Unreachable Statement是什么意思
What is the meaning of Unreacheable Statement
它说 "int addition = t+r;" 是一个无法访问的语句。那是什么意思?如何纠正?
public class parseMETHOD {
public static void main(String[] args) {
int a=9;
int b=45;
int result=calFunction(a,b);
System.out.println(result);
}
private static int calFunction(int t,int r) {
throw new UnsupportedOperationException("Not supported yet."); //To change body of generated methods, choose Tools |
Templates.
int addition = t+r;
return addition;
} }
由于程序的某些控制,该语句在逻辑上不可访问
流动。您正在抛出未在您的函数中捕获的异常。
请删除throw语句和单词"Template"
public class parseMETHOD {
public static void main(String[] args) {
int a=9;
int b=45;
int result=calFunction(a,b);
System.out.println(result);
}
private static int calFunction(int t,int r) {
int addition = t+r;
return addition;
}
}
此外,良好的命名约定规定您应该将 class 个名称大写。
它说 "int addition = t+r;" 是一个无法访问的语句。那是什么意思?如何纠正?
public class parseMETHOD {
public static void main(String[] args) {
int a=9;
int b=45;
int result=calFunction(a,b);
System.out.println(result);
}
private static int calFunction(int t,int r) {
throw new UnsupportedOperationException("Not supported yet."); //To change body of generated methods, choose Tools |
Templates.
int addition = t+r;
return addition;
} }
由于程序的某些控制,该语句在逻辑上不可访问 流动。您正在抛出未在您的函数中捕获的异常。
请删除throw语句和单词"Template"
public class parseMETHOD {
public static void main(String[] args) {
int a=9;
int b=45;
int result=calFunction(a,b);
System.out.println(result);
}
private static int calFunction(int t,int r) {
int addition = t+r;
return addition;
}
}
此外,良好的命名约定规定您应该将 class 个名称大写。