提示用户继续不工作，java

Question

我需要帮助。我想询问用户是否想再试一次，但我的代码似乎有问题，因为它不起作用。

public class TotoAzul
{
   public static void main(String[] args)
   {

      Scanner keyboard = new Scanner(System.in);

      int n1, n2, sum;
      String answer;
      do {

      System.out.println("Enter number 1: ");
      n1 = keyboard.nextInt();

      System.out.println("Enter number 2: ");
      n2 = keyboard.nextInt();

      sum = n1 + n2;

      System.out.println("Number 1\t" + "Number 2\t" + "Sum");
      System.out.println("__________________________________");
      System.out.println(n1 + "\t\t" + n2 + "\t\t" + sum);

      System.out.println("Enter yes to continue or any other key to end");
      answer = keyboard.nextLine();

      keyboard.nextLine();

      }
      while(answer.equalsIgnoreCase("YES"));



}

   }

当我运行它时，它会存储用户的答案，但程序不会重复。我该如何解决这个问题？

Answer 1

在 n2 = keyboard.nextInt(); 之后移动 keyboard.nextLine(); 以接受并忽略输入流中因调用 nextInt() 而留下的 悬空换行符 。

当我运行它存储用户的答案 - 尝试打印它存储在 answer 字段中的内容然后你会看到问题.

Answer 2

改变keyboard.nextLine();的位置。

keyboard.nextLine();
answer = keyboard.nextLine();

在您的代码中，答案是获取下一行（即 enter），当您获取 n2 的值并按回车键时，它就会出现。

您可以通过执行以下代码来测试您的代码

System.out.println("Enter yes to continue or any other key to end");
answer = keyboard.nextLine();
System.out.println("Answer : " + answer);
System.out.println(keyboard.nextLine());

Answer 3

Scanner keyboard = new Scanner(System.in);

      int n1, n2, sum;
      String answer = "Yes";

while (answer.equals("Yes"))
{
 System.out.println("Enter number 1: ");
      n1 = keyboard.nextInt();

      System.out.println("Enter number 2: ");
      n2 = keyboard.nextInt();

      sum = n1 + n2;

      System.out.println("Number 1\t" + "Number 2\t" + "Sum");
      System.out.println("__________________________________");
      System.out.println(n1 + "\t\t" + n2 + "\t\t" + sum);

      System.out.println("Enter yes to continue or any other key to end");
      answer = keyboard.nextLine();

      keyboard.nextLine();
}

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