具有延迟的异步 return - IllegalMonitorStateException
Async return with delay - IllegalMonitorStateException
我正在尝试在新线程中调用方法,该方法将 return 使用可调用延迟后的内容。由于 IllegalMonitorStateException 而下降
是否有可能以这种方式封装线程服务,当我只创建 class 的实例时,调用方法并且该方法将延迟 return 对象?
提前谢谢你。
// ENTITY
public class Result {
public String name;
public int value;
public Result(String name, int value) {
this.name = name;
this.value = value;
}
public Result() {
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getValue() {
return value;
}
public void setValue(int value) {
this.value = value;
}
@Override
public String toString() {
return "Result{" +
"name='" + name + '\'' +
", value=" + value +
'}';
}
}
创建具有延迟和 return 值的线程
import java.util.concurrent.*;
public class AsyncCallable {
public Result calculate() throws ExecutionException, InterruptedException {
int delay = 5000;
ExecutorService executorService = Executors.newSingleThreadExecutor();
Callable<Result> callable = () -> {
this.wait(delay);
return new Result("Name", 4);
};
Future<Result> future = executorService.submit(callable);
executorService.shutdown();
return future.get();
}
}
调用方式:
import java.util.concurrent.ExecutionException;
public class Main {
public static void main(String[] args) throws ExecutionException, InterruptedException {
AsyncCallable asyncCallable = new AsyncCallable();
System.out.println(asyncCallable.calculate().toString());
}
}
因为你的 ExecutorService
只使用一个线程,所以只调用 Thread#sleep
而不是 Object#wait
:
应该没问题
Callable<Result> callable = () -> {
Thread.sleep(5_000);
return new Result("Name", 4);
};
嗯,为了坚持你的情况,任何对 wait() 的调用都必须包含在同步块中(参见方法 javadoc here). But, I think you should consider using built-in tools, like Scheduled thread pool。使用它,你可以执行以下操作:
import java.util.concurrent.ScheduledThreadPoolExecutor;
import java.util.concurrent.Executors;
final ScheduledExecutorService scheduler = Executors.newScheduledThreadPool(4);
// Execute a task after 5 seconds
scheduler.schedule(() -> new Result("Name", 4), 5, TimeUnit.SECONDS);
我正在尝试在新线程中调用方法,该方法将 return 使用可调用延迟后的内容。由于 IllegalMonitorStateException 而下降 是否有可能以这种方式封装线程服务,当我只创建 class 的实例时,调用方法并且该方法将延迟 return 对象? 提前谢谢你。
// ENTITY
public class Result {
public String name;
public int value;
public Result(String name, int value) {
this.name = name;
this.value = value;
}
public Result() {
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getValue() {
return value;
}
public void setValue(int value) {
this.value = value;
}
@Override
public String toString() {
return "Result{" +
"name='" + name + '\'' +
", value=" + value +
'}';
}
}
创建具有延迟和 return 值的线程
import java.util.concurrent.*;
public class AsyncCallable {
public Result calculate() throws ExecutionException, InterruptedException {
int delay = 5000;
ExecutorService executorService = Executors.newSingleThreadExecutor();
Callable<Result> callable = () -> {
this.wait(delay);
return new Result("Name", 4);
};
Future<Result> future = executorService.submit(callable);
executorService.shutdown();
return future.get();
}
}
调用方式:
import java.util.concurrent.ExecutionException;
public class Main {
public static void main(String[] args) throws ExecutionException, InterruptedException {
AsyncCallable asyncCallable = new AsyncCallable();
System.out.println(asyncCallable.calculate().toString());
}
}
因为你的 ExecutorService
只使用一个线程,所以只调用 Thread#sleep
而不是 Object#wait
:
Callable<Result> callable = () -> {
Thread.sleep(5_000);
return new Result("Name", 4);
};
嗯,为了坚持你的情况,任何对 wait() 的调用都必须包含在同步块中(参见方法 javadoc here). But, I think you should consider using built-in tools, like Scheduled thread pool。使用它,你可以执行以下操作:
import java.util.concurrent.ScheduledThreadPoolExecutor;
import java.util.concurrent.Executors;
final ScheduledExecutorService scheduler = Executors.newScheduledThreadPool(4);
// Execute a task after 5 seconds
scheduler.schedule(() -> new Result("Name", 4), 5, TimeUnit.SECONDS);