对文件中的某些信息进行排序

Question

我正在制作一个程序，以最高分的字母顺序对文件进行排序。该文件有 4 个这样的名称，用制表符分隔：

Jeff    12    17    16
Dan     23    21   18
John    12    10   20
Mary    13    24   24

这是我的代码：

with open("file.txt","r") as f:
    lines = f.readlines()
    lines.sort()
    fields = [line.split() for line in f]
    name, grades = fields[0], fields[1:]
    grades = [int(grade) for grade in grades]
    grades.sort()
    highest = max(grades)
with open('file.txt','w') as fout:
    for el in lines:
        fout.write('{0}\n'.format(' '.join(el)))
with open('file.txt','r') as fsort:
    for line in fsort:
        print(line[:-1])
    fsort.close()

我不断收到列表值超出范围等错误；对于场线。谁能给我一个解决方案，让这段代码有效？

Answer 1

您需要使用 fields = [line.split() for line in lines]，而不是 in f。当调用 f.readlines() 时，文件指针最终移动到末尾，这意味着 fields 是一个空列表。

但是，我感觉 name, grades = fields[0], fields[1:] 不会按照您的意愿去做。以下内容应确保 name 和 grades 存储您想要的内容（根据提问者的要求进行大量编辑）：

with open("class6Afile.txt","r") as f:
    lines = f.readlines()
lines.sort()
with open('class6AfileOut.txt','w') as fout:
    for line in lines:
        fields = line.split()
        name, grades = fields[0], fields[1:]
        grades = [int(grade) for grade in grades]
        grades.sort()
        highest = max(grades)
        grades = [str(grade) for grade in grades]
        print name, grades
        fout.write('{0} {1}\n'.format(name, ' '.join(grades)))

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