Python pathlib 如果目录不存在则创建目录

Question

如果我想指定一个路径来保存文件并创建该路径中不存在的目录，是否可以使用 pathlib 库在一行代码中完成此操作？

Answer 1

对，就是Path.mkdir:

pathlib.Path('/tmp/sub1/sub2').mkdir(parents=True, exist_ok=True)

来自 the docs:

If parents is true, any missing parents of this path are created as needed; they are created with the default permissions without taking mode into account (mimicking the POSIX mkdir -p command).

If parents is false (the default), a missing parent raises FileNotFoundError.

If exist_ok is false (the default), FileExistsError is raised if the target directory already exists.

If exist_ok is true, FileExistsError exceptions will be ignored (same behavior as the POSIX mkdir -p command), but only if the last path component is not an existing non-directory file.

Answer 2

这为路径已经存在的情况提供了额外的控制：

path = Path.cwd() / 'new' / 'hi' / 'there'
try:
    path.mkdir(parents=True, exist_ok=False)
except FileExistsError:
    print("Folder is already there")
else:
    print("Folder was created")

Answer 3

添加到 Wim 的回答中。如果您的路径末尾有一个您不想作为目录的文件。

即。 '/existing_dir/not_existing_dir/another_dir/a_file'

那你就用PurePath.parents。但好处是因为 Paths 继承了 Pure Paths 的属性，所以你可以简单地做

filepath = '/existing_dir/not_existing_dir/another_dir/a_file'
pathlib.Path(filepath).parents[0].mkdir(parents=True, exist_ok=True)

Python pathlib 如果目录不存在则创建目录

Python pathlib make directories if they don’t exist

python

pathlib