连接按列分组的值

Concatenate values that are grouped by a column

我有以下 table:

Code    Ref     Value
A1      Car     A
A1      Car     -
A1      Car     B
B2      Truck   CC
B2      Truck   D
B2      Truck   -
C3      Van     E
C3      Van     F
C3      Van     -
C3      Van     G

我要实现的目标是将所有值组合在一起的串联字符串,如下所示:

Code   Ref    Value
A1     Car    A-B
B2     Truck  CCD-
C3     Van    EF-G

我偏离了示例 here,但一无所获。这是我想出的:

SELECT [Table].[Code]
, [Table].[Ref]
, STUFF((SELECT DISTINCT [Value]
  FROM [Table2]
  FOR XML PATH ('')),1, 1,'') AS Values
FROM [Table]
LEFT JOIN [Table2] ON
[Table2].[Code] = [Table].[Code]

我哪里错了?有没有更有效的方法来做到这一点?

您没有任何 link 对 [Table] 的内部和外部引用,并且您还需要使外部引用不同。最后,您需要在子查询中没有列名,或者需要 [text()]

SELECT  [Code]
        ,[Ref]
        ,STUFF((SELECT DISTINCT [Value] AS [text()]
                FROM [Table] AS T2
                WHERE T1.Code = T2.Code -- LINK HERE
                AND T2.Ref = T2.Ref     -- AND HERE
                FOR XML PATH ('')
                ),1, 1,'') AS [Values]
FROM    [Table] AS T1
GROUP BY T1.Code, T1.Ref; -- GROUP BY HERE

顺便说一句,您不需要使用 STUFF,因为您没有定界符,STUFF 通常用于从字符串的开头删除所选的定界符。因此,当您有一个像 ,value1,value2,value3 这样的字符串时,STUFF(string, 1, 1, '') 会将第一个字符替换为 '',从而使您得到 value1,value2,value3.

你还应该使用 value xquery 方法来确保你不会被特殊字符绊倒,如果你不这样做,你可以尝试连接 ">>""<<" 你不会像您想要的那样以 ">><<" 结尾,您会得到 "&gt;&gt;&lt;&lt;",因此更好的查询是:

SELECT  t1.Code,
        t1.Ref,
        [Values] = (SELECT  DISTINCT [text()] = [Value]
                    FROM    [Table] AS t2
                    WHERE   T1.Code = T2.Code
                    AND     T2.Ref = T2.Ref
                    FOR XML PATH (''), TYPE
                ).value('.', 'NVARCHAR(MAX)')
FROM    [Table] AS T1
GROUP BY t1.Code, t1.Ref;

附录

根据对问题的最新编辑,您的 Value 列似乎来自另一个 table,link 编辑到第一个 table Code。如果有的话,这会使您的查询更简单。您不需要 JOIN,但您仍然需要确保有一个表达式 link 从外部 table 到内部 table 您的子查询。我假设行在第一个 table 中是唯一的,因此您可能不需要分组依据:

SELECT  t1.Code,
        t1.Ref,
        [Values] = (SELECT  DISTINCT [text()] = t2.[Value]
                    FROM    [Table2] AS t2
                    WHERE   T1.Code = T2.Code
                    FOR XML PATH (''), TYPE
                ).value('.', 'NVARCHAR(MAX)')
FROM    [Table] AS T1;

工作示例

CREATE TABLE #Table1 (Code CHAR(2), Ref VARCHAR(10));
INSERT #Table1 VALUES ('A1', 'Car'), ('B2', 'Truck'), ('C3', 'Van');

CREATE TABLE #Table2 (Code CHAR(2), Value VARCHAR(2));
INSERT #Table2
VALUES ('A1', 'A'), ('A1', '-'), ('A1', 'B'),
        ('B2', 'CC'), ('B2', 'D'), ('B2', '-'),
        ('C3', 'F'), ('C3', '-'), ('C3', 'G');

SELECT  t1.Code,
        t1.Ref,
        [Values] = (SELECT  DISTINCT [text()] = t2.[Value]
                    FROM    #Table2 AS t2
                    WHERE   T1.Code = T2.Code
                    FOR XML PATH (''), TYPE
                ).value('.', 'NVARCHAR(MAX)')
FROM    #Table1 AS T1;