="demo"
    document.getElementById("demo").innerHTML = days + hours + "h "
    + minutes + "m " + seconds + "s ";

与小时和分钟相同

Answer 2

您可以使用三元运算符来检查天数是否 == 0

document.getElementById("demo").innerHTML = ((days) ? days + "d " : '') + hours + "h " + minutes + "m " + seconds + "s ";

<!DOCTYPE HTML>
<html>
<head>
<meta name="viewport" content="width=device-width, initial-scale=1">
<style>
p {
  text-align: center;
  font-size: 60px;
  margin-top:0px;
}
</style>
</head>
<body>

<p id="demo"></p>

<script>
// Set the date we're counting down to
var countDownDate = new Date("April 12, 2018 15:37:25").getTime();

// Update the count down every 1 second
var x = setInterval(function() {

    // Get todays date and time
    var now = new Date().getTime();
    
    // Find the distance between now an the count down date
    var distance = countDownDate - now;
    
    // Time calculations for days, hours, minutes and seconds
    var days = Math.floor(distance / (1000 * 60 * 60 * 24));
    var hours = Math.floor((distance % (1000 * 60 * 60 * 24)) / (1000 * 60 * 60));
    var minutes = Math.floor((distance % (1000 * 60 * 60)) / (1000 * 60));
    var seconds = Math.floor((distance % (1000 * 60)) / 1000);
    
    // Output the result in an element with id="demo"
    document.getElementById("demo").innerHTML = ((days) ? days + "d " : '') + hours + "h "
    + minutes + "m " + seconds + "s ";
    
    // If the count down is over, write some text 
    if (distance < 0) {
        clearInterval(x);
        document.getElementById("demo").innerHTML = "EXPIRED";
    }
}, 1000);
</script>

</body>
</html>

Answer 3

您可以通过document.getElementById("demo").innerHTML设置更改时间的条件，

(days === 0 ? '' : days + "d ") +
(hours === 0 ? '' : hours + "h ")+
(minutes === 0 ? '' : minutes + "m ")+ 
 seconds + "s ";

这将检查 days、hours 和 minutes 的零值并在 HTML、

中分配 null

// Set the date we're counting down to
var countDownDate = new Date("April 12, 2018 15:37:25").getTime();
// Update the count down every 1 second
var x = setInterval(function() {

    // Get todays date and time
    var now = new Date().getTime();
    
    // Find the distance between now an the count down date
    var distance = countDownDate - now;
    
    // Time calculations for days, hours, minutes and seconds
    var days = Math.floor(distance / (1000 * 60 * 60 * 24));
    var hours = Math.floor((distance % (1000 * 60 * 60 * 24)) / (1000 * 60 * 60));
    var minutes = Math.floor((distance % (1000 * 60 * 60)) / (1000 * 60));
    var seconds = Math.floor((distance % (1000 * 60)) / 1000);
    
    // Output the result in an element with id="demo"
    document.getElementById("demo").innerHTML = 
    (days === 0 ? '' : days + "d ") +
    (hours === 0 ? '' : hours + "h ")+
    (minutes === 0 ? '' : minutes + "m ")+ 
     seconds + "s ";
    
    // If the count down is over, write some text 
    if (distance < 0) {
        clearInterval(x);
        document.getElementById("demo").innerHTML = "EXPIRED";
    }
}, 1000);

p {
  text-align: center;
  font-size: 60px;
  margin-top:0px;
}

<p id="demo"></p>

Answer 4

如果您想对所有输出执行此操作并显示类似 1d 0h 52m 0s 而不是 1d 52m 的内容，那么逻辑应该类似于：

// Output the result in an element with id="demo"
document.getElementById("demo").innerHTML = 
                         ((!days) ? '' : days + "d ") + 
                         ((!days && !hours) ? '' : hours + "h ") +
                         ((!days && !hours && !minutes) ? '' : minutes + "m ") + 
                         ((!days && !hours && !minutes && !seconds) ? '' : seconds + "s ";

这样 0d 0h 52m 0s 这样的时间会像 52m 0s

当它变为零时如何隐藏计数器天数？

How can i hide counter days when it gets zero?

javascript

timer

countdown