将数字从 mathematica csv 导出转换为 numpy 复杂数组
Convert numbers from mathematica csv export to numpy complex array
我已经将数据从 Mathematica 导出到一个 csv 文件。文件结构如下:
"x","y","Ex","Ey"
0.,0.,0.+0.*I,-3.0434726787506006*^-12+3.4234894344189825*^-12*I
0.,0.,0.+0.*I,-5.0434726787506006*^-12+10.4234894344189825*^-13*I
...
我正在使用 pandas 读取数据,但出现错误
import csv
import pandas as pd
import numpy as np
df=pd.read_csv('filename.csv')
df.columns=['x', 'y', 'Ex','Ey']
df['Ey'] = df['Ey'].str.replace('*^','E')
df['Ey'] = df['Ey'].str.replace('I','1j').apply(lambda x: np.complex(x))
编辑:我在代码的倒数第二行出现以下错误:
Traceback (most recent call last):
File "plot.py", line 6, in <module>
df['Ey'] = df['Ey'].str.replace('*^','E')
File "/home/.../.local/lib/python2.7/site-packages/pandas/core/strings.py", line 1579, in replace
flags=flags)
File "/home/.../.local/lib/python2.7/site-packages/pandas/core/strings.py", line 424, in str_replace
regex = re.compile(pat, flags=flags)
File "/usr/lib/python2.7/re.py", line 194, in compile
return _compile(pattern, flags)
File "/usr/lib/python2.7/re.py", line 251, in _compile
raise error, v # invalid expression
sre_constants.error: nothing to repeat
当我写的时候
df['Ey'] = df['Ey'].str.replace('*','E')
或
df['Ey'] = df['Ey'].str.replace('^','E')
我没有收到错误。好像只能给一个字符被替换?
为什么要搞乱 ascii 编码的浮点数?
这里是如何使用原始二进制文件在 python 和 Mathematica 之间交换复数数组。
在数学中:
cdat = RandomComplex[{0, 1 + I}, 5]
{0.0142816 + 0.0835513 I, 0.434109 + 0.977644 I,
0.579678 + 0.337286 I, 0.426271 + 0.166166 I, 0.363249 + 0.0867334 I}
f = OpenWrite["test", BinaryFormat -> True]
BinaryWrite[f, cdat, "Complex64"]
Close[f]
或:
Export["test", cdat, "Binary", "DataFormat" -> "Complex64"]
在python中:
import numpy as np
x=np.fromfile('test',np.complex64)
print x
[ 0.01428160+0.0835513j 0.43410850+0.97764391j 0.57967812+0.3372865j
0.42627081+0.16616575j 0.36324903+0.08673338j]
走另一条路:
y=np.array([[1+2j],[3+4j]],np.complex64)
y.tofile('test')
f = OpenRead["test", BinaryFormat -> True]
BinaryReadList[f, "Complex64"]
Close[f]
请注意,这比通过 csv 交换数据快 几个数量级。
我已经将数据从 Mathematica 导出到一个 csv 文件。文件结构如下:
"x","y","Ex","Ey"
0.,0.,0.+0.*I,-3.0434726787506006*^-12+3.4234894344189825*^-12*I
0.,0.,0.+0.*I,-5.0434726787506006*^-12+10.4234894344189825*^-13*I
...
我正在使用 pandas 读取数据,但出现错误
import csv
import pandas as pd
import numpy as np
df=pd.read_csv('filename.csv')
df.columns=['x', 'y', 'Ex','Ey']
df['Ey'] = df['Ey'].str.replace('*^','E')
df['Ey'] = df['Ey'].str.replace('I','1j').apply(lambda x: np.complex(x))
编辑:我在代码的倒数第二行出现以下错误:
Traceback (most recent call last):
File "plot.py", line 6, in <module>
df['Ey'] = df['Ey'].str.replace('*^','E')
File "/home/.../.local/lib/python2.7/site-packages/pandas/core/strings.py", line 1579, in replace
flags=flags)
File "/home/.../.local/lib/python2.7/site-packages/pandas/core/strings.py", line 424, in str_replace
regex = re.compile(pat, flags=flags)
File "/usr/lib/python2.7/re.py", line 194, in compile
return _compile(pattern, flags)
File "/usr/lib/python2.7/re.py", line 251, in _compile
raise error, v # invalid expression
sre_constants.error: nothing to repeat
当我写的时候
df['Ey'] = df['Ey'].str.replace('*','E')
或
df['Ey'] = df['Ey'].str.replace('^','E')
我没有收到错误。好像只能给一个字符被替换?
为什么要搞乱 ascii 编码的浮点数?
这里是如何使用原始二进制文件在 python 和 Mathematica 之间交换复数数组。
在数学中:
cdat = RandomComplex[{0, 1 + I}, 5]
{0.0142816 + 0.0835513 I, 0.434109 + 0.977644 I, 0.579678 + 0.337286 I, 0.426271 + 0.166166 I, 0.363249 + 0.0867334 I}
f = OpenWrite["test", BinaryFormat -> True]
BinaryWrite[f, cdat, "Complex64"]
Close[f]
或:
Export["test", cdat, "Binary", "DataFormat" -> "Complex64"]
在python中:
import numpy as np
x=np.fromfile('test',np.complex64)
print x
[ 0.01428160+0.0835513j 0.43410850+0.97764391j 0.57967812+0.3372865j 0.42627081+0.16616575j 0.36324903+0.08673338j]
走另一条路:
y=np.array([[1+2j],[3+4j]],np.complex64)
y.tofile('test')
f = OpenRead["test", BinaryFormat -> True]
BinaryReadList[f, "Complex64"]
Close[f]
请注意,这比通过 csv 交换数据快 几个数量级。