popStackImmediate() 导致非法状态异常

Question

这是代码

    FragmentManager fm = getSupportFragmentManager();
    int count = fm.getBackStackEntryCount();
    for (int i = 0; i < count; ++i) {
        fm.popBackStackImmediate();
    }

这段代码在所有情况下都能正常工作。但是当从广播接收器调用时，我们得到非法状态异常。

分享 logcat

java.lang.RuntimeException: 
  at android.app.LoadedApk$ReceiverDispatcher$Args.run 
  (LoadedApk.java:894)
  at android.os.Handler.handleCallback (Handler.java:739)
  at android.os.Handler.dispatchMessage (Handler.java:95)
  at android.os.Looper.loop (Looper.java:148)
  at android.app.ActivityThread.main (ActivityThread.java:5484)
  at java.lang.reflect.Method.invoke (Native Method)
  at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run 
  (ZygoteInit.java:726)
  at com.android.internal.os.ZygoteInit.main (ZygoteInit.java:616)
Caused by: java.lang.IllegalStateException: 
  at android.support.v4.app.FragmentManagerImpl.checkStateLoss 
  (FragmentManager.java:1842)
  at android.support.v4.app.FragmentManagerImpl.popBackStackImmediate 
  (FragmentManager.java:775)
  at com.app.sample.BaseContentFragmentHolderActivity.startFragment 
  (BaseContentFragmentHolderActivity.java:58)
  at app.sample.SampleActivity.showDashboardFragment 
  (SampleActivity.java:732)
  at com.app.sample.SampleActivity.onMotionDetected 
  (SampleActivity.java:725)
  at com.app.sample.SampleActivity.onReceive 
  (SampleActivity.java:261)
  at android.app.LoadedApk$ReceiverDispatcher$Args.run 
  (LoadedApk.java:884)

对此有什么想法吗？

Answer 1

如果应用程序在后台，则会出现异常。实施逻辑以确保应用程序在执行这些代码时处于前台。

popStackImmediate() 导致非法状态异常

popStackImmediate() Causing illegal state exception

android

android-fragments

fragmentmanager