C#中两个日期之间的周差
Week difference between 2 dates in C#
我正在尝试在 C# 中创建一个函数,return是两个日期之间的周差。它的目标是提供相同的结果:
select datediff(ww,'2018-04-13','2018-04-16') as diff
在上面的例子中,这些日期之间只有 3 天,但它们在不同的星期,所以结果应该是 1。
我尝试使用 .TotalDays
,但它无法正常工作。我也试过 .GetWeekOfYear
但当日期年份不同时它不会 return 正确。我在 Whosebug 和其他论坛上似乎遇到了很多问题,到目前为止,none 个问题与我的情况相符。这是我正在尝试的功能:
public static int GetWeekDiff(DateTime dtStart, DateTime dtEnd) {
// Doesn't work
var val = ((dtEnd - dtStart).TotalDays / 7);
val = Math.Ceiling(val);
return Convert.ToInt32(val);
// Doesn't work well between years
DateTimeFormatInfo dinfo = DateTimeFormatInfo.CurrentInfo;
var x = dinfo.Calendar.GetWeekOfYear(dtStart, CalendarWeekRule.FirstFullWeek, DayOfWeek.Monday);
var y = dinfo.Calendar.GetWeekOfYear(dtEnd, CalendarWeekRule.FirstFullWeek, DayOfWeek.Monday);
return y - x;
}
在函数的第一部分,我尝试了 this post 中描述的内容。没用
你能帮帮我吗?
提前致谢。
也许它可以帮助
public static int GetIso8601WeekOfYear(DateTime time)
{
// Seriously cheat. If its Monday, Tuesday or Wednesday, then it'll
// be the same week# as whatever Thursday, Friday or Saturday are,
// and we always get those right
DayOfWeek day = CultureInfo.InvariantCulture.Calendar.GetDayOfWeek(time);
if (day >= DayOfWeek.Monday && day <= DayOfWeek.Wednesday)
{
time = time.AddDays(3);
}
// Return the week of our adjusted day
return CultureInfo.InvariantCulture.Calendar.GetWeekOfYear(time, CalendarWeekRule.FirstFourDayWeek, DayOfWeek.Monday);
}
Get the correct week number of a given date
看看这是否有效。可能还有更多未涵盖的用例,解决方案取决于您如何定义周边界(根据上面的评论假设周日至周一)。
// Output:
// Weeks between 12/28/2017 and 1/10/2018: 2
// Weeks between 4/13/2018 and 4/16/2018: 1
// Weeks between 4/21/2018 and 4/22/2018: 0
// Weeks between 4/22/2018 and 4/23/2018: 1
void Main()
{
var datePairs = new List<KeyValuePair<DateTime, DateTime>>();
datePairs.Add(new KeyValuePair<DateTime, DateTime>(new DateTime(2017, 12, 28), new DateTime(2018, 1, 10)));
datePairs.Add(new KeyValuePair<DateTime, DateTime>(new DateTime(2018, 4, 13), new DateTime(2018, 4, 16)));
datePairs.Add(new KeyValuePair<DateTime, DateTime>(new DateTime(2018, 4, 21), new DateTime(2018, 4, 22)));
datePairs.Add(new KeyValuePair<DateTime, DateTime>(new DateTime(2018, 4, 22), new DateTime(2018, 4, 23)));
foreach (var datePair in datePairs)
{
var string1 = datePair.Key.ToShortDateString();
var string2 = datePair.Value.ToShortDateString();
Console.WriteLine($"Weeks between {string1} and {string2}: {GetWeekDiff(datePair.Key, datePair.Value)}");
}
}
public static int GetWeekDiff(DateTime dtStart, DateTime dtEnd)
{
var totalDays = (dtEnd - dtStart).TotalDays;
var weeks = (int)totalDays / 7;
var hasRemainder = totalDays % 7 > 0;
if (hasRemainder)
{
if (!(dtStart.DayOfWeek.Equals(DayOfWeek.Saturday) && dtEnd.DayOfWeek.Equals(DayOfWeek.Sunday)))
{
weeks++;
}
}
return weeks;
}
首先计算两个日期之间有多少天。将天数除以 7 得到整周。
现在,通过计算天数对 7 的模数得到任何剩余天数,来计算是否有额外的一周要计算。如果第一个日期加上剩余天数在不同的一周内,则在计数上多加一周。
void Main()
{
var first = new DateTime(2018, 04, 13);
var second = new DateTime(2018, 04, 16);
Console.WriteLine(weekDiff(first, second));
}
public int weekDiff(DateTime d1, DateTime d2, DayOfWeek startOfWeek = DayOfWeek.Monday)
{
var diff = d2.Subtract(d1);
var weeks = (int)diff.Days / 7;
// need to check if there's an extra week to count
var remainingDays = diff.Days % 7;
var cal = CultureInfo.InvariantCulture.Calendar;
var d1WeekNo = cal.GetWeekOfYear(d1, CalendarWeekRule.FirstFullWeek, startOfWeek);
var d1PlusRemainingWeekNo = cal.GetWeekOfYear(d1.AddDays(remainingDays), CalendarWeekRule.FirstFullWeek, startOfWeek);
if (d1WeekNo != d1PlusRemainingWeekNo)
weeks++;
return weeks;
}
还不能发表评论,并且已经在这个 post 我认为相似的东西上使用了标记。这是另一个 post 我发现它似乎与您尝试创建的解决方案一致:
static void Main(string[] args)
{
DateTime date1 = new DateTime(2018, 04, 18);
DateTime date2 = new DateTime(2018, 04, 19);
System.Console.WriteLine((GetDiff(new DateTime(2018, 04, 18), new DateTime(2018, 04, 18)))); // 0
System.Console.WriteLine((GetDiff(new DateTime(2018, 04, 22), new DateTime(2018, 04, 23)))); // 1
System.Console.WriteLine((GetDiff(new DateTime(2018, 04, 16), new DateTime(2018, 04, 22)))); // 0
System.Console.WriteLine((GetDiff(new DateTime(2018, 04, 18), new DateTime(2018, 05, 03)))); // 2
}
private static int GetDiff(DateTime date1, DateTime date2)
{
date1 = SetDayToMonday(date1);
date2 = SetDayToMonday(date2);
return (int)((date2 - date1).TotalDays / 7);
}
private static DateTime SetDayToMonday(DateTime date)
{
var weekDay = date.DayOfWeek;
if (weekDay == DayOfWeek.Sunday)
return date.AddDays(-6);
else
return date.AddDays(-((int)weekDay-1));
}
首先,将日期设置为本周的星期一。然后计算所有完整周数(= /7
天作为整数)。尽管很简单,但它可能会持续数周和数年。
这是我解决类似问题的实现,我没有进行彻底测试,但它似乎可以工作。
var dt1 = DateTime.Today.AddDays(-30);
var dt2 = DateTime.Today;
var noOfDays =(int) (dt2 - dt1).TotalDays;
int reminder;
var weeks = Math.DivRem(noOfDays, 7, out reminder);
weeks = reminder > 0 ? weeks + 1 : weeks;
它 returns 1 周 6 天或更短的间隔,这正是我所需要的。
我正在尝试在 C# 中创建一个函数,return是两个日期之间的周差。它的目标是提供相同的结果:
select datediff(ww,'2018-04-13','2018-04-16') as diff
在上面的例子中,这些日期之间只有 3 天,但它们在不同的星期,所以结果应该是 1。
我尝试使用 .TotalDays
,但它无法正常工作。我也试过 .GetWeekOfYear
但当日期年份不同时它不会 return 正确。我在 Whosebug 和其他论坛上似乎遇到了很多问题,到目前为止,none 个问题与我的情况相符。这是我正在尝试的功能:
public static int GetWeekDiff(DateTime dtStart, DateTime dtEnd) {
// Doesn't work
var val = ((dtEnd - dtStart).TotalDays / 7);
val = Math.Ceiling(val);
return Convert.ToInt32(val);
// Doesn't work well between years
DateTimeFormatInfo dinfo = DateTimeFormatInfo.CurrentInfo;
var x = dinfo.Calendar.GetWeekOfYear(dtStart, CalendarWeekRule.FirstFullWeek, DayOfWeek.Monday);
var y = dinfo.Calendar.GetWeekOfYear(dtEnd, CalendarWeekRule.FirstFullWeek, DayOfWeek.Monday);
return y - x;
}
在函数的第一部分,我尝试了 this post 中描述的内容。没用
你能帮帮我吗? 提前致谢。
也许它可以帮助
public static int GetIso8601WeekOfYear(DateTime time)
{
// Seriously cheat. If its Monday, Tuesday or Wednesday, then it'll
// be the same week# as whatever Thursday, Friday or Saturday are,
// and we always get those right
DayOfWeek day = CultureInfo.InvariantCulture.Calendar.GetDayOfWeek(time);
if (day >= DayOfWeek.Monday && day <= DayOfWeek.Wednesday)
{
time = time.AddDays(3);
}
// Return the week of our adjusted day
return CultureInfo.InvariantCulture.Calendar.GetWeekOfYear(time, CalendarWeekRule.FirstFourDayWeek, DayOfWeek.Monday);
}
Get the correct week number of a given date
看看这是否有效。可能还有更多未涵盖的用例,解决方案取决于您如何定义周边界(根据上面的评论假设周日至周一)。
// Output:
// Weeks between 12/28/2017 and 1/10/2018: 2
// Weeks between 4/13/2018 and 4/16/2018: 1
// Weeks between 4/21/2018 and 4/22/2018: 0
// Weeks between 4/22/2018 and 4/23/2018: 1
void Main()
{
var datePairs = new List<KeyValuePair<DateTime, DateTime>>();
datePairs.Add(new KeyValuePair<DateTime, DateTime>(new DateTime(2017, 12, 28), new DateTime(2018, 1, 10)));
datePairs.Add(new KeyValuePair<DateTime, DateTime>(new DateTime(2018, 4, 13), new DateTime(2018, 4, 16)));
datePairs.Add(new KeyValuePair<DateTime, DateTime>(new DateTime(2018, 4, 21), new DateTime(2018, 4, 22)));
datePairs.Add(new KeyValuePair<DateTime, DateTime>(new DateTime(2018, 4, 22), new DateTime(2018, 4, 23)));
foreach (var datePair in datePairs)
{
var string1 = datePair.Key.ToShortDateString();
var string2 = datePair.Value.ToShortDateString();
Console.WriteLine($"Weeks between {string1} and {string2}: {GetWeekDiff(datePair.Key, datePair.Value)}");
}
}
public static int GetWeekDiff(DateTime dtStart, DateTime dtEnd)
{
var totalDays = (dtEnd - dtStart).TotalDays;
var weeks = (int)totalDays / 7;
var hasRemainder = totalDays % 7 > 0;
if (hasRemainder)
{
if (!(dtStart.DayOfWeek.Equals(DayOfWeek.Saturday) && dtEnd.DayOfWeek.Equals(DayOfWeek.Sunday)))
{
weeks++;
}
}
return weeks;
}
首先计算两个日期之间有多少天。将天数除以 7 得到整周。
现在,通过计算天数对 7 的模数得到任何剩余天数,来计算是否有额外的一周要计算。如果第一个日期加上剩余天数在不同的一周内,则在计数上多加一周。
void Main()
{
var first = new DateTime(2018, 04, 13);
var second = new DateTime(2018, 04, 16);
Console.WriteLine(weekDiff(first, second));
}
public int weekDiff(DateTime d1, DateTime d2, DayOfWeek startOfWeek = DayOfWeek.Monday)
{
var diff = d2.Subtract(d1);
var weeks = (int)diff.Days / 7;
// need to check if there's an extra week to count
var remainingDays = diff.Days % 7;
var cal = CultureInfo.InvariantCulture.Calendar;
var d1WeekNo = cal.GetWeekOfYear(d1, CalendarWeekRule.FirstFullWeek, startOfWeek);
var d1PlusRemainingWeekNo = cal.GetWeekOfYear(d1.AddDays(remainingDays), CalendarWeekRule.FirstFullWeek, startOfWeek);
if (d1WeekNo != d1PlusRemainingWeekNo)
weeks++;
return weeks;
}
还不能发表评论,并且已经在这个 post 我认为相似的东西上使用了标记。这是另一个 post 我发现它似乎与您尝试创建的解决方案一致:
static void Main(string[] args)
{
DateTime date1 = new DateTime(2018, 04, 18);
DateTime date2 = new DateTime(2018, 04, 19);
System.Console.WriteLine((GetDiff(new DateTime(2018, 04, 18), new DateTime(2018, 04, 18)))); // 0
System.Console.WriteLine((GetDiff(new DateTime(2018, 04, 22), new DateTime(2018, 04, 23)))); // 1
System.Console.WriteLine((GetDiff(new DateTime(2018, 04, 16), new DateTime(2018, 04, 22)))); // 0
System.Console.WriteLine((GetDiff(new DateTime(2018, 04, 18), new DateTime(2018, 05, 03)))); // 2
}
private static int GetDiff(DateTime date1, DateTime date2)
{
date1 = SetDayToMonday(date1);
date2 = SetDayToMonday(date2);
return (int)((date2 - date1).TotalDays / 7);
}
private static DateTime SetDayToMonday(DateTime date)
{
var weekDay = date.DayOfWeek;
if (weekDay == DayOfWeek.Sunday)
return date.AddDays(-6);
else
return date.AddDays(-((int)weekDay-1));
}
首先,将日期设置为本周的星期一。然后计算所有完整周数(= /7
天作为整数)。尽管很简单,但它可能会持续数周和数年。
这是我解决类似问题的实现,我没有进行彻底测试,但它似乎可以工作。
var dt1 = DateTime.Today.AddDays(-30);
var dt2 = DateTime.Today;
var noOfDays =(int) (dt2 - dt1).TotalDays;
int reminder;
var weeks = Math.DivRem(noOfDays, 7, out reminder);
weeks = reminder > 0 ? weeks + 1 : weeks;
它 returns 1 周 6 天或更短的间隔,这正是我所需要的。