修复 "Warning: Illegal string offset" --(但不丢失内容)

Fixing "Warning: Illegal string offset" -- (but without losing content)

I have searched for solution for this problem but none fix my problem. The answers suggest that I use isset to check the array before working on it. But I will explain how it doesnt do it for me later.

先决条件:
我有一个来自旅游网络服务的巨大 XML 文件,我将解析并转换为 PHP 数组,然后对其进行一些操作。 (主要是过滤游览)。

我的做法:
我正在使用 SimpleXML 加载 xml 并将其转换为 PHP 数组,如下所示:

$xml = file_get_contents(APPPATH."tour.xml", true);
$xmlString = htmlentity_to_xml($xml); //custom method to clean XML
$Str = simplexml_load_string($xmlString, 'SimpleXMLElement', LIBXML_NOCDATA);

//converting to array
$json = json_encode($Str);
$array = json_decode($json,TRUE);

然后我将此数组连同搜索参数(城市名称和日期)和数组本身一起发送到 fitlerTours($searchParams, $tourArray) 方法。

然后使用 foreach() 我将在每次游览中寻找 cityName 并在找到时举旗。

问题
当我为日期筛选游览(包含 cityName 的游览)时,我得到了这个。

Severity: Warning
Message: Illegal string offset 'year'
Filename: controllers/tourFilter.php
Line Number: 78

警告显示偏移 'month' 和 'day'。
这是我的 PHP 日期过滤器:(第 78 行是第 4 行)

if($flag == 1){
  if(!empty($fromDate)){
     foreach($tour['departureDates']['date'] AS $date){
        $dateDep = strtotime($date['year'] . "-" . (($date['month']) < 10 ? "0".$date['month'] : $date['month']) . "-" . (($date['day']) < 10 ? "0".$date['day'] : $date['day']));
        if(strtotime($fromDate) <= $dateDep && $dateDep <= strtotime($fromDate . "+".$range." days")){
          if($date['departureStatus'] != "SoldOut"){
             $dateFlag = 1;
          }
        }
     }
  }
  else{
     $dateFlag = 1;
  }
  $flag = 0;
}

if($dateFlag == 1){//Collect tours which contain the keyword & dates to $response array
   $responseArray[] = $tour;
   $dateFlag = false; //Reset Flag
}

这是 XML 的片段:

...
<departureDates>
        <date>
            <day>7</day>
            <month>1</month>
            <year>2016</year>
            <singlesPrice>12761</singlesPrice>
            <doublesPrice>9990</doublesPrice>
            <triplesPrice>0</triplesPrice>
            <quadsPrice>0</quadsPrice>
            <shipName/>
            <departureStatus>Available</departureStatus>
        </date>
        <date>
            <day>8</day>
            <month>1</month>
            <year>2016</year>
            <singlesPrice>12761</singlesPrice>
            <doublesPrice>9990</doublesPrice>
            <triplesPrice>0</triplesPrice>
            <quadsPrice>0</quadsPrice>
            <shipName/>
            <departureStatus>SoldOut</departureStatus>
        </date>
</departureDates>
...

现在,如果我使用我通过四处搜索找到的解决方案,检查数组是否由 isset() 正确设置,它不 return 正确并且第 78 行未执行并且数据是丢失。但是我需要数据。

只有我搜索的关键字会出现这种情况。
任何帮助表示赞赏。

错误表明 $date var 在某些时候被检测为字符串...

Characters within strings may be accessed and modified by specifying the zero-based offset of the desired character after the string using square array brackets, as in $str[42]. Think of a string as an array of characters for this purpose. See here

所以试试这个:

    if(is_array($date)){
        $dateDep = strtotime($date['year'] . "-" . (($date['month']) < 10 ? "0".$date['month'] : $date['month']) . "-" . (($date['day']) < 10 ? "0".$date['day'] : $date['day']));
        if(strtotime($fromDate) <= $dateDep && $dateDep <= strtotime($fromDate . "+".$range." days")){
          if($date['departureStatus'] != "SoldOut"){
             $dateFlag = 1;
          }
        }
    }
    else {
        //If this is not an array what is it then?
        var_dump($date);
    }