使用字符串变量在 R 函数中传递多个变量信息
Passing multiple variable information inside R functions using string variable
这是一个可重现的例子
#install.packages("expss")
library("expss")
data(mtcars)
mtcars = apply_labels(mtcars,
mpg = "Miles/(US) gallon",
cyl = "Number of cylinders",
disp = "Displacement (cu.in.)",
hp = "Gross horsepower",
drat = "Rear axle ratio",
wt = "Weight (1000 lbs)",
qsec = "1/4 mile time",
vs = "Engine",
vs = c("V-engine" = 0,
"Straight engine" = 1),
am = "Transmission",
am = c("Automatic" = 0,
"Manual"=1),
gear = "Number of forward gears",
carb = "Number of carburetors"
)
mtcars %>%
tab_cols(total(),vs,gear) %>%
tab_cells(gear) %>%
tab_stat_cpct(total_row_position = "none", label = "col %") %>%
tab_pivot(stat_position = "inside_rows")
根据我的情况,我想动态传递 tab_cols(total(),vs,gear) 中的变量信息。因此,为了便于使用,假设我想评估如下函数:
var1 <- "vs, gear"
mtcars %>%
tab_cols(total(),var1) %>%
tab_cells(gear) %>%
tab_stat_cpct(total_row_position = "none", label = "col %") %>%
tab_pivot(stat_position = "inside_rows")
显然会出错!!我知道只适用于单个参数的惰性评估。因此尝试了很多在多个论坛上搜索但没有运气。
所以,一个好的方法可能是:
var1 <- "vs"
var2 <- "gear"
mtcars %>%
tab_cols(total(),eval(parse(text = var1)),eval(parse(text = var2))) %>%
tab_cells(gear) %>%
tab_stat_cpct(total_row_position = "none", label = "col %") %>%
tab_pivot(stat_position = "inside_rows")
但我想用单个变量(它会以字符串或向量形式包含变量信息)来实现这一点,因为该变量可能存储超过 3 或 4 列信息。
文档 table_cols
说您可以传递列名列表。所以这似乎可以满足您的要求:
vars <- expression(list(vs, gear))
mtcars %>%
tab_cols(total(), eval(vars)) %>%
tab_cells(gear) %>%
tab_stat_cpct(total_row_position = "none", label = "col %") %>%
tab_pivot(stat_position = "inside_rows")
expss中有一个特殊的参数传递工具:
var1 <- "vs, gear"
var_names = trimws(unlist(strsplit(var1, split = ",")))
mtcars %>%
tab_cols(total(), ..[(var_names)]) %>%
tab_cells(gear) %>%
tab_stat_cpct(total_row_position = "none", label = "col %") %>%
tab_pivot(stat_position = "inside_rows")
免责声明:我是 expss 包的作者。
这是一个可重现的例子
#install.packages("expss")
library("expss")
data(mtcars)
mtcars = apply_labels(mtcars,
mpg = "Miles/(US) gallon",
cyl = "Number of cylinders",
disp = "Displacement (cu.in.)",
hp = "Gross horsepower",
drat = "Rear axle ratio",
wt = "Weight (1000 lbs)",
qsec = "1/4 mile time",
vs = "Engine",
vs = c("V-engine" = 0,
"Straight engine" = 1),
am = "Transmission",
am = c("Automatic" = 0,
"Manual"=1),
gear = "Number of forward gears",
carb = "Number of carburetors"
)
mtcars %>%
tab_cols(total(),vs,gear) %>%
tab_cells(gear) %>%
tab_stat_cpct(total_row_position = "none", label = "col %") %>%
tab_pivot(stat_position = "inside_rows")
根据我的情况,我想动态传递 tab_cols(total(),vs,gear) 中的变量信息。因此,为了便于使用,假设我想评估如下函数:
var1 <- "vs, gear"
mtcars %>%
tab_cols(total(),var1) %>%
tab_cells(gear) %>%
tab_stat_cpct(total_row_position = "none", label = "col %") %>%
tab_pivot(stat_position = "inside_rows")
显然会出错!!我知道只适用于单个参数的惰性评估。因此尝试了很多在多个论坛上搜索但没有运气。
所以,一个好的方法可能是:
var1 <- "vs"
var2 <- "gear"
mtcars %>%
tab_cols(total(),eval(parse(text = var1)),eval(parse(text = var2))) %>%
tab_cells(gear) %>%
tab_stat_cpct(total_row_position = "none", label = "col %") %>%
tab_pivot(stat_position = "inside_rows")
但我想用单个变量(它会以字符串或向量形式包含变量信息)来实现这一点,因为该变量可能存储超过 3 或 4 列信息。
文档 table_cols
说您可以传递列名列表。所以这似乎可以满足您的要求:
vars <- expression(list(vs, gear))
mtcars %>%
tab_cols(total(), eval(vars)) %>%
tab_cells(gear) %>%
tab_stat_cpct(total_row_position = "none", label = "col %") %>%
tab_pivot(stat_position = "inside_rows")
expss中有一个特殊的参数传递工具:
var1 <- "vs, gear"
var_names = trimws(unlist(strsplit(var1, split = ",")))
mtcars %>%
tab_cols(total(), ..[(var_names)]) %>%
tab_cells(gear) %>%
tab_stat_cpct(total_row_position = "none", label = "col %") %>%
tab_pivot(stat_position = "inside_rows")
免责声明:我是 expss 包的作者。