ValueError: Shape of passed values is (1, 6), indices imply (6, 6)

Question

我正在将一个列表从 flask 函数传递到另一个函数，并得到这个值错误。

发送端我的代码：

@app.route('/process', methods=['POST'])
def process():
    name = request.form['name']
    comment = request.form['comment']
    wickets = request.form['wickets']
    ga = request.form['ga']
    ppballs = request.form['ppballs']
    overs = request.form['overs']

    score = [name,comment,wickets,ga,ppballs,overs]
    results = []
    results = eval_score(score)
    print results

接收端：

def ml_model(data):
    col = pd.DataFrame(data,columns=['runs','balls', 'wickets', 'ground_average', 'pp_balls_left', 'total_overs'])
    predicted = predictor(col)

错误痕迹：

 ...
 line 1598, in dispatch_request
 return self.view_functions[rule.endpoint](**req.view_args)

 File "/Users/sbk/guestbook/guestbook.py", line 26, in process
 results = eval_score(score)

 File "/Users/sbk/guestbook/eval_score.py", line 6, in eval_score
 col = pd.DataFrame(data,columns=['runs','balls', 'wickets',  'ground_average', 'pp_balls_left', 'total_overs'])

 File "/Users/sbk/anaconda2/lib/python2.7/site-  packages/pandas/core/frame.py", line 385, in __init__
 copy=copy)

 File "/Users/sbk/anaconda2/lib/python2.7/site-packages/pandas/core/frame.py", line 533, in _init_ndarray
 return create_block_manager_from_blocks([values], [columns, index])

 File "/Users/sbk/anaconda2/lib/python2.7/site-packages/pandas/core/internals.py", line 4631, in  create_block_manager_from_blocks
 construction_error(tot_items, blocks[0].shape[1:], axes, e)

 File "/Users/sbk/anaconda2/lib/python2.7/site-packages/pandas/core/internals.py", line 4608, in construction_error
 Open an interactive python shell in this framepassed, implied))

请让我知道哪里出错了。

Answer 1

简单改变

col = pd.DataFrame(data, columns=['runs','balls', 'wickets', 'ground_average', 'pp_balls_left', 'total_overs'])

为

col = pd.DataFrame([data], columns=['runs','balls', 'wickets', 'ground_average', 'pp_balls_left', 'total_overs'])

您希望 [data] 和 pandas 了解它们是行。

简单说明：

a = [1, 2, 3]
>>> pd.DataFrame(a)
   0
0  1
1  2
2  3

>>> pd.DataFrame([a])
   0  1  2
0  1  2  3

Answer 2

我在从回归系数 (regressor.coeff_) 制作数据帧时遇到了类似的问题，括号给出了另一个要求二维输入的错误。如果出现此错误，请尝试在输入数组后附加 [0]，以便提取值。前任：数据[0]

Answer 3

我遇到了与消息类似的错误

Shape of passed values is (68, 1783), indices imply (68, 68) in dataframe

并且根据我的猜测，我输入了数据的 ndarray 转置并解决了问题

更改自

Features_Dataframe = pd.DataFrame(data=Features, columns=Feature_Labels)  # here Features ndarray is 68*1783

到

Features_Dataframe = pd.DataFrame(data=Features.transpose(), columns=Feature_Labels)  # Now Features array became 1783*68 i.e., 1783 rows and 68 columns

Answer 4

改变这个：

pd.DataFrame(regr.coef_, df_coeficientes.columns, 列=['Coeffecient'])

对此：

pd.DataFrame(regr.coef_[0], df_coeficientes.columns, 列=['Coeffecient'])

ValueError: Shape of passed values is (1, 6), indices imply (6, 6)

ValueError: Shape of passed values is (1, 6), indices imply (6, 6)

python

flask

pandas

valueerror