为什么我的插值在我的函数中不能正常工作？
Why is my interpolation not working properly in my function?
我有一个相当长的处理光谱的代码，并且在此过程中我需要对一些点进行插值。我以前把所有这些代码都一行一行地写出来，没有任何函数，而且一切正常，但现在我把它转换成两个大函数，这样我以后可以更容易地在其他模型上调用它。下面是我的代码（我在最后一行之后有更多代码绘制了一些东西，但这与我的问题无关，因为我已经用一堆 print 行测试了它并了解到我的问题出现在我在 process 函数中调用了 interpolation 函数。
import re
import numpy as np
import scipy.interpolate
# Required files and lists
filename = 'bpass_spectra.txt' # number of columns = 4
extinctionfile = 'ExtinctionLawPoints.txt' # R_V = 4.0
datalist = []
if filename == 'bpass_spectra.txt':
filetype = 4
else:
filetype = 1
if extinctionfile == 'ExtinctionLawPoints.txt':
R_V = 4.0
else:
R_V = 1.0 #to be determined
# Constants
h = 4.1357e-15 # Planck's constant [eV s]
c = float(3e8) # speed of light [m/s]
# Inputs
beta = 2.0 # power used in extinction law
R = 1.0 # star formation rate [Msun/yr]
z = 1.0 # redshift
M_gas = 1.0 # mass of gas
M_halo = 2e41 # mass of dark matter halo
# Read spectra file
f = open(filename, 'r')
rawlines = f.readlines()
met = re.findall('Z\s=\s(\d*\.\d+)', rawlines[0])
del rawlines[0]
for i in range(len(rawlines)):
newlist = rawlines[i].split(' ')
datalist.append(newlist)
# Read extinction curve data file
rawpoints = open(extinctionfile, 'r').readlines()
def interpolate(R_V, rawpoints, Elist, i):
pointslist = []
if R_V == 4.0:
for i in range(len(rawpoints)):
newlst = re.split('(?!\S)\s(?=\S)|(?!\S)\s+(?=\S)', rawpoints[i])
pointslist.append(newlst)
pointslist = pointslist[3:]
lambdalist = [float(item[0]) for item in pointslist]
k_abslist = [float(item[4]) for item in pointslist]
xvallist = [(c*h)/(lamb*1e-6) for lamb in lambdalist]
k_interp = scipy.interpolate.interp1d(xvallist, k_abslist)
return k_interp(Elist[i])
# Processing function
def process(interpolate, filetype, datalist, beta, R, z, M_gas, M_halo, met):
speclist = []
if filetype == 4:
metallicity = float(met[0])
Elist = [float(item[0]) for item in datalist]
speclambdalist = [h*c*1e9/E for E in Elist]
met1list = [float(item[1]) for item in datalist]
speclist.extend(met1list)
klist, Tlist = [None]*len(speclist), [None]*len(speclist)
if metallicity > 0.0052:
DGRlist = [50.0*np.exp(-2.21)*metallicity]*len(speclist) # dust to gas ratio
elif metallicity <= 0.0052:
DGRlist = [((50.0*metallicity)**3.15)*np.exp(-0.96)]*len(speclist)
for i in range(len(speclist)):
if Elist[i] <= 4.1357e-3: # frequencies <= 10^12 Hz
klist[i] = 0.1*(float(Elist[i])/(1000.0*h))**beta # extinction law [cm^2/g]
elif Elist[i] > 4.1357e-3: # frequencies > 10^12 Hz
klist[i] = interpolate(R_V, rawpoints, Elist, i) # interpolated function's value at Elist[i]
print "KLIST (INTERPOLATION) ELEMENTS 0 AND 1000:", klist[0], klist[1000]
return
print 行的输出是 KLIST (INTERPOLATION) ELEMENTS 0 AND 1000: 52167.31734159269 52167.31734159269。
当我 运行 我的旧代码没有函数时，我打印 klist[0] 和 klist[1000] 就像我在这里做的那样，并为每个得到不同的值。在这段新代码中，我从这一行中取回了两个相同的值。这不应该是这种情况，所以它不能在我的函数内正确插值（也许它没有在循环中的每个点上正确执行它？）。有没有人有任何见识？ post 我的整个代码和这里所有使用的文本文件（它们非常大）是不合理的，所以我不希望任何人 运行 它，而是检查我如何使用和调用我的函数。
编辑：下面是我的代码的原始版本，直到没有函数（有效）的插值点。
import re
import numpy as np
import scipy.interpolate
filename = 'bpass_spectra.txt'
extinctionfile = 'ExtinctionLawPoints.txt' # from R_V = 4.0
pointslist = []
datalist = []
speclist = []
# Constants
h = 4.1357e-15 # Planck's constant [eV s]
c = float(3e8) # speed of light [m/s]
# Read spectra file
f = open(filename, 'r')
rawspectra = f.readlines()
met = re.findall('Z\s=\s(\d*\.\d+)', rawspectra[0])
del rawspectra[0]
for i in range(len(rawspectra)):
newlist = rawspectra[i].split(' ')
datalist.append(newlist)
# Read extinction curve data file
rawpoints = open(extinctionfile, 'r').readlines()
for i in range(len(rawpoints)):
newlst = re.split('(?!\S)\s(?=\S)|(?!\S)\s+(?=\S)', rawpoints[i])
pointslist.append(newlst)
pointslist = pointslist[3:]
lambdalist = [float(item[0]) for item in pointslist]
k_abslist = [float(item[4]) for item in pointslist]
xvallist = [(c*h)/(lamb*1e-6) for lamb in lambdalist]
k_interp = scipy.interpolate.interp1d(xvallist, k_abslist)
# Create new lists
Elist = [float(item[0]) for item in datalist]
speclambdalist = [h*c*1e9/E for E in Elist]
z1list = [float(item[1]) for item in datalist]
speclist.extend(z1list)
met = met[0]
klist = [None]*len(speclist)
Loutlist = [None]*len(speclist)
Tlist = [None]*len(speclist)
# Define parameters
b = 2.0 # power used in extinction law (beta)
R = 1.0 # star formation ratw [Msun/yr]
z = 1.0 # redshift
Mgas = 1.0 # mass of gas
Mhalo = 2e41 # mass of dark matter halo
if float(met) > 0.0052:
DGRlist = [50.0*np.exp(-2.21)*float(met)]*len(speclist)
elif float(met) <= 0.0052:
DGRlist = [((50.0*float(met))**3.15)*np.exp(-0.96)]*len(speclist)
for i in range(len(speclist)):
if float(Elist[i]) <= 4.1357e-3: # frequencies <= 10^12 Hz
klist[i] = 0.1*(float(Elist[i])/(1000.0*h))**b # extinction law [cm^2/g]
elif float(Elist[i]) > 4.1357e-3: # frequencies > 10^12 Hz
klist[i] = k_interp(Elist[i]) # interpolated function's value at Elist[i]
print "KLIST (INTERPOLATION) ELEMENTS 0 AND 1000:", klist[0], klist[1000]
此 print 行的输出是 KLIST (INTERPOLATION) ELEMENTS 0 AND 1000 7779.275435560996 58253.589270674354。
您将 i 作为参数传递给 interpolate，然后还在 interpolate 的循环中使用 i。一旦 i 在 interpolate 的 for i in range(len(rawpoints)) 循环中使用，它将被设置为某个值：len(rawpoints)-1。 interpolate 函数将始终 return 相同的值 k_interp(Elist[i])，相当于 k_interp(Elist[len(rawpoints)-1])。您需要在循环中定义一个新变量（例如 for not_i in range(len(rawpoints))），或者为 Elist 参数使用不同的变量。考虑对 interpolate 的以下更改：
def interpolate(R_V, rawpoints, Elist, j):
pointslist = []
if R_V == 4.0:
for i in range(len(rawpoints)):
newlst = re.split('(?!\S)\s(?=\S)|(?!\S)\s+(?=\S)', rawpoints[i])
pointslist.append(newlst)
pointslist = pointslist[3:]
lambdalist = [float(item[0]) for item in pointslist]
k_abslist = [float(item[4]) for item in pointslist]
xvallist = [(c*h)/(lamb*1e-6) for lamb in lambdalist]
k_interp = scipy.interpolate.interp1d(xvallist, k_abslist)
return k_interp(Elist[j])
我有一个相当长的处理光谱的代码，并且在此过程中我需要对一些点进行插值。我以前把所有这些代码都一行一行地写出来，没有任何函数，而且一切正常，但现在我把它转换成两个大函数，这样我以后可以更容易地在其他模型上调用它。下面是我的代码（我在最后一行之后有更多代码绘制了一些东西，但这与我的问题无关，因为我已经用一堆 print 行测试了它并了解到我的问题出现在我在 process 函数中调用了 interpolation 函数。
import re
import numpy as np
import scipy.interpolate
# Required files and lists
filename = 'bpass_spectra.txt' # number of columns = 4
extinctionfile = 'ExtinctionLawPoints.txt' # R_V = 4.0
datalist = []
if filename == 'bpass_spectra.txt':
filetype = 4
else:
filetype = 1
if extinctionfile == 'ExtinctionLawPoints.txt':
R_V = 4.0
else:
R_V = 1.0 #to be determined
# Constants
h = 4.1357e-15 # Planck's constant [eV s]
c = float(3e8) # speed of light [m/s]
# Inputs
beta = 2.0 # power used in extinction law
R = 1.0 # star formation rate [Msun/yr]
z = 1.0 # redshift
M_gas = 1.0 # mass of gas
M_halo = 2e41 # mass of dark matter halo
# Read spectra file
f = open(filename, 'r')
rawlines = f.readlines()
met = re.findall('Z\s=\s(\d*\.\d+)', rawlines[0])
del rawlines[0]
for i in range(len(rawlines)):
newlist = rawlines[i].split(' ')
datalist.append(newlist)
# Read extinction curve data file
rawpoints = open(extinctionfile, 'r').readlines()
def interpolate(R_V, rawpoints, Elist, i):
pointslist = []
if R_V == 4.0:
for i in range(len(rawpoints)):
newlst = re.split('(?!\S)\s(?=\S)|(?!\S)\s+(?=\S)', rawpoints[i])
pointslist.append(newlst)
pointslist = pointslist[3:]
lambdalist = [float(item[0]) for item in pointslist]
k_abslist = [float(item[4]) for item in pointslist]
xvallist = [(c*h)/(lamb*1e-6) for lamb in lambdalist]
k_interp = scipy.interpolate.interp1d(xvallist, k_abslist)
return k_interp(Elist[i])
# Processing function
def process(interpolate, filetype, datalist, beta, R, z, M_gas, M_halo, met):
speclist = []
if filetype == 4:
metallicity = float(met[0])
Elist = [float(item[0]) for item in datalist]
speclambdalist = [h*c*1e9/E for E in Elist]
met1list = [float(item[1]) for item in datalist]
speclist.extend(met1list)
klist, Tlist = [None]*len(speclist), [None]*len(speclist)
if metallicity > 0.0052:
DGRlist = [50.0*np.exp(-2.21)*metallicity]*len(speclist) # dust to gas ratio
elif metallicity <= 0.0052:
DGRlist = [((50.0*metallicity)**3.15)*np.exp(-0.96)]*len(speclist)
for i in range(len(speclist)):
if Elist[i] <= 4.1357e-3: # frequencies <= 10^12 Hz
klist[i] = 0.1*(float(Elist[i])/(1000.0*h))**beta # extinction law [cm^2/g]
elif Elist[i] > 4.1357e-3: # frequencies > 10^12 Hz
klist[i] = interpolate(R_V, rawpoints, Elist, i) # interpolated function's value at Elist[i]
print "KLIST (INTERPOLATION) ELEMENTS 0 AND 1000:", klist[0], klist[1000]
return
print 行的输出是 KLIST (INTERPOLATION) ELEMENTS 0 AND 1000: 52167.31734159269 52167.31734159269。
当我 运行 我的旧代码没有函数时，我打印 klist[0] 和 klist[1000] 就像我在这里做的那样，并为每个得到不同的值。在这段新代码中，我从这一行中取回了两个相同的值。这不应该是这种情况，所以它不能在我的函数内正确插值（也许它没有在循环中的每个点上正确执行它？）。有没有人有任何见识？ post 我的整个代码和这里所有使用的文本文件（它们非常大）是不合理的，所以我不希望任何人 运行 它，而是检查我如何使用和调用我的函数。
编辑：下面是我的代码的原始版本，直到没有函数（有效）的插值点。
import re
import numpy as np
import scipy.interpolate
filename = 'bpass_spectra.txt'
extinctionfile = 'ExtinctionLawPoints.txt' # from R_V = 4.0
pointslist = []
datalist = []
speclist = []
# Constants
h = 4.1357e-15 # Planck's constant [eV s]
c = float(3e8) # speed of light [m/s]
# Read spectra file
f = open(filename, 'r')
rawspectra = f.readlines()
met = re.findall('Z\s=\s(\d*\.\d+)', rawspectra[0])
del rawspectra[0]
for i in range(len(rawspectra)):
newlist = rawspectra[i].split(' ')
datalist.append(newlist)
# Read extinction curve data file
rawpoints = open(extinctionfile, 'r').readlines()
for i in range(len(rawpoints)):
newlst = re.split('(?!\S)\s(?=\S)|(?!\S)\s+(?=\S)', rawpoints[i])
pointslist.append(newlst)
pointslist = pointslist[3:]
lambdalist = [float(item[0]) for item in pointslist]
k_abslist = [float(item[4]) for item in pointslist]
xvallist = [(c*h)/(lamb*1e-6) for lamb in lambdalist]
k_interp = scipy.interpolate.interp1d(xvallist, k_abslist)
# Create new lists
Elist = [float(item[0]) for item in datalist]
speclambdalist = [h*c*1e9/E for E in Elist]
z1list = [float(item[1]) for item in datalist]
speclist.extend(z1list)
met = met[0]
klist = [None]*len(speclist)
Loutlist = [None]*len(speclist)
Tlist = [None]*len(speclist)
# Define parameters
b = 2.0 # power used in extinction law (beta)
R = 1.0 # star formation ratw [Msun/yr]
z = 1.0 # redshift
Mgas = 1.0 # mass of gas
Mhalo = 2e41 # mass of dark matter halo
if float(met) > 0.0052:
DGRlist = [50.0*np.exp(-2.21)*float(met)]*len(speclist)
elif float(met) <= 0.0052:
DGRlist = [((50.0*float(met))**3.15)*np.exp(-0.96)]*len(speclist)
for i in range(len(speclist)):
if float(Elist[i]) <= 4.1357e-3: # frequencies <= 10^12 Hz
klist[i] = 0.1*(float(Elist[i])/(1000.0*h))**b # extinction law [cm^2/g]
elif float(Elist[i]) > 4.1357e-3: # frequencies > 10^12 Hz
klist[i] = k_interp(Elist[i]) # interpolated function's value at Elist[i]
print "KLIST (INTERPOLATION) ELEMENTS 0 AND 1000:", klist[0], klist[1000]
此 print 行的输出是 KLIST (INTERPOLATION) ELEMENTS 0 AND 1000 7779.275435560996 58253.589270674354。
您将 i 作为参数传递给 interpolate，然后还在 interpolate 的循环中使用 i。一旦 i 在 interpolate 的 for i in range(len(rawpoints)) 循环中使用，它将被设置为某个值：len(rawpoints)-1。 interpolate 函数将始终 return 相同的值 k_interp(Elist[i])，相当于 k_interp(Elist[len(rawpoints)-1])。您需要在循环中定义一个新变量（例如 for not_i in range(len(rawpoints))），或者为 Elist 参数使用不同的变量。考虑对 interpolate 的以下更改：
def interpolate(R_V, rawpoints, Elist, j):
pointslist = []
if R_V == 4.0:
for i in range(len(rawpoints)):
newlst = re.split('(?!\S)\s(?=\S)|(?!\S)\s+(?=\S)', rawpoints[i])
pointslist.append(newlst)
pointslist = pointslist[3:]
lambdalist = [float(item[0]) for item in pointslist]
k_abslist = [float(item[4]) for item in pointslist]
xvallist = [(c*h)/(lamb*1e-6) for lamb in lambdalist]
k_interp = scipy.interpolate.interp1d(xvallist, k_abslist)
return k_interp(Elist[j])