根据不同大小写字符串属性 in Java 8 从对象列表中删除重复项

Question

如何根据 Java 8 中的 "String" 属性从对象列表中删除重复项？我只能找到 Int 或 long 属性的代码，但当字符串大小写不同并获得唯一列表时无法找到字符串比较。

以下是我正在尝试实现的程序。

public class Diggu {

    class Employee{
        private int id;
        private String name;
        public Employee(int id, String name){
            this.id = id;
            this.name = name;
        }

        public int getId() {
            return id;
        }

        public void setId(int id) {
            this.id = id;
        }

        public String getName() {
            return name;
        }

        public void setName(String name) {
            this.name = name;
        }



    }

    public void ra(){
        List<Employee> employee = Arrays.asList(new Employee(1, "John"), new Employee(3, "JOHN"), new Employee(2, "BOB"));
        System.out.println(""+ employee.size());
        List<Employee> unique = employee.stream()
                                .collect(collectingAndThen(toCollection(() -> new TreeSet<>(comparing(Employee::getName))),
                                                           ArrayList::new));
        System.out.println(""+ unique.size());
    }
    public static void main(String[] args) {
        new Diggu().ra();
    }
}

结果：

run:
3
3
BUILD SUCCESSFUL (total time: 2 seconds)

应该是 3 和 2

Answer 1

John和JOHN是不同的字符串，不区分大小写Comparator

 Comparator.comparing(Employee::getName, String.CASE_INSENSITIVE_ORDER)

根据不同大小写字符串属性 in Java 8 从对象列表中删除重复项

Remove duplicates from a list of objects based on different case String property in Java 8

java

lambda

string-comparison

java-8

根据不同大小写字符串 属性 in Java 8 从对象列表中删除重复项

Remove duplicates from a list of objects based on different case String property in Java 8

java

lambda

string-comparison

java-8

根据不同大小写字符串属性 in Java 8 从对象列表中删除重复项