将一个对象的所有QT信号动态映射到一个插槽
Dynamic mapping of all QT signals of one object to one slot
我想将一个QObject的所有信号都连接到某个插槽。
插槽看起来像这样:
void SignalIntercepter::signalFired()
{
std::cout << "Signal is fired!" << std::endl;
}
以下代码是 QObject 将传递到的位置:
void SignalIntercepter::handleObject(QObject* object)
{
const QMetaObject *me = object->metaObject();
int methodCount = me->methodCount();
for(int i = 0; i < methodCount; i++)
{
QMetaMethod method = me->method(i);
if(method.methodType() == QMetaMethod::Signal)
{
// How do I connect this signal to the slot?
// QObject::connect(object, ..., ..., ...);
}
}
}
看看
const char * QMetaMethod::signature() const
那么你应该可以像
一样使用它
QObject::connect(object, method->signature(), this, SLOT(signalFired()));
您可能需要在 method->signature()
调用之前添加 "2"
因为 SIGNAL(a)
makro 已定义 SIGNAL(a) "2"#a
如前所述 Is it possible to see definition of Q_SIGNALS, Q_SLOT, SLOT(), SIGNAL() macros? (Qt)
我想将一个QObject的所有信号都连接到某个插槽。
插槽看起来像这样:
void SignalIntercepter::signalFired()
{
std::cout << "Signal is fired!" << std::endl;
}
以下代码是 QObject 将传递到的位置:
void SignalIntercepter::handleObject(QObject* object)
{
const QMetaObject *me = object->metaObject();
int methodCount = me->methodCount();
for(int i = 0; i < methodCount; i++)
{
QMetaMethod method = me->method(i);
if(method.methodType() == QMetaMethod::Signal)
{
// How do I connect this signal to the slot?
// QObject::connect(object, ..., ..., ...);
}
}
}
看看
const char * QMetaMethod::signature() const
那么你应该可以像
一样使用它QObject::connect(object, method->signature(), this, SLOT(signalFired()));
您可能需要在 method->signature()
调用之前添加 "2"
因为 SIGNAL(a)
makro 已定义 SIGNAL(a) "2"#a
如前所述 Is it possible to see definition of Q_SIGNALS, Q_SLOT, SLOT(), SIGNAL() macros? (Qt)