How can I fix this error in python 3.4 tkinter "Index Error: list index out of range"

Question

我正在尝试将一些值和名称保存和加载为一个小项目，但我在加载部分遇到了一些问题我正在使用 PYTHON 3.4 和 tkinter 创建 4 个文本框，2 个用于名称，2 个用于值，2 个按钮用于保存和加载我放在这些文本框中的内容我可以在这些文本框中写任何东西，所以假设我输入

苹果 20

橙40

所以在我的前 2 个文本框中我有 2 个字符串和其他 2 个整数
所以我的代码是

import time
import serial
import sys
import os
import tkinter as tk
from tkinter import ttk
from tkinter import *
from tkinter import messagebox
from tkinter import filedialog
from tkinter.filedialog import askopenfilename
from tkinter.filedialog import asksaveasfilename
from tkinter.messagebox import showerror
try:
  import Tkinter              # Python 2
  import ttk
except ImportError:
  import tkinter as Tkinter   # Python 3
  import tkinter.ttk as ttk
mGui = Tk()
mGui.title("trying")
mGui.geometry('1250x650+10+10')
def mSave():
  filename = asksaveasfilename(defaultextension='.txt',filetypes = (('Text files', '*.txt'),    ('Python files', '*.py *.pyw'),('All files', '*.*')))
  if filename is None:
    return
  file = open (filename, mode = 'w')
  NameVal_1 = name1.get()
  NameVal_2 = name2.get()
  Vol_Val_1 = value1.get()
  Vol_Val_2 = value2.get()

  all =   (NameVal_1 + "," + (str(Vol_Val_1)) + ","
         + NameVal_2 + "," + (str(Vol_Val_2)))
  file.write(all)
  file.close()

def mLoad():
  filenamel = askopenfilename()
  if filenamel is None:
    return
  (NameVal_1, Vol_Val_1,
   NameVal_2, Vol_Val_2)   = (x.split(",")[3] for x in filenamel)

  name1.set(NameVal_1)
  name2.set(NameVal_2)
  value1.set(Vol_Val_1)
  value2.set(Vol_Val_2)
  file.close()

value1 = IntVar()
value2 = IntVar()
name1 = StringVar()
name2 = StringVar()

mButtonSave = Button(mGui, text = "Save Data", command = mSave, fg = 'Red').place(x=550,y=80)
mButtonLoad = Button(mGui, text = "Load Data", command = mLoad, fg = 'Red').place(x=550,y=110)

tText1 = Entry(mGui, textvariable = name1).place(x=10,y=80)
tText2 = Entry(mGui, textvariable = name2).place(x=10,y=100)
vText1 = Entry(mGui, textvariable = value1).place(x=200,y=80)
vText2 = Entry(mGui, textvariable = value2).place(x=200,y=100)

正在保存，我可以创建一个存档 .txt 来显示

apple,20,orange,40

但是当我尝试将这些值放入文本框时，我做不到 python 说

IndexError: list index out of range

我只是想，当四个文本框为空时，我按下加载按钮，将苹果放入文本框 1，将 20 放入文本框 2，将橙色放入文本框 3，将 40 放入文本框 4

我该怎么办？请帮忙

已编辑

这是最终代码，谢谢

import time
import serial
import sys
import os
import tkinter as tk
from tkinter import ttk
from tkinter import *
from tkinter import messagebox
from tkinter import filedialog
from tkinter.filedialog import askopenfilename
from tkinter.filedialog import asksaveasfilename
from tkinter.messagebox import showerror
try:
  import Tkinter              # Python 2
  import ttk
except ImportError:
  import tkinter as Tkinter   # Python 3
  import tkinter.ttk as ttk
mGui = Tk()
mGui.title("trying")
mGui.geometry('1250x650+10+10')
def mSave():
  filename = asksaveasfilename(defaultextension='.txt',filetypes = (('Text files', '*.txt'),    ('Python files', '*.py *.pyw'),('All files', '*.*')))
  if filename is None:
    return
  file = open (filename, mode = 'w')
  NameVal_1 = name1.get()
  NameVal_2 = name2.get()
  Vol_Val_1 = value1.get()
  Vol_Val_2 = value2.get()

  all =   (NameVal_1 + "," + (str(Vol_Val_1)) + ","
         + NameVal_2 + "," + (str(Vol_Val_2)))
  file.write(all)
  file.close()

def mLoad():
  filenamel = askopenfilename()
  if filenamel is None:
    return
  with open(filenamel, 'r') as f:
    x = f.readline()  # read the first line
    (NameVal_1, Vol_Val_1,  NameVal_2, Vol_Val_2) = x.split(",")  

  name1.set(NameVal_1)
  name2.set(NameVal_2)
  value1.set(Vol_Val_1)
  value2.set(Vol_Val_2)
  filename.close()

value1 = IntVar()
value2 = IntVar()
name1 = StringVar()
name2 = StringVar()

mButtonSave = Button(mGui, text = "Save Data", command = mSave, fg = 'Red').place(x=550,y=80)
mButtonLoad = Button(mGui, text = "Load Data", command = mLoad, fg = 'Red').place(x=550,y=110)

tText1 = Entry(mGui, textvariable = name1).place(x=10,y=80)
tText2 = Entry(mGui, textvariable = name2).place(x=10,y=100)
vText1 = Entry(mGui, textvariable = value1).place(x=200,y=80)
vText2 = Entry(mGui, textvariable = value2).place(x=200,y=100)

Answer 1

filenamel = askopenfilename() 只给你一个文件的路径。它实际上并不读取文件。因此，您需要打开它并阅读。此外，如果文件中只有一行，如示例所示，此 (x.split(",")[3] for x in filenamel) 将不起作用，因为它遍历文件路径中的字母，而不是文件中的行。您应该在 mLoad() 中执行以下操作：

# open the file for reading
with open(filenamel, 'r') as f:
    x = f.readline()  # read the first line   

# split it by ',' and assing to appropriate variables.
(NameVal_1, Vol_Val_1,  NameVal_2, Vol_Val_2) = x.split(",")

How can I fix this error in python 3.4 tkinter "Index Error: list index out of range"

How can I fix this error in python 3.4 tkinter "Index Error: list index out of range"

python

indexing

load

tkinter

save