tensorflow 是否像 2D 卷积那样允许 LSTM 反卷积（convlstm2d）？

Question

我正在尝试扩充网络。对于卷积部分，我使用的是 keras 的 convlstm2d。是否有执行反卷积的过程（即 lstmdeconv2d ？）

Answer 1

有 Conv3D，查看此示例 used to predict the next frame

Answer 2

应该可以将任何模型与 TimeDistributed 包装器结合起来。因此，您可以创建一个反卷积模型，并使用 TimeDistributed 包装器将其应用于 LSTM 的输出（这是一个向量序列）。

一个例子。首先使用 Conv2DTranspose 层创建一个 deconv 网络。

from keras.models import Model
from keras.layers import LSTM,Conv2DTranspose, Input, Activation, Dense, Reshape, TimeDistributed

# Hyperparameters
layer_filters = [32, 64]

# Deconv Model 
# (adapted from https://github.com/keras-team/keras/blob/master/examples/mnist_denoising_autoencoder.py )

deconv_inputs = Input(shape=(lstm_dim,), name='deconv_input')
feature_map_shape = (None, 50, 50, 64) # deconvolve from [batch_size, 50,50,64] => [batch_size, 200,200,3]
x = Dense(feature_map_shape[1] * feature_map_shape[2] * feature_map_shape[3])(deconv_inputs)
x = Reshape((feature_map_shape[1], feature_map_shape[2],feature_map_shape[3]))(x)
for filters in layer_filters[::-1]:
   x = Conv2DTranspose(filters=16,kernel_size=3,strides=2,activation='relu',padding='same')(x)
x = Conv2DTranspose(filters=3,kernel_size=3, padding='same')(x) # last layer has 3 channels
deconv_output = Activation('sigmoid', name='deconv_output')(x)
deconv_model = Model(deconv_inputs, deconv_output, name='deconv_network')

然后，您可以使用 TimeDistributed 层将此反卷积模型应用于 LSTM 的输出。

# LSTM
lstm_input = Input(shape=(None,16), name='lstm_input') # => [batch_size, timesteps, input_dim]
lstm_outputs =  LSTM(units=64, return_sequences=True)(lstm_input) # => [batch_size, timesteps, output_dim]
predicted_images = TimeDistributed(deconv_model)(lstm_outputs)

model = Model(lstm_input , predicted_images , name='lstm_deconv')
model.summary()

tensorflow 是否像 2D 卷积那样允许 LSTM 反卷积（convlstm2d）？

Does tensorflow allow LSTM deconvolution ( convlstm2d) as it does for 2D convolution?

convolution

lstm

keras

tensorflow