对 SHA1 哈希的字典攻击

Question

以下是我的代码。我一直在尝试修复代码以对哈希 (SHA-1) 执行字典攻击，我得到以下结果。 P.S。我是编码初学者。

import hashlib
import random
#plug in the hash that needs to be cracked
hash_to_crack = "5baa61e4c9b93f3f0682250b6cf8331b7ee68fd8"
#direct the location of the dictionary file
dict_file = "C:/Users/kiran/AppData/Local/Programs/Python/Python37/dictionary.txt"

def main():
    with open(dict_file) as fileobj:
        for line in fileobj:
            line = line.strip()
            if hashlib.sha1(line.encode()).hexdigest() == hash_to_crack:
                print ("The password is %s") % (line);
                return ""
    print ("Failed to crack the hash!")
    return ""


if __name__ == "__main__":
    main()

结果：

RESTART: C:/Users/kiran/AppData/Local/Programs/Python/Python37/Codes/datest1.py
The password is %s
Traceback (most recent call last):
  File "C:/Users/kiran/AppData/Local/Programs/Python/Python37/Codes/datest1.py", line 20, in <module>
    main()
  File "C:/Users/kiran/AppData/Local/Programs/Python/Python37/Codes/datest1.py", line 13, in main
    print ("The password is %s") % (line);
TypeError: unsupported operand type(s) for %: 'NoneType' and 'str'

Answer 1

此行无效 python3 语法：（编辑：这是一个有效的语法！但不是您想要的:)）

print ("The password is %s") % (line);

改用这个：

print ("The password is %s" % line)

此外，根据错误信息，行可能是None。

Answer 2

您正在使用 Python 3，其中 print 是一个函数。该行：

print ("The password is %s") % (line)

使用参数 "The password is %s" 调用函数 print。函数 returns None。然后 None % (line) 给出您看到的错误消息。

最惯用的方式是这样写：

print("The password is", line)

其他可行的方法：

print("The password is %s" % line)
print(("The password is %s") % (line))

对 SHA1 哈希的字典攻击

Dictionary attack on SHA1 hash

python

hash

sha1

dictionary-attack