如何计算 Swift 中给定文本中的句子数？

Question

我想创建一个 playground 来计算给定文本的句子数量。

let input = "That would be the text . it hast 3. periods. "

func sentencecount() {
    let periods = CharacterSet.whitespacesAndNewlines.union(.punctuationCharacters)
    let periods = input.components(separatedBy: spaces)
    let periods2  = Int (words.count)
    print ("The Average Sentence length is \(periods2)") 
}
sentencecount()

Answer 1

这应该有效：

   let input = "That would be the text . it hast 3. periods. "
   let occurrencies = input.characters.filter { [=10=] == "." || [=10=] == "?" }.count
   print(occurrencies)
   //result 3

Answer 2

只需在 charset 中添加您要用来区分句子的字符：

我现在假设 ? . ,：

    let input = "That would be the text. it hast 3? periods."
    let charset = CharacterSet(charactersIn: ".?,")
    let arr = input.components(separatedBy: charset)
    let count = arr.count - 1

此处 arr 将是：

["That would be the text", " it hast 3", " periods", ""]

将计数减 1，以获得实际句子。

注意：如果你不想考虑" , "那么把它从charset.

中去掉

Answer 3

据我所知，您需要使用 .并修剪空格如下：

func sentencecount () {

    let result = input.trimmingCharacters(in: .whitespaces).split(separator: ".")

   print ("The Average Sentence length is \(result.count)") // 3
}

祝你好运！

Answer 4

您可以使用 enumerateSubstrings(in: Range) 并使用选项 .bySentences:

let input = "Hello World !!! That would be the text. It hast 3 periods."
var sentences: [String] = []
input.enumerateSubstrings(in: input.startIndex..., options: .bySentences) { (string, range, enclosingRamge, stop) in
    sentences.append(string!)
}

另一种方法是使用子字符串数组而不是字符串：

var sentences: [Substring] = []
input.enumerateSubstrings(in: input.startIndex..., options: .bySentences) { (string, range, enclosingRamge, stop) in
    sentences.append(input[range])
}

print(sentences)   // "["Hello World !!! ", "That would be the text. ", "It hast 3 periods."]\n"
print(sentences.count)  // "3\n"

如何计算 Swift 中给定文本中的句子数？

How can I count the number of sentences in a given text in Swift?

string

count

sentence

swift