使用 boost::spirit 解析为向量<vector<double>>
Parse into a vector<vector<double>> with boost::spirit
我的目的是将逗号分隔的值列表解析为嵌套向量。这个列表是二维的。基本问题是:
是否可以用 boost::spirit 解析成向量的向量?
类似于 "Traction" 下的 table:
'
' RPM
0,5000,10000,15000,20000,25000
'
' Temp
'
-40.,0.,20.,40.
'
' Traction
200.,175.,170.,165.,160.,150.
200.,175.,170.,165.,160.,150.
165.,165.,160.,155.,145.,145.
160.,155.,150.,145.,145.,140.
'
下一步,我想读入 4 维数据,但现在我正在努力处理第二维数据。数据结构是这样的:
struct table {
std::vector<double> index;
std::vector<double> index2;
std::vector<std::vector<double> > base;
};
恕我直言,语法非常简单,如下所示:
comment %= qi::lexeme[ '\'' >> *(qi::standard::char_ - qi::eol)] >> qi::eol;
commentblock = comment >> *(comment);
doublevector = qi::double_ % ',' >> qi::eol ;
vectorblock = *doublevector;
start = commentblock >>
doublevector >>
commentblock >>
doublevector >>
commentblock >>
vectorblock >>
commentblock >>
qi::eoi
;
到目前为止,我在解析 index
和 index2
这两个向量时没有问题。但问题始于 base
。我认为关键部分是我定义 vectorblock
的地方:
vectorblock = *doublevector;
我已经尝试了该声明的几种变体。 this 问题中的 %=
运算符也没有任何改变。尽管属性传播可能是正确的方向。
如果我按照 boost 文档示例 "with style",结果是完全一样的:
vectorblock = doublevector % qi::eps;
使用 push_back()
的 List Redux 示例:
vectorblock = doublevector[phoenix::push_back(qi::_val, qi::_1)] % qi::eps;
引发大量编译错误,开始于:
error C2039: 'push_back' : is not a member of 'boost::spirit::unused_type'
更新: 问题出在 vectorblock
的声明处。我忘记了属性类型后面的()
。所以,定义应该是这样的:
qi::rule<Iterator, std::vector<std::vector<double> >(), Skipper> vectorblock;
(更新的)工作示例在这里:
#include <iostream>
#include <string>
#include <vector>
#define BOOST_SPIRIT_DEBUG
#include <boost/spirit/include/qi.hpp>
#include <boost/spirit/include/phoenix.hpp>
#include <boost/fusion/adapted.hpp>
struct table {
std::vector<double> index;
std::vector<double> index2;
std::vector<std::vector<double> > base;
};
BOOST_FUSION_ADAPT_STRUCT(
table,
(std::vector<double> , index)
(std::vector<double> , index2)
(std::vector<std::vector<double> >, base)
)
const std::string contents =
"'\n"
"' RPM\n"
"'\n"
"0,5010,10000,15000,20000,25000\n"
"'\n"
"' Temp\n"
"'\n"
"-40.,0.,20.,40.\n"
"'\n"
"' Traction\n"
"200.,175.,170.,165.,160.,150.\n"
"200.,175.,170.,165.,160.,150.\n"
"165.,165.,160.,155.,145.,145.\n"
"160.,155.,150.,145.,145.,140.\n"
"'\n"
;
int main()
{
namespace qi = boost::spirit::qi;
namespace phoenix = boost::phoenix;
typedef std::string::const_iterator Iterator;
typedef boost::spirit::ascii::blank_type Skipper;
qi::rule<Iterator, std::string(), Skipper> comment;
qi::rule<Iterator, Skipper> commentblock;
qi::rule<Iterator, std::vector<double>(), Skipper> doublevector;
qi::rule<Iterator, std::vector<std::vector<double> >, Skipper> vectorblock;
qi::rule<Iterator, table(), Skipper> start;
comment %= qi::lexeme[ '\'' >> *(qi::standard::char_ - qi::eol)] >> qi::eol;
commentblock = comment >> *(comment);
doublevector = qi::double_ % ',' >> qi::eol ;
vectorblock = *doublevector;
start = commentblock >>
doublevector >>
commentblock >>
doublevector >>
commentblock >>
vectorblock >>
commentblock >>
qi::eoi
;
BOOST_SPIRIT_DEBUG_NODES((start)(doublevector)(vectorblock));
table tref;
bool rv = qi::phrase_parse(
std::begin(contents), std::end(contents),
start,
boost::spirit::ascii::blank,
tref
);
std::cout << "parse " << ((char *)rv?"success":"failure") << ".\n";
for (auto i : tref.index)
std::cout << i << ", ";
std::cout << "\n";
for (auto i : tref.index2)
std::cout << i << ", ";
std::cout << "\nBase:\n";
for (auto & i : tref.base)
{
for(auto & j : i)
std::cout << j << ", ";
std::cout << "\n";
}
std::cout << std::endl;
}
答案是肯定的。
解析成 vector<vector<double> >
实际上很简单
规则定义需要一个函数类型,而不是直接的类型。这个简单解释一下here. A more thorough explanation is probably found in the documentation of boost::phoenix
上面程序的输出现在很好地显示了解析后的值:
parse success.
0, 5011, 10000, 15000, 20000, 25000,
-40, 0, 20, 40,
Base:
200, 175, 170, 165, 160, 150,
200, 175, 170, 165, 160, 150,
165, 165, 160, 155, 145, 145,
160, 155, 150, 145, 145, 140,
我的目的是将逗号分隔的值列表解析为嵌套向量。这个列表是二维的。基本问题是:
是否可以用 boost::spirit 解析成向量的向量?
类似于 "Traction" 下的 table:
'
' RPM
0,5000,10000,15000,20000,25000
'
' Temp
'
-40.,0.,20.,40.
'
' Traction
200.,175.,170.,165.,160.,150.
200.,175.,170.,165.,160.,150.
165.,165.,160.,155.,145.,145.
160.,155.,150.,145.,145.,140.
'
下一步,我想读入 4 维数据,但现在我正在努力处理第二维数据。数据结构是这样的:
struct table {
std::vector<double> index;
std::vector<double> index2;
std::vector<std::vector<double> > base;
};
恕我直言,语法非常简单,如下所示:
comment %= qi::lexeme[ '\'' >> *(qi::standard::char_ - qi::eol)] >> qi::eol;
commentblock = comment >> *(comment);
doublevector = qi::double_ % ',' >> qi::eol ;
vectorblock = *doublevector;
start = commentblock >>
doublevector >>
commentblock >>
doublevector >>
commentblock >>
vectorblock >>
commentblock >>
qi::eoi
;
到目前为止,我在解析 index
和 index2
这两个向量时没有问题。但问题始于 base
。我认为关键部分是我定义 vectorblock
的地方:
vectorblock = *doublevector;
我已经尝试了该声明的几种变体。 this 问题中的 %=
运算符也没有任何改变。尽管属性传播可能是正确的方向。
如果我按照 boost 文档示例 "with style",结果是完全一样的:
vectorblock = doublevector % qi::eps;
使用 push_back()
的 List Redux 示例:
vectorblock = doublevector[phoenix::push_back(qi::_val, qi::_1)] % qi::eps;
引发大量编译错误,开始于:
error C2039: 'push_back' : is not a member of 'boost::spirit::unused_type'
更新: 问题出在 vectorblock
的声明处。我忘记了属性类型后面的()
。所以,定义应该是这样的:
qi::rule<Iterator, std::vector<std::vector<double> >(), Skipper> vectorblock;
(更新的)工作示例在这里:
#include <iostream>
#include <string>
#include <vector>
#define BOOST_SPIRIT_DEBUG
#include <boost/spirit/include/qi.hpp>
#include <boost/spirit/include/phoenix.hpp>
#include <boost/fusion/adapted.hpp>
struct table {
std::vector<double> index;
std::vector<double> index2;
std::vector<std::vector<double> > base;
};
BOOST_FUSION_ADAPT_STRUCT(
table,
(std::vector<double> , index)
(std::vector<double> , index2)
(std::vector<std::vector<double> >, base)
)
const std::string contents =
"'\n"
"' RPM\n"
"'\n"
"0,5010,10000,15000,20000,25000\n"
"'\n"
"' Temp\n"
"'\n"
"-40.,0.,20.,40.\n"
"'\n"
"' Traction\n"
"200.,175.,170.,165.,160.,150.\n"
"200.,175.,170.,165.,160.,150.\n"
"165.,165.,160.,155.,145.,145.\n"
"160.,155.,150.,145.,145.,140.\n"
"'\n"
;
int main()
{
namespace qi = boost::spirit::qi;
namespace phoenix = boost::phoenix;
typedef std::string::const_iterator Iterator;
typedef boost::spirit::ascii::blank_type Skipper;
qi::rule<Iterator, std::string(), Skipper> comment;
qi::rule<Iterator, Skipper> commentblock;
qi::rule<Iterator, std::vector<double>(), Skipper> doublevector;
qi::rule<Iterator, std::vector<std::vector<double> >, Skipper> vectorblock;
qi::rule<Iterator, table(), Skipper> start;
comment %= qi::lexeme[ '\'' >> *(qi::standard::char_ - qi::eol)] >> qi::eol;
commentblock = comment >> *(comment);
doublevector = qi::double_ % ',' >> qi::eol ;
vectorblock = *doublevector;
start = commentblock >>
doublevector >>
commentblock >>
doublevector >>
commentblock >>
vectorblock >>
commentblock >>
qi::eoi
;
BOOST_SPIRIT_DEBUG_NODES((start)(doublevector)(vectorblock));
table tref;
bool rv = qi::phrase_parse(
std::begin(contents), std::end(contents),
start,
boost::spirit::ascii::blank,
tref
);
std::cout << "parse " << ((char *)rv?"success":"failure") << ".\n";
for (auto i : tref.index)
std::cout << i << ", ";
std::cout << "\n";
for (auto i : tref.index2)
std::cout << i << ", ";
std::cout << "\nBase:\n";
for (auto & i : tref.base)
{
for(auto & j : i)
std::cout << j << ", ";
std::cout << "\n";
}
std::cout << std::endl;
}
答案是肯定的。
解析成 vector<vector<double> >
规则定义需要一个函数类型,而不是直接的类型。这个简单解释一下here. A more thorough explanation is probably found in the documentation of boost::phoenix
上面程序的输出现在很好地显示了解析后的值:
parse success.
0, 5011, 10000, 15000, 20000, 25000,
-40, 0, 20, 40,
Base:
200, 175, 170, 165, 160, 150,
200, 175, 170, 165, 160, 150,
165, 165, 160, 155, 145, 145,
160, 155, 150, 145, 145, 140,