解析 Wiley 在线图书馆

Question

我想从 Ullmann's Encyclopedia of Industrial Chemistry 和 Python 和 BeautifulSoup 中提取所有章节的 DOI。

所以从

<h2 class="meta__title meta__title__margin"><span class="hlFld-Title"><a href="/doi/10.1002/14356007.c01_c01.pub2">Aerogels</a></span></h2>

我想得到 "Aerogels" 和“/doi/full/10.1002/14356007.c01_c01.pub2”

更大的样本：

     <ul class="chapter_meta meta__authors rlist--inline comma">
        <li><span class="hlFld-ContribAuthor"><a href="/action/doSearch?ContribAuthorStored=H%C3%BCsing%2C+Nicola"><span>Nicola Hüsing</span></a></span></li>
        <li><span class="hlFld-ContribAuthor"><a href="/action/doSearch?ContribAuthorStored=Schubert%2C+Ulrich"><span>Ulrich Schubert</span></a></span></li>
     </ul><span class="meta__epubDate"><span>First published: </span>15 December 2006</span><div class="content-item-format-links">
        <ul class="rlist--inline separator">
           <li><a title="Abstract" href="/doi/abs/10.1002/14356007.c01_c01.pub2">Abstract</a></li>
           <li><a title="Full text" href="/doi/full/10.1002/14356007.c01_c01.pub2">
                 Full text
                 </a></li>

我试过的标题：

span['hlFld-Title'].a

我试过的 DOI：

for link in soup.find_all('a'.title):
    print(link.get('href'))

但遗憾的是我是一个十足的菜鸟（傻瓜）而且它不起作用。

网址是 https://onlinelibrary.wiley.com/browse/book/10.1002/14356007/title?startPage={1..59}

感谢您的帮助。

Answer 1

这是一个快速解决方案，将 "DOI;title" 对打印到命令行：

import requests
from bs4 import BeautifulSoup

for i in range(59):
    page = requests.get("https://onlinelibrary.wiley.com/browse/book/10.1002/14356007/title?startPage={}".format(i))

    soup = BeautifulSoup(page.content, 'lxml')

    content = soup.findAll("span", class_="hlFld-Title")

    for c in content:
        print(c.a.get('href')+";"+c.get_text())

解析 Wiley 在线图书馆

Parse Wiley Online Library

python

web-scraping

beautifulsoup

doi