在第 n 次出现空格后删除所有文本

delete all text after the nth occurance of a whitespace

我使用此代码段在文本中创建换行符。我怎样才能完全删除第n个空格后面的文字?

var str:String = ("This is just a test string").replace(/(( [^ ]+){2}) /, "\n");

问候

这可以使用正则表达式 (([^ ]* ){2}).* 并替换模式 </code>:</p> <p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false"> <div class="snippet-code"> <pre><code>function removeAfterNthSpace() { var nth = parseInt($("#num").val()); var regEx = new RegExp("(([^ ]* ){" + nth + "}).*", "g") var str = ("This is just a test string").replace(regEx, ""); console.log(str); } $('#num').change(removeAfterNthSpace); removeAfterNthSpace();

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="number" id="num" value="2" />

看到了working on regex101.